Transcript + H 2 O(l )

Chemistry Chapter 11
Chemical Reactions
Describing Chemical Reactions
Chemical Reaction- process by which one or more
substances are changed into one or more
different substances.
Reactant- original substance
Product- resulting substance
Chemical Equation - Represents the identities and
relative amounts of the reactants and products in
a chemical reaction
How do you know a chemical reaction occurred?
Evidence that one or more substance has
undergone a change in identity.
1. Evolution of heat and light.
2. Production of a gas
3. Formation of a precipitate (solid produced in
solution that separates from the solution)
Characteristics of Chemical Equations
Must represent the known facts.
The equation must contain the correct
formulas for the reactants and products.
The law of conservation of mass must be
satisfied.
(coefficients are used to equalize the #
of moles of a substance)
Word and Skeleton Equations
Word equation
methane + oxygen
Skeleton Equation
CH4(g) + O2(g)
carbon dioxide + water
CO2(g) + H2O(g)
Balance Equation
Usually balance Hydrogen and Oxygen last.
CH4(g) + 2O2(g)
CO2(g) + 2H2O(g)
Sample Problem 1
•Write word and formula equations for
the chemical reaction that occurs when
solid sodium oxide is added to water at
room temperature and forms sodium
hydroxide (dissolved in the water).
Include symbol for physical states and
then balance.
Answer 1
Sodium oxide + water  sodium hydroxide
Na2O + H20  NaOH
Na2O(s) + H20(l)
 2NaOH(aq)
Balancing Equations
Identify the names of the reactants and products
and write a word equation.
water  hydrogen + oxygen
Write the formula equation.
H2O(l)  H2 (g) + O2 (g)
Balance the equation
1. balance 1 at a time.
2. balance atoms that are combined
and appear only once on each side.
3. balance polyatomic ions as single
units
4. balance H and O last.
Balancing cont.
2H2O(l)  H2 (g) + O2 (g)
2H2O(l)  2H2 (g) + O2 (g)
Count the atoms.
2H2O(l)  2H2 (g) + O2 (g)
Sample Problem 2
•The reaction of zinc with aqueous
hydrochloric acid produces a solution of
zinc chloride and hydrogen gas. Write
a balanced equation for the reaction.
Answer 2
• Zn(s) + 2HCl(aq)  ZnCl2(aq) + H2(g)
Sample Problem 3
• Solid aluminum carbide, Al4C3, reacts
with water to produce methane gas
and solid aluminum hydroxide. Write a
balanced chemical equation for this
reaction.
Answer 3
Al4C3(s) + 12H20(l)  3CH4(g) + 4Al(OH)3(s)
What are the driving forces of reactions?
•
•
•
•
Formation of a solid
Formation of water
Transfer of electrons
Formation of a gas
Types of Solution Reactions
 Precipitation
reactions
AgNO3(aq) + NaCl(aq)  AgCl(s) +
NaNO3(aq)
 Acid-base
reactions
NaOH(aq) + HCl(aq)  NaCl(aq) + H2O(l)
 Oxidation-reduction
reactions
Fe2O3(s) + Al(s)  Fe(l) + Al2O3(s)
Precipitation Reaction
K2CrO4(aq) + Ba(NO3)2 --> KNO3 + Ba(CrO4)
Figure 4.13: When yellow
aqueous potassium chromate
is added to a colorless
barium nitrate solution,
yellow barium chromate
precipitates.
Precipitation reaction
(Double Replacement)
Yellow potassium chromate with colorless barium nitrate
yields a yellow precipitation
K2 CrO4 (aq)  Ba( NO3 ) 2 (aq)  product
In virtually every case when a solid containing
ions dissolves in water, the ions separate and move
around independently.
What happens when an Ionic compound Dissolves in
Water?
Strong electrolytes:
2 K  (aq)  CrO4 2 (aq)  Ba 2 (aq)  NO3   product
How is the yellow solid formed?

