Transcript Astronomy

Astronomy
Day One
Ptolemy
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Copernicus
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Galileo
He found the four
large moons of
Jupiter with his
large telescope.
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Brahe
Made great
measurements of the
skies.
Fake nose that he lost
in a duel
Assistant was Kepler
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Kepler
Determined what Brachs work
was good for.
1st law, orbits are ellipses not circles.
2nd, for similar time periods, the areas
in the triangles is the same.
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3rd law, T2/R3
T is time
R is distance from Sun, or other
gravitationally attractive point.
Examples of Kepler's 3rd Law
Taken from The physics classroom tutorial
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Newton put these together with the
three laws of motion.
a. Velocity will not change unless there
is an unbalanced force.
b. Force, Mass and Acceleration are
related. Force = Mass x Acceleration
c. Every action has an equal and
opposite reaction.
Our understanding of the elliptical motion of planets about
the Sun spanned several years and included
contributions from many scientists.
a. Which scientist is credited with the collection of the data
necessary to support the planet's elliptical motion?
b. b. Which scientist is credited with the long and difficult
task of analyzing the data?
c. c. Which scientist is credited with the accurate
explanation of the data?
Tycho Brahe gathered the data. Johannes Kepler
analyzed the data. Isaac Newton explained the data
Galileo is often credited with the early discovery of four of
Jupiter's many moons. The moons orbiting Jupiter follow the
same laws of motion as the planets orbiting the sun. One of
the moons is called Io - it's distance from Jupiter's center is
4.2 units and it orbits Jupiter in 1.8 Earth-days. Another moon
is called Ganymede; it is 10.7 units from Jupiter's center.
Make a prediction of the period of Ganymede using Kepler's
law of harmonies.
Answer: T = 7.32 days
Given:Io: Rio = 4.2 and Tio = 1.8
Ganymede: Rg = 10.7 Tg=???
Use Kepler's 3rd law to solve.
(Tio)2/(Rio)3 = 0.04373;so (Tg)2 / (Rg)3 = 0.04373
Proper algebra would yield (Tg)2 = 0.04373 ・ (Rg)3(Tg)2 = 53.57
so Tg = SQRT(53.57) = 7.32 days
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Cross multiply and divide.