Rating of Covalent Bonds
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Transcript Rating of Covalent Bonds
Polar Molecular
Compounds
SWBAT: Identify Polar and
Nonpolar Molecules
Periodic Table Trends
Atomic Radii
Half
the distance
between the nuclei
of two adjacent
atoms
Electronegativity
Ability
of an atom
to attract electrons
when bonded with
another atom
Atomic Radii Trend
Atomic Radii Trend
Electronegativity Trend
Electronegativity
is highest within the
nonmetals with Fluorine having the
highest. Why are noble gases excluded?
Electronegativity Trend
A. Three Types of Bonds:
non-polar, polar, ionic
Use Electronegativity (EN) values to
determine type of bond
EN value:
H = 2.1 C = 2.5 N = 3.0 O = 3.5 F = 4.0
P = 2.1 S = 2.5 Cl = 3.0
Br = 2.8
I = 2.5
Every element has a specific EN value
We will focus on the elements of organic
chemistry C,H,N,O,P,S and Halogens
Do not need to memorize
Electronegativity Difference
and type of bond
Rating of Covalent Bonds:
Example
1: What type of bond is H-Cl?
EN: H = 2.1 Cl: 3.0
Subtract ENs from each other, larger – smaller
3.0 – 2.1 = 0.9 compare to rating
Redraw compound with partial charges: δ+ & δδ+ δ-
H – Cl
Dipole Moment
*Polar Covalent
0 - .4 = nonpolar
.5 – 1.7 = polar
1.8 and greater = ionic
Rating of Covalent Bonds:
Example
1: What type of bond is H-Br?
EN: H = 2.1 Br: 2.8
Subtract ENs from each other, larger – smaller
2.8 – 2.1 = 0.7 compare to rating
Redraw compound with partial charges: δ+ & δδ+ δ-
H – Br
Dipole Moment
*Polar Covalent
0 - .4 = nonpolar
.5 – 1.7 = polar
1.8 and greater = ionic
Rating of Covalent Bonds:
Example
2: What type of bond is C-H?
EN: H = 2.1 C: 2.5
Subtract ENs from each other, larger – smaller
2.5 – 2.1 = 0.4 compare to rating
Less than 0.5 = no partial charges, no dipole arrow
C–H
0 - .4 = nonpolar
.5 – 1.7 = polar
1.8 and greater = ionic
*Nonpolar Covalent
Tips
Bonds
between different elements always
have some kind of dipole moment
regardless of polarity rating
Draw the dipole arrow of Br – Pd (use just
their position in the PT)
Br – Pd
Bonds between same elements never
have a dipole moment regardless of
individual EN
No
dipole between F – F or H – H
Practice Problems
Using
electronegativity difference, classify
each bond as ionic, polar covalent, or
nonpolar covalent.
K
Show the partial charge for any polar
covalent bonds.
– F EN values: K = 0.8 & F = 4.0
O – O EN values: O = 3.5
I – Cl EN values: I = 2.5, & Cl = 3.0
Practice Problems
Using
electronegativity difference, classify
each bond as ionic, polar covalent, or
nonpolar covalent.
Show the partial charge for any polar
covalent bonds.
K
– F EN values: K = 0.8 & F = 4.0
O
I
4.0 - 0.8 = 3.2 - ionic bond
– O EN values: O = 3.5
3.5 - 3.5 = 0 - nonpolar covalent bond
– Cl EN values: I = 2.5 & Cl = 3.0
3.0 - 2.5 = 0.5 - polar covalent bond
δ+
δ-
I – Cl
Practice Problems
The
bonds between the following pairs of
elements are covalent. Arrange them
according to polarity, listing the most
polar first.
a. H – Cl
b. H – C
c. H – F
d. H – O
e. H – H
f. S – Cl
Homework Problems
4.50
Describe the end in EN going down a group.
4.52 Approximately what EN difference would
you expect for a polar covalent bond?
4.54 Predict whether each of the following bonds
is ionic, polar covalent or nonpolar covalent:
A. Si-O
B. K-Cl
C. S-F
D. P-Br
E. Li-O
4.56
F. N-P
For each of the following bonds, indicate the
positive end with δ+ and the negative end with
δ-. Write an arrow to show the dipole for each.
A. Si-Br
B. Se-F
C. Br-F
D. N-H
E. N-P