2


2 K (aq)  CrO4 (aq)  Ba (aq)  2 NO3 (aq)
1. Ions form a compound; zero net charge. Thus the product must
contain anions and cations.
2. Most ionic materials contain only two types of ions: one type
of cation and one type of anion.
possibilities….K2CrO4 KNO3 BaCrO4 Ba(NO3)2
****CrO4 is the only yellow ion.
What happens to the K+ and NO3-?
2 K  (aq)  CrO4 2 (aq)  Ba  (aq)  2 NO3  (aq)
They are not involved in the reaction
Therefore…..
K2 CrO4 (aq)  Ba( NO3 ) 2 (aq)  Ba(CrO4 )( s)  2 K ( NO3 )(aq)
Remain in solution
Simple Rules for Solubility
1.Most nitrate (NO3) salts are soluble.
2.Most alkali (group 1A) salts and NH4+ are soluble.
3.Most Cl, Br, and I salts are soluble (NOT Ag+,
Pb2+, Hg22+)
4.Most sulfate salts are soluble (NOT BaSO4,
PbSO4, HgSO4, CaSO4)
5.Most OH salts are only slightly soluble (NaOH,
KOH are soluble, Ba(OH)2, Ca(OH)2 are marginally
soluble)
6.Most S2, CO32, CrO42, PO43 salts are only
slightly soluble.
Molecular Equation
K2 CrO4 (aq)  Ba( NO3 ) 2 (aq)  Ba(CrO4 )( s)  2 K ( NO3 )(aq)
Complete ionic equation
2


2 K  (aq)  CrO 4 (aq)  Ba 2 (aq)  NO3 (aq)  BaCrO 4 ( s )  2 K  (aq )  NO3 (aq)
Net ionic equation
2
CrO 4 (aq)  Ba 2 (aq)  BaCrO 4 ( s )
Predict the following and write the molecular and
net ionic equations:
1. Aqueous sodium sulfide is mixed with
aqueous copper(II)nitrate to
produce…
2. Aqueous ammonium chloride and
aqueous lead(II)nitrate react to
form…
Acid-Base Reactions
• Acid
substance that produces H+ ions
when it is dissolved in water.
• Base
substance that produces hydroxide
ions (OH-) in water.
Product of strong acid + strong base
• When a strong acid and a strong base
react the chemical change that always
occurs is that H+ ions react with OHto form water.
• Strong acid- HCl, HNO3, H2SO4
• Strong base-NaOH, KOH
Products of a strong acid/strong base reaction:
1. Water
2. Ionic compound (salt) which may
precipitate or remain dissolved
Aqueous nitric acid and aqueous aluminum
hydroxide react to form…
Molecular
HNO 3 (aq )  Al (OH ) 3 (aq)  H 2O(l )  Al ( NO 3 ) 3 (aq )
Ionic
H  (aq )  NO 3  (aq )  Al 3 (aq )  OH  (aq )  H 2O (l )  Al 3 (aq )  NO  3 (aq )
Net Ionic
H  (aq )  OH  (aq )  H 2O(l )
