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Today5/2
Questions?
E-Fields and Potential Difference
(review)
E = kQs /r2
Many Charge Example
+qo
-2qo
+4qo
-3qo
What is the force on +4qo? (direction also)
Find the field at +4qo due to the “other”
charges. These are the “source” charges.
ro
E+q = kQs/r2 = k(qo)/(ro)2 = Eo
Direction?
Away from + so right
E-2q = kQs/r2 = k(2qo)/(2ro)2 = k2qo/2(ro)2= k(qo)/(ro)2 = Eo
E-3q = kQs/r2 = k(3qo)/(ro)2 = 3kqo/(ro)2 = 3Eo
E = kQs /r2
Many Charge Example
+qo
+4qo
What is the force on +4qo? (direction also)
E+q = Eo
E-2q = Eo
E-3q = 3Eo
ro Now add E-Field vectors
-2qo
-3qo
Ey = E-2q,y + E-3q,y
Ey = Eosin45 + 3Eo
Ex = E+q,x + E-2q,x
Ex = Eo - Eosin45
Ex = 0.29Eo
= tan-1(0.29/3.7) = 4.5°
Ey = 3.7Eo
Fon +4q = (4qo)3.71Eo = 14.84qoEo
Etotal = 3.72 + 0.292 Eo = 3.71Eo Fon +4q = 14.84kqo2/ro2
same direction as Etotal
What direction would the
force point on a small positive
charge at 1,2,3?
Compare the size of the force
exerted on a small charge at
a. 1 and 2 1 larger
b. 2 and 3 3 larger
The test charge is doubled
when at 2
a. how does the force
change? 2x
b. how does the electric
field change? Stays
the
same
“Potential Energy Difference”
and “Potential Difference”
Potential Energy Difference PEA,B is the
change in PE the particular charge feels when it
is moved from one location to another.
Potential Difference VA,B is the change in PE a
positive 1C charge would feel if it were moved
from one location to another.
VA,B = +108 Volts,
and q = +1C
PEA,B = +100J
VA,B = -108 Volts,
and q = +1C
PEA,B = -100J
Which way does the E Field point?
PEA,B =
+100J, and q =
+1C What is
VA,B?
Remember:
From A to B!!!
VA,B = 108 Volts
Higher
Potential
E field
A
Higher
Potential
B
PEA,B =
E field
+100J, and q =
VA,B = -108 Volts
-1C What is
VA,B
? “downhill” with respect to potential difference
E Fields
point
At which location is the
potential highest?
At 2
downhill to 1 and 3
At which location is the
potential lowest?
At 3
uphill to 1 and 2
Energy stored
kQ
V
r
PE qV
V 0
How much energy is stored in the assembly of
charges? All are +1 x 10-3C and 1g (1 x 10-3kg).
Energy stored is the same as
3m
the work required to
assemble the charges.
4m
5m
Move them all very far away,
bring them in one at a time,
and total up the work done.
Enet = 0
How big is E?
E
2 0
(+)
E
2 0
E net
Enet = 0
(-)
0
WAB = qED
What is the
change in
potential
energy in
going from
A to B?
PEAB = qED
PEAB = qVAB
VAB = EDAB
WAB = qED
FHq
B
FE = qE
A
Only applies when the
field is uniform over the
distance. VAB‘s sign
depends on the direction
of E. In this case it’s
positive.