Transcript (A) Number of bodies

The Official Police Procedure
for Investigating
Murders
If 1 Body is found then you must seal off surrounding
squares to avoid contaminating the crime scene.
Special police tape is used!
Each piece of tape is equal to the length of 1 square.
1 Body
4 Squares
8 Pieces of tape
Another example of how to seal a crime scene….
1 Body
6 Squares
12 Pieces of tape
The reason for the 2 extra squares is that they
contained other vital evidence to the crime.
When you investigate a murder involving 1 body,
you have to seal off the 4 squares surrounding it.
The reason for this is so that investigators can
walk around the perimeter. Other squares can
be added to these 4 squares in any direction if
they contain vital forensic evidence!
Notice the
cross in the
middle.
This is
where the
body is!
How many…
• Bodies?
• Squares?
• Pieces of tape?
Solution
1 Body
6 Squares
12 Pieces of tape
How many…
• Bodies?
• Squares?
• Pieces of tape?
Solution
2 Bodies
11 Squares
20 Pieces of tape
How many…
• Bodies?
• Squares?
• Pieces of tape?
Solution
2 Bodies
6 Squares
10 Pieces of tape
How many…
• Bodies?
• Squares?
• Pieces of tape?
Solution
1 Body
13 Squares
26 Pieces of tape
To complete your initial crime scene investigator
training, you have to show that you fully understand the
procedure for dealing with a murder.
Tasks
Investigate different situations with 1 body…..
• How many squares will you seal off?
• How much police tape will your require?
• Can you find a rule (using words/algebra) linking the
numbers of squares to the length of police tape?
For those of you wanting to become officers, you
should also complete the following….
• Investigate for 2, 3, 4,….n number of bodies
• Investigate a crime scene without a body
Solution
Let
N = number of bodies
A = Area of crime scene
T = Tape used
Number of bodies
(N)
0
Perimeter
(T)
2A + 2
1
2A
2
2A – 2
3
2A – 4
N
2A – 2N + 2
= 2(A – N + 1)
Solution
Let
N = number of bodies
A = Area of crime scene
T = Tape used
Number of bodies
(N)
0
Area of crime
scene
(A)
T/2 – 1
1
T/2
2
T/2 + 1
3
T/2 + 2
N
T/2 + (N – 1)