Weak acids and bases do not ionize.
sodium hydroxide + oxalic acid →
2 NaOH + H2C2O4 (aq)  Na2C2O4 + 2 H2O (l)
Ionic : 2Na+ + 2OH- + H2C2O4 (aq)  2Na+ + C2O42- +2H2O (l)
Net:
H2C2O4 (aq) + 2 OH-  C2O42- +2 H2O (l)
Formation of Gases
1. CO2
2. H2S
3. NH3
(H2CO3  H2O + CO2)
(sulfide salt + acid)
(NH4OH  NH3(aq) + H2O(l))
Ammonia solution + acetic acid 
Weak base + weak acid  salt
NH4OH  NH3(aq) + H2O(l)
NH3(aq) + HC2H3O2 (aq)  NH4C2H3O2(aq)
NH3(aq) + HC2H3O2 (aq)  NH4+ (aq) + C2H3O2-(aq)
Oxidation Reduction Reaction
Synthesis
Single replacement
Combustion
Decomposition
Synthesis (Composition) Reactions
Two or more substances combine to form a
new compound.
A + X  AX
 Reaction of elements with oxygen and sulfur
 Reactions of metals with Halogens
 Synthesis Reactions with Oxides
Synthesis Reactions of Elements w/ Oxygen and
Sulfur
Most metals react w/ oxygen to form oxides.
They react similarly w/ sulfur to form sulfides.
2Mg(s) + O2(g)
8Ba(s) + S8(s)
2 MgO(s)
8BaS(s)
Synthesis Reactions of Metals with
Halogens
Most group 1 and 2 metals react with the halogens
2Na(s) + Cl2(g)
2NaCl(s)
Synthesis Reactions w/ Oxides
Metal oxides react with water to produce
metal hydroxides.
CaO(s) + H2O(l)
Ca(OH) 2(s)
Synthesis w/ oxides cont.
Many oxides of nonmetals in the upper
right portion of the periodic table
react w/water to produce oxyacids.
SO2(g) + H2O(l)
2H2SO3(aq) + O 2(g)
H2SO3(aq)
2H2SO4(aq)
Synthesis reactions cont.
Certain metal oxides and nonmetal oxides
react w/ each other to form salts.
CaO(s) + SO2(g)
CaSO3(s)
Decomposition Reactions
A single compound undergoes a reaction that
produces two or more simpler substances
AX  A + X
Decomposition of:
Binary compounds
Metal carbonates
Metal hydroxides
Metal chlorates
Oxyacids
2H2O(l )  2H2(g) + O2(g)
CaCO3(s)  CaO(s) + CO2(g)
Ca(OH)2(s)  CaO(s) + H2O(g)
2KClO3(s)  2KCl(s) + 3O2(g)
H2CO3(aq)  CO2(g) + H2O(l )
Formation of a Gas
• Zn(s) + 2HCl(aq)  H2(g) + ZnCl2(aq)
• How would you classify this reaction?
precip, acid-base, redox
It is an electron transfer process
Also called... Single replacement
redox
Single Replacement Reactions
A + BX  AX + B
BX + Y  BY + X
Replacement of:




