Transcript File

Unit 5:
Momentum
and Impulse
1
Momentum
What does it mean to have
momentum?
2
Sports Example
• Coach: “We have all the momentum.
Now we need to use that momentum
and bury them in the third quarter.”
• What does the coach mean?
• His team is on the move and will take
some effort to stop.
3
Momentum
• All objects in motion have
momentum!
• What factors determine how much
momentum an object has?
4
Linear Momentum
• Linear momentum (p) – product of an object’s
mass and velocity.


p  mv
• Momentum is a vector that points in the same
direction as the velocity.
• Units: kg *m/s
5
• Example #1: A freight train moves due north with a
speed of 1.4 m/s. The mass of the train is 4.5 x 105
kg. How fast would an 1800 kg automobile have to
be moving due north to have the same momentum?
ptrain = mtrainvtrain
=(4.5 x 105 kg)(1.4 m/s)
= 630,000 kg*m/s
pauto = mautovauto
pauto
vauto 
mauto
kg  m
630,000
s

= 350 m/s
1800 kg
6
Varying Forces
• Forces are not always constant. Many forces
change as they are applied over a period of
time.
Average Force
(F)
t0
tf
When a baseball hits a bat, the ball is in contact with the
bat for a short time interval. The force reaches its
maximum value towards the middle of the time interval.
7
Impulse
• For a baseball to be hit well, both the size of the
force and the time of contact (Follow through!) are
important.
• Impulse (J) – product of the average force F
and the time interval Δt over which the force
 
acts.
J  F  t
• Units: Newton * seconds (Ns)
• Impulse is a vector that points in the same
direction as the average force.
8
Impulse-Momentum Theorem


nd
• Remember Newton’s 2 Law: F  m a

 v
• And acceleration is defined as a 
t



v


• Substitute: F  m 

 t 
• Rearrange:
Impulse-Momentum Theorem


F  Δt  m Δv
9
Impulse-Momentum Theorem
• Another way to write the theorem is:


J  p
• In words: Impulse = Change in Momentum
10
• Example #2: A volleyball is spiked so that its
incoming velocity of +4.0 m/s is changed to an
outgoing velocity of -21 m/s. The mass of the
volleyball is 0.35 kg. What impulse does the
player apply to the ball?
v0 = +4.0 m/s
vf = -21 m/s
m = 0.35 kg


J  p
 mv f  mv0
 (0.35kg)( 21m / s)  (0.35kg)( 4.0m / s)
 8.75 Ns
11
Impulse
Why doesn’t the egg break??
http://www.youtube.com/watch?v=7RSUjxiZnME
12
Impulse
An object with 100 units of momentum must experience
100 units of impulse to be brought to a stop .
This can come from any combination of Force x time.
As time
Force
13
Conservation of Momentum
• closed system – system where nothing is lost
and no net external forces act.
• Law of Conservation of Momentum – the total
momentum of any closed system does not
change; the momentum before an interaction
equals the momentum after the interaction.
p0  p f
14
Collisions in 1-Dimension
Inelastic
• Inelastic collision- a collision in which the
objects stick together and move with one
common velocity after colliding.
• 2 objects  1 object
15
Inelastic Collisions
Example 3: Two cars collide and become entangled. If car #1 has a mass
of 2000 kg and a velocity of 20 m/s to the right, and car #2 has a mass of
1500 kg and a velocity of 25 m/s to the left, find the velocity of the
system after the collision.
BEFORE Collision
AFTER Collision
p0  p f
m1v1  m2 v2  mtotalv f
m1v1  m2 v2
vf 
mtotal
(2000kg)( 20m / s)  (1500kg)( 25m / s)

(3500kg)
 0.71 m/s to the right
16
Explosions
• Explosion- process of one object splitting into 2
(or more) objects
• Recoil- kickback; momentum opposite a projectile
• 1 object  2 objects (or more)
17
Explosions
Example 4: Starting from rest, two skaters push off each other on smooth
level ice. Skater 1 has a mass of 88 kg and Skater 2 has a mass of 54 kg.
Upon breaking apart, Skater 2 moves away with a velocity of 2.5m/s to the
right. Find the recoil velocity of Skater 1.
BEFORE Explosion
AFTER Explosion
p0  p f
mtotalv0  m1v1 f  m2 v2 f
0  m1v1 f  m2 v2 f
v1 f 
 m2 v2 f
m1
 (54 kg)( 2.5 m/s )

 1.53 m/s
(88 kg)
18
OR 1.53 m/s to the left
Collisions in 1-Dimension
Elastic
• Elastic collision – a collision in which the
colliding objects bounce off each other.
• 2 objects  stay 2 objects
19
Elastic Collisions
BEFORE Collision
AFTER Collision
?
?
p0  p f
m1v10  m2v20  m1v1 f  m2v2 f
This is the hardest type of
problem since there are two
pieces on both sides!
20
Elastic Collisions Example
21
Elastic Collisions
BEFORE Collision
AFTER Collision
?
?
p0  p f
m1v10  m2v20  m1v1 f  m2v2 f
If there are 2 unknowns we would
need to use Conservation of Energy
and solve a system of equations…
We may do this type of problem, but
NOT YET!
22
Is Kinetic Energy Conserved?
•Elastic Collision: KE is conserved
•Inelastic Collision: KE is NOT conserved
23
Practice Problem #1
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Practice Problem #2
• An automobile accident investigator needs to
determine the initial westerly velocity of a Jeep
(m=1720 kg) that may have been speeding before
colliding head-on with a Volkswagen (m=1510 kg)
that was moving with a velocity of 21 m/s east. The
speed limit on the road was 55 mi/hr. After the
collision, the Jeep and Volkswagen stuck together
and continued to travel with a velocity of 4.3 m/s
west.
a. Find the initial westerly velocity of the Jeep.
b. Was the jeep speeding?
25
Practice Problem #2
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