2-27 Potential Energy, Potential, and Work
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Transcript 2-27 Potential Energy, Potential, and Work
Today 2/27
Read Ch 19.1 and 19.4 Skip 2-3 for now
Electric Potential Energy, PEE
Electric Potential, V
Electric Potential Difference, V
(watch out foe +/- signs!!!)
HW:
“Electric Potential Energy”
Due Monday 3/3
Problem:
Two identical point charges of 0.01g are placed 1m
apart. The right-hand charge is released. Find its
velocity when it is 10cm farther away.
v=0
v=?
Two opposite point charges of 0.01g are placed 1m
apart. The right-hand charge is released. Find its
velocity when it is 10cm closer.
v=?
v=0
Problem:
Two identical point charges of mass of 0.01g are placed
1m apart. The right-hand charge is released. Find its
velocity when it is 10cm farther away.
E Field and Force are not the same
everywhere so Fnet = ma requiresv calculus.
=0 v=?
Also need a system to handle direction.
Two opposite point charges of 0.01g are placed 1m
apart. The right-hand charge is released. Find its
velocity when it is 10cm closer.
v=?
v=0
Energy buckets are the way!
Problem:
Two identical point charges og mass .01g are placed 1m
apart. The right-hand charge is released. Find its
velocity when it is 10cm farther away.
A
Initial PE at A?
Initial KE at A?
B
v=0 v=?
0
PEE KE
PEE KE
PEA,B = - KEA,B
Final PE at B? (More or less than before?) Subscripts tell us
from A to B
Final KE at B? Equals the PE lost!
“Potential Energy Difference”
and “Potential Difference”
Potential Energy Difference PEA,B is the
change in PE the particular charge feels when it
is moved from one location to another.
Potential Difference VA,B is the change in PE a
positive 1C charge would feel if it were moved
from one location to another.
VA,B = +108 Volts,
and q = +1C
PEA,B = +100J
VA,B = -108 Volts,
and q = +1C
PEA,B = -100J
Which way does the E Field point?
PEA,B =
+100J, and q =
+1C What is
VA,B?
Remember:
From A to B!!!
VA,B = 108 Volts
Higher
Potential
E field
A
Higher
Potential
B
PEA,B =
E field
+100J, and q =
VA,B = -108 Volts
-1C What is
VA,B
? “downhill” with respect to potential difference
E Fields
point
What about Work, WA,B?
PEA,B =
+100J, and q =
+1C What is
VA,B?
Remember:
From A to B!!!
VA,B = 108 Volts
+Work
Higher
Potential
E field
A
Higher
Potential
B
+Work
PEA,B =
E field
+100J, and q =
VA,B = -108 Volts
-1C What is
VA,B
? “downhill” with respect to potential difference
E Fields
point