Metals by another metal
Hydrogen in water by a metal
Hydrogen in an acid by a metal
Halogens by more active halogens
The Activity Series of the Metals
Lithium
Potassium
Calcium
Sodium
Magnesium
Aluminum
Zinc
Chromium
Iron
Nickel
Lead
Hydrogen
Bismuth
Copper
Mercury
Silver
Platinum
Gold
Metals can replace other metals
provided that they are above the
metal that they are trying to
replace.
Metals above hydrogen can
replace hydrogen in acids.
Metals from sodium upward can
replace hydrogen in water
The Activity Series of the Halogens
Fluorine
Chlorine
Bromine
Iodine
Halogens can replace other
halogens in compounds, provided
that they are above the halogen
that they are trying to replace.
???
+ Cl2(g)
2NaCl(s) + F2(g)  2NaF(s)
???Reaction
MgCl2(s) + Br2(g)  No
Combustion Reactions
A substance combines with oxygen, releasing a large
amount of energy in the form of light and heat.
Usually produce CO2 and H20
(special form of oxidation-reduction)
The burning of natural gas, wood, gasoline
C3H8(g) + 5O2(g)  3CO2(g) + 4H2O(g)
Oxidation-Reduction (Redox) Reactions
Oxidation Number (State): A value which
indicates whether an atom is neutral, electronrich, or electron-poor.
Rules for Assigning Oxidation Numbers
1. An atom in its elemental state has an
oxidation number of 0.
Na
H2
Br2
S
Oxidation number 0
Ne
2. A monatomic ion has an oxidation number
identical to its charge.
Na1+
Ca2+
Al3+
Cl1-
O2-
+1
+2
+3
-1
-2
3. An atom in a polyatomic ion or in a molecular
compound usually has the same oxidation
number it would have if it were a monatomic
ion.
a) Hydrogen can be either +1 or -1.
H
+1
O
1-
-2
H
Ca
-1
+2
H
-1
b) Oxygen usually has an oxidation number
of -2.
H O H
H O O H
+1
-2 +1
with halogens it’s (+2) OF2
+1
-1 -1
peroxide
+1
3. c) Halogens usually have an oxidation number
of -1.
H
Cl
+1
-1
Cl
+1
O
-2
Cl
+1
4. The sum of the oxidation numbers is 0 for a
neutral compound and is equal to the net
charge for a polyatomic ion.
H2SO3
+1
x -2
Cr2O72x
-2
2(+1) + x + 3(-2) = 0 (net charge)
x = +4
2(x) + 7(-2) = -2 (net charge)
x = +6
Assign Oxidation #s
• UF6
• H2SO4
• ClO3-
Examples - assigning oxidation numbers
Assign oxidation states to all elements:
SO3
SO42-
K
NH3
MnO4
Cr2O72-
CH3OH
PO43-
ClO3
HSO3
Cu
H2
+
53
The chemical changes that occur when electrons
are transferred between reactants are called
oxidation – reduction reactions
54
Oxidation and Reduction
• Oxidation: complete or partial loss of
electrons or gain of oxygen.
Not all reactions involve burning.
example:
Iron rusting: Fe + O2  Fe2O3
Bleaching: 4 NaClO + 2 H2O → 4 Na+ + 4
OH- + 2 Cl2 + O2
The O2 then attaches to stains
Reduction: opposite of oxidation
complete or partial gain of electrons
or loss of oxygen.
Iron rusting: Fe + O2  Fe2O3
Bleaching:
4 NaClO + 2 H2O → 4 Na+ + 4 OH- + 2 Cl2 + O2
OIL RIG
• Oxidation involves loss of electrons
• Reduction involves gain of electrons
LEO says GER
• For every oxidation there is a
reduction. The electrons are
transferred from one spies to the
other.
REDOX
+2 = Oxidation
+2 -1
+4 -1
SnCl2 +
PbCl4
+4 -1
+2 -1
SnCl4 +
PbCl2
-2 = Reduction
-3 = Reduction
+2-2 +1
+5-2
CuS + H+ + NO3-
+2
Cu+2 +
0
S
+2-2
NO
+1 -2
H2O
+2 = Oxidation
58
Try These!!
+1 = Fe
2+
is oxidized
5 Fe2+ + MnO4- + 8 H+  5 Fe3+ + Mn2+ + 4 H2O
- 5 = Mn
+2 = Zn
0
7+
is reduced
is oxidized
Zn + 2 HCl  ZnCl2 + H2
- 1 = H
1+
is reduced
59
How to write net ionic equations
• 1) write a balanced equation
(aq)
Cu(s) + 2NaCl(aq)
2Na(s) + CuCl2

