Worker-Machine Systems

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Transcript Worker-Machine Systems

Worker-Machine Systems
 Worker operates a powered equipment
 Examples:
Machinist operating a milling machine
Construction worker operating a backhoe ‫حفار‬
Truck driver driving an 18-wheel tractor-trailer‫جرار ومقطورة‬
Worker crew operating a rolling mill ‫ماكينة درفلة‬
Clerical worker entering data into a PC
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Relative Strengths
Humans
Machines
 Sense unexpected stimuli
‫ الشعور بالمؤثرات الغير متوقعه‬
 Solve problems
 Perform repetitive operations
consistently
 Store large amounts of information
 Adapt to change
 Generalize from observations
 Learn from experience
 Make decisions on incomplete data
 Retrieve data from memory reliably
 Perform multiple tasks at the same
time
 Apply high forces and power
 Perform computations very quickly
 Make routine decisions quickly
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Relative Strengths
 In a worker-machine system the worker and
the machine both contribute their own
strengths and capabilities
 The result is synergistic ‫التآزرية‬
 Types of worker-machine systems:
 Types of powered machinery used in the system
 Numbers of workers and machines in the system
 Level of operator attention required to run the
machinery
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Types of Powered Equipment

Powered machinery: A source of power other
than human (or animal) strength is used to
operate that tool (or machine).
1.Portable power tools
 Light enough in weight so that they can be easily carried
2.Mobile powered equipment
 Heavy pieces of equipment but transportable
3.Stationary powered machines
 Perfom functions in a stationary location
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Classification of Powered
Machinery
Portable power drills, chain saws,
electric hedge trimmers
Cars, buses, trucks, airplanes
Tractor, bulldozers, backhoes, forklifts
Electric power generators
Turning, drilling, milling
PCs, photocopiers, telephones
Ovens, cash register
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Numbers of Workers and Machines
One worker and One machine
 Taxicab driver and taxi
One worker and Multiple machines
 A worker operating several machines
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Numbers of Workers and Machines
Multiple workers and One machine
 A crew on a ship
Multiple workers and Multiple machines
 Emergency repair crew responding to
machine breakdowns in a factory
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Level of Operator Attention
 Full-time attention
 Welders performing arc welding
 Part-time attention during each work cycle
 Worker loading and unloading a production machine on
semi-automatic cycle
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Level of Operator Attention
 Periodic attention with regular servicing
 Worker loading a machine every 20 cycles
 Periodic attention with random servicing
 Firefighters responding to alarms
 Maintenance worker repairing machines
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Good Work Design for Machine-Worker
Systems
1. Design the controls of the machine to be logical and easy to
operate for the worker.
2. Design the work sequence so that as much of the worker’s
task as possible can be accomplished while the machine is
operating.
3. Minimize the idle times of both the worker and the machine.
4. Design the task and the machine to be safe for the worker.
5. If the system is a multiple worker or/and multiple machine
system, optimize the number of workers or machines in the
system according to a specified objective.
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Cycle Time Analysis

Two categories of worker-machine systems in terms of cycle time
analysis

Cases:
1. Systems in which the machine time depends on operator
control




A typist typing a list of names on a typewriter
Carpenter using power saw to cut lumber
A construction worker operating a backhoe
Cycle time analysis is same as for manual work cycle
2. Systems in which machine time is constant and independent
of operator control



Operator loading semi-automatic production machine
Our focus is on this 2nd type
Two types:
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Case 2.a: Cycle Times with No Overlap
Between Worker and Machine
 Worker elements and machine elements are sequential
 There is no overlap in work elements between the
worker and the machine
 While worker is busy, machine is idle
 While machine is busy, worker is idle
 Normal time for cycle
Tn = Tnw + Tm,
where
Tnw = Normal time for the worker-controlled portion of the
cycle time, min
Tm = Machine cycle time (assumed to be constant)
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Case 2.a: Cycle Times with No Overlap
Between Worker and Machine

Standard time for cycle
Tstd = Tnw (1 + Apfd) + Tm (1 + Am)
where
Am = Machine allowance factor

Am=30%: Workers love that since efficiencies are
overestimated
Am=0%: Workers hate that since efficiencies are
underestimated
Am= Apfd


