Transcript Force on a current carrying conductor

Force on a current carrying
conductor
Submitted to:
Dr. Tariq Bhatti
Submmited by:
Ahmad Mushtaq
Roll No.: 07-45
Program BS-it
Session 2007-11
Department of Computer Science
Bahauddin Zakariya University,
Multan
How to find force on a current
carrying conductor ?
Equation for finding force on a moving particle
can be used to find force on a current carrying
conductor.
Current
Source: www.boredofstudies.org
Substituting
We know that,
F = qv x B
Substituting,
Velocity v = vd
Total Charge q = Nq = nAlq
Hence,
F = nAlqvd x B
. ..
N = nAl
Relation of Force with Length &
Current
F = nAlqvd x B
‘l’ has the same direction as ‘vd’ we can
write:
lvd = lud
Substituting:
F = nAlqud x B
Relation of Force with Length &
Current
F = nAlqud x B
We know that,
Current Density j = nqud
and Current I = jA = nqud A
Hence,
F = Il x B
Magnitude of Magnetic Force
F = Il x B sin0
Where ‘O’ is angle b/w directions of ‘l ’ & ‘B’.
Direction of
the force can
be determined
by fleming’s
left hand rule
Source: http://physics503.one-school.net
What if conductor is not straight?
Here we use,
dF=Idl x B
For sum,
F= ∫Idl x B
Conclusion:
The magnitude of the force on length l of the conductor is
proportional to the length as well as to the current in the
conductor and to the magnitude of the magnetic field.
Elements For Presentation