2) Ionize any aqueous substances
Cu(s) + 2Na1+(aq) 2Cl1-(aq)

2Na(s) + Cu2+
(aq)
2Cl 1-
(aq)
3) Remove any like substances (spectators)
Cu(s) + 2Na1+(aq) 2Cl1-(aq)

2Na(s) + Cu2+
(aq)
2Cl 1-
(aq)
4) Sum up what’s left
Cu(s) + 2Na1+(aq)

2Na(s) + Cu2+
(aq)
The Net Ionic Equation (the reaction that60
is really occurring)
Oxidation Reduction Reaction
Synthesis
• Reaction that involves a transfer of
electrons.
• Presence of oxygen **hint**
2Mg(s) + O2(g)  2MgO(s)
MgMg2+ + 2eoxidation
O + 2e- O2reduction
Most REDOX reactions used for energy production
Thermite Reaction (single replacement)
Fe2O3(s) + 2Al(s)  2Fe(l) + Al2O3(s)
Al  Al3+ +3e-
Fe3+ 3e- Fe (molten)
Production of Bleach
Cl2 + 2 NaOH → NaCl + NaClO + H2O
Identify the oxidize and reduced species
What do you notice different about this
reaction?
Hence, chlorine is simultaneously reduced
and oxidized; this process is known
as disproportionation.
Balancing Equations with the Half-Reaction Method
1) Identify what is oxidized and what is reduced.
Split the equation into two half-reactions.
In each half-reaction, follow these steps:
2) Balance all elements except “H” and “O”.
3) Balance the “O’s” by adding water, H2O.
4) Balance the “H’s” by adding hydrogen ions, H+.
5) Balance the charges by adding electrons. If necessary,
multiply one or both half reactions by an integer to equalize
the number of electrons transferred in the two half-reactions.
6) Recombine the ½ reactions into a complete balanced
equation, cancel identical species.
64
Example:
Fe2+ + Cr2O72-  Fe3+ + Cr3+ acidic solution
6( Fe2+
21( 6 e-+ 14 H+ + Cr2O7
Fe3+ + 1e- )
 2Cr3+ + 7 H2O)
Cr2O72- + 6 Fe2+ + 14 H+  2 Cr3+ + 6 Fe3+ + 7 H2O
65
Table 12.1 Strength of oxidizing and reducing agents
Inquiry into Chemistry Chapter 12
Oxidizing Agent
Reduction
Oxidation
Reducing Agent
Stronger Oxidizing Agent
Cu 2+
Cu
Zn 2+
Zn
Stronger Reducing Agent
66
Oxidation
Reduction
Strongest Oxidizing Agent
Weakest Reducing Agent
Ba 2+ (aq)
Ba (s)
Ca 2+ (aq)
Ca (s)
Mg 2+ (aq)
Mg (s)
Al 3+ (aq)
Al (s)
Zn 2+ (aq)
Zn (s)
Cr 3+ (aq)
Cr (s)
Fe 2+ (aq)
Fe (s)
Cd 2+ (aq)
Cd (s)
Tl + (aq)
Tl (s)
Co 2+ (aq)
Co (s)
Ni 2+ (aq)
Ni (s)
Sn 2+ (aq)
Sn (s)
Cu 2+ (aq)
Cu (s)
Hg 2+ (aq)
Hg (s)
Ag 2+ (aq)
Ag (s)
Pt 2+ (aq)
Pt (s)
Au 1+ (aq)
Au (s)
Weakest Oxidizing Agent
Strongest Reducing Agent
67
Spontaneous Reaction
Compare Reducing Agents
Loses 2 e Pt (s)+
Sn 2+ (aq)  Pt 2+ (aq)+
Sn (s)
Gains 2 eStronger
Reducing
Agent
Stronger
Oxidizing
Agent
Compare Oxidizing
Agents
68
Non Spontaneous Reaction
Compare Reducing Agents
Loses 2 e -
Mg (s) +
Fe2+ (aq)

Mg 2+ (aq) +
Fe (s)
Gains 2 eCompare Oxidizing
Agents
Stronger
Oxidizing
Agent
Stronger
Reducing
Agent
69
What if the solution was basic?
Notice that the method has assumed the solution was acidic - we
added H+ to balance the equation. The [H+] in a basic solution is
very small. The [OH-] is much greater.
For this reason, we will add enough OH- ions to both sides of the
equation to neutralize the H+ added in the reaction.
The hydrogen and hydroxide ions will combine to make water, and
you may have to do some canceling before you’re done.
Cr2O72- + Fe2+ + H2O  Cr3+ + Fe3+
Try this in a basic solution!!!
70
Cr2O72- + Fe2+ + H2O  Cr3+ + Fe3+ Basic Solution
6 ( Fe2+
)
1(6 e-+ 14OH
14 H-214H
O
+ ++
)
Cr2O72-
Fe3+ + 1e2 Cr3+ + 7 H2O
+ 14OH-
Cr2O72- + 6 Fe2+ + 7 H2O  2 Cr3+ + 6 Fe3+ + 14 OH-
71
Balancing Redox Equations Practice
Balance
in acidic solution:
H2C2O4 + MnO4-  Mn2+ + CO2
5 H2C2O4 + 2 MnO4- + 6 H+  2 Mn2+ + 10 CO2 + 8 H2O
Balance
in basic solution:
CN- + MnO4-  CNO- + MnO2
3 CN- + 2 MnO4- + H2O  3 CNO- + 2 MnO2 + 2 OH-
72
Chemical
reactions
Precipitation
Reactions
(Double replacement)
Oxidation-Reduction
reactions
Combustion
reactions
Single Replacement
Acid-Base
Reactions
(Double Replacement)
Decomposition
reactions
Synthesis
reactions