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Example 2.8: Effect of machine
allowance on standard time
 Given: The work cycle consists of several
manual work elements (operator controlled)
and one machine element performed under
semiautomatic control. The manual work
elements: a normal time of 1 min and the
semiautomatic machine cycle time is 2 min.
Apfd=15%.
 Determine: the standard time using
(a) Am =0,
(b) Am=30%.
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Example 2.8: Solution

The normal time for the work cycle: Tn=1.0+2.0=3.0 min
(a) Tstd = Tnw (1 + Apfd) + Tm (1 + Am)
Tstd=1.0(1+0.15)+2.0=3.15 min
Workers
(b) Tstd = Tnw (1 + Apfd) + Tm (1 + Am)
Tstd=1.0(1+0.15)+2.0(1+0.30) =3.75 min
Workers
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Example 2.9: Effect of machine
allowance on worker efficiency

Given: Standard times in the previous example (Example 2.8).

Determine: The worker efficiencies if 150 units are produced in
an 8-hour shift.

Solution:
(a) Hstd = Q Tstd
Hstd=150(3.15)=472.5min=7.875hr
Ew = Hstd / Hsh
Ew=7.875/8.0=0.984=
98.4%
(b) Hstd = Q Tstd
Hstd=150(3.75)=562.5min=9.375hr
Ew = Hstd / Hsh
Ew=9.375/8.0=1.172=
117.2%
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Case 2.b: Internal Work Elements
 Some worker elements are performed while
machine is working
 Internal work elements performed simultaneously
with machine cycle
 External work elements performed sequentially with
machine cycle
 Desirable to design the work cycle with
internal rather than external work elements
 If it is possible, include operator work elements
that are performed while machine is running.
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Normal Time and Standard Time
 Normal time
Tn = Tnw + Max{Tnwi , Tm}
 Standard time
Tstd = Tnw (1 + Apfd) +Max{Tnwi (1 + Apfd) , Tm (1 + Am)}
 Actual cycle time
Tc = Tnw / Pw + Max{Tnwi /Pw , Tm}
where
Tnw = normal time for the worker’s external elements, min
Tnwi = normal time for the worker’s internal elements, min
Tm = machine cycle time, min
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Example 2.10: Internal vs external work
elements in cycle time analysis
Work Element Description
Worker
Time
(min)
Machine
Time
(min)
1
Worker walks to tote pan containing raw stock
0.13
(idle)
2
Worker picks up raw workpart and transports to machine
0.23
(idle)
3
Worker loads part into machine and engages machine
semiautomatic cycle
0.12
(idle)
4
Machine semiautomatic cycle
(idle)
0.75
5
Worker unloads finished part from machine
0.10
(idle)
6
Worker transports finished part and deposits into tote pan
0.15
(idle)
0.73
0.75
Seq.
Total
Tc=0.73+0.75=1.48 min
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Example 2.10: Internal vs external work
elements in cycle time analysis
Work Element Description
Worker
Time
(min)
Machine
Time
(min)
1
Worker unloads finished part from machine
0.10
(idle)
2
Worker loads part into machine and engages
semiautomatic machine cycle
0.12
(idle)
3
Machine semiautomatic cycle
(idle)
0.75
4
Worker transports finished part and deposits it into tote
pan, walks to tote pan containing raw stock, and picks up
raw workpart and transports it to machine. (This element
is internal to the machine semiautomatic cycle.)
0.15+
0.13+
0.23=
0.51
(operating)
0.73
0.75
Seq.
Total
Tc=0.10+0.12+0.75=0.97 min
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Example 2.10: Internal vs external work
elements in cycle time analysis

The cycle time is reduced from 1.48 min to 0.97 min.

