Transcript Document

Warm Up Day 60(30)
v1
A lab cart of mass 500g initially at
a constant velocity of 0.50 m/s is
subjected to a force of 30 N for
0.050 sec. The force is directed
opposite to its velocity. What is
the final velocity of the cart?
Solution
V=v0+at
F=ma
A=F/m= - 30/0.5= - 60 m/s2
V=0.5 - 60(.05) = -2.5 m/s
Or delta mv=Fdelta t = 1.5 kg m/s
-1.5/.5 = - 3m/s
0.5 - 3.0= -2.5 m/s