Transcript Slide 1

Electric Field
Questions from
2006 and 2007
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The oil drop is stationary. What
is its charge?
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• Force down is its weight.
• If it is stationary then there must be an
electric force up that is equal and
opposite to the weight.
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We therefore know that the charge
must be negative (so it is attracted to
the upper plate!)
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Magnitude of force down = mg
Magnitude of force up = QE
But E = V/d
So magnitude of force up = QV/d
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I mg I = I QV/d I
So Q = - mgd/V
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In a Rutherford scattering experiment, an α particle approaches a
gold nucleus along the straight line joining their centres and comes
momentarily to rest at point P, as shown in the diagram. The α
particle then returns along its previous path.
(a) The distance from the centre of the gold nucleus, to the point P is 30
fm.
For the point P
(i)
show that the strength of the electric field associated with the
charge of the nucleus is 1.3 × 1020 V m-1
(ii)
calculate the magnitude of the force acting on the α particle
(iii) calculate the electric potential due to the charge of the nucleus
(5 marks)
,
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(b) (i) State the energy changes of the α
particle during its interaction with the
gold nucleus.
(ii) Calculate the initial kinetic energy, in
J, of the α particle, explaining your
reasoning.
(4 marks)
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Garfield Graphics included with kind permission from PAWS Inc. All Rights Reserved.
• Two protons are 1.0 × 10 -14 m apart.
Approximately how many times is the
electrostatic force between them
greater than the gravitational force
between them?
A 1023
B 1030
C 1036
D 1042
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• Two protons are 1.0 × 10 -14 m apart.
Approximately how many times is the
electrostatic force between them
greater than the gravitational force
between them?
A 1023
B 1030
C 1036
D 1042
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(a) (i) Define the electric field strength,
E, at a point in an electric field.
(ii) State whether E is a scalar or a
vector quantity.
(3 marks)
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(a) (i) Define the electric field strength, E, at a
point in an electric field.
(ii) State whether E is a scalar or a vector
quantity.
(3 marks)
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(b) Point charges of + 4.0 nC and - 8.0 nC are placed 80
mm apart
(i) Calculate the magnitude of the force exerted on
the + 4.0 nC charge by the -8.0 nC charge.
(ii) Determine the distance from the + 4.0 nC charge
to the point, along the straight line between the
charges, where the electric potential is zero.
• (4 marks)
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(c) Point P is equidistant from the two charges.
(i) Draw two arrows on the diagram at P to represent
the directions and relative magnitudes of the
components of the electric field at P due to each of
the charges.
(ii) Hence draw an arrow, labelled R, at P to represent
the direction of the resultant electric field at P.
(3 marks)
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Garfield Graphics included with kind permission from PAWS Inc. All Rights Reserved.