% cycle time reduction=(CTcurrent-CTimproved)/CTcurrent
=(1.48-0.97)/1.48=34%

Rcurrent=1/1.48 min=0.68 units per min

Rimproved=1/0.97 min=1.03 units per min

% increase in R=(Rimproved-Rcurrent)/Rcurrent
=(1.03-0.68)/0.68=53%
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Automated Work Systems
 Automation is the technology by which a
process or procedure is accomplished without
human assistance
 Implemented using a program of instructions
combined with a control system that executes
the instructions
 Power is required to drive the process and
operate the control system
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Automated Work Systems
Automated robotic
spot welding cell
(photo courtesy of Ford
Motor Company)
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Levels of Automated Systems
 There is not always a clear distinction between worker-machine
systems and automated systems, because many workermachine systems operate with some degree of automation.
1. Semiautomated machine
 Performs a portion of the work cycle under some form of
program control
 Human worker tends the machine for the rest of the cycle by
loading unloading etc.
 Operator must be present every cycle
 Same characteristics with worker-machine system
 e.g.,an automated lathe requires a worker to unload parts at
every cycle, although changing tools may not be required at
every cycle
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Levels of Automated Systems
1. Fully automated machine
 Operates for extended periods of time with no human
attention (longer than one work cycle, e.g. every
hundredth cycle ‫)كل مائة دورة‬
 e.g., periodically the molded parts at a molding
machine must be collected.
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Determining worker and machine
Requirements
 How many workers/machines are required to
achieve the organization’s work objectives?
 If too few workers are assigned to perform a
given amount of work
 The work cannot be completed on time, customer
service will suffer.
 If too many workers are assigned to perform
a given amount of work
 The payroll costs are higher than needed, and
productivity will suffer.
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Determining worker and machine
Requirements
• Workload (WL): Total hours required to
complete a given amount of work or to produce a
given number of work units scheduled during the
period
 Available time (AT): The number of hours (in the
same period) available from one worker or
worker-machine system
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Case 3.1: When Setup is not a Factor
Workload
WL=QTc
where
WL = workload scheduled for a given period, hr,
Q = quantity to be produced during the period. pc/period,
Tc = work cycle time required per work unit, hr/pc. (Tc =Tstd)
If the workload includes multiple part or product styles that are
produced by the same work system:
WL   Q jTcj
j
where
Qj =quantity of part or product style j, pc,
Tcj =cycle time of part or product style j, hr/pc.
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Case 1: When Setup is not a Factor
 Number of workers and number of machines
required:
W = WL / AT,
or
n = WL / AT
where
w
= number of workers,
n
= number of workstations,
AT = available time of one worker in the
period, hr / period / worker
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Example 2.11: Determining Worker
requirements
 Given: 800 shafts must be produced in the
lathe section of a machine shop in particular
week. Each shaft is identical and Tstd=11.5min.
All the lathes are identical. There are 40 hours
of available time on each lathe.
 Determine: Number of lathes and lathe
operators must be devoted during that week.
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Example 2.11: Solution
 Workload:
WL=800(11.5 min)=9200 min=153.33hr
Machine (and worker) requirements
w =n =153.3/40=3.83 (round up)
=4 lathe operators and lathes
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Factors that affect the workload
1. Learning effect: As learning occurs in repetitive
manual work, worker efficiency increases, cycle
time decreases so that the workload is reduced.
2. Worker efficiency: Worker may perform either
above or below standard performance.
Ew =
Workload actually completed
Workload completed at standard performance
 Worker efficiency greater than 1.00 reduces the
workload.
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Factors that affect the workload
Defect rate: Fraction of parts produced that are defective.
A defect rate greater than zero increases the quantity of
work units that must be processed to yield the desired
quantity. So workload increases with defect rate.
The relationship between the starting quantity and the final
quantity produced:
Q =Q0 (1-q)
where
Q= quantity of good units made in the process,
Q0 =original or starting quantity; q=fraction defect rate.
The combined effect of worker efficiency and defect rate is
given by
WL=(QTstd) / (Ew(1-q))
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Availability
 A common measure of reliability for equipment
 Defined as the proportion of time the equipment is
available to run relative to the total time it could be used.
 Available time increases as availability increases
AT=Hsh A
where
AT =available time, hr/worker,
Hsh=shift hours during the period, hr,
A =availability, expressed as a decimal fraction.
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Example 2.12: Effect of worker efficiency
defect rate, and availability
 Given:
Previous
example.
Anticipated
availability of the lathes 95%. Expected worker
efficiency during production=110%. The
fraction defect rate=3%.
 Determine: Number of lathes required.
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Example 2.12: Solution
 Total workload
WL=(QTstd) / (Ew(1-q))
WL =( 800 (11.5/60) ) / ( 1.10 (1-0.03) ) = 143.7 hr
Available time
AT=Hsh A
AT=40(0.95)=38hr/machine
n=WL/AT
n=143.7/38=3.78 lathes (and lathe operators)
=4 lathes (and lathe operators)
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