Transcript PHY 231 Lecture 29 (Fall 2006)

Physics 213
General Physics
Lecture 9
Exam 1: Raw Scores
35
30
# of students
25
20
15
10
5
0
0
20
40
60
80
100
Raw score
1
Exam 1: % Scores Without Curve
35
30
# of students
25
20
15
10
5
0
0
20
40
60
80
100
120
140
% score without curve
2
Exam 1: % Scores With Curve
35
30
# of students
25
N1  N2  25
 100%
90
20
15
10
5
0
0
20
40
60
80
100
120
140
% score with curve
3
Last Meeting: Magnetism &
Magnetic Field
Today: Lorentz Force and Torque
4
5
6
7
Determining the Direction of
Force, the Right Hand Rule
Point your fingers in the
direction of v
Curl the fingers in the
direction of the magnetic
field, B
Your thumb points in the
direction of the force, F , on
a positive charge
If the charge is negative, the
force is opposite that
determined by the right hand
rule
┴
┴
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10
Circular Orbit of Charged Particle
in a Magnetic Field
mv
r
qB
Particle Moving in an External
Magnetic Field

If the particle’s
velocity is not
perpendicular to the
field, the path
followed by the
particle is a spiral
 The
spiral path is
called a helix
Force on a Wire



B is into the page
The current is up
the page
The force is to the
left
13
Force on a Wire
(cont.)



B is into the page
The current is
down the page
The force is to the
right
14
Force on a Wire



The magnetic force is exerted on each moving
charge in the wire
The total force is the sum of all the magnetic
forces on all the individual charges producing
the current
F = B I ℓ sin θ
 θ is the angle between B and the direction
of I
 The direction is found by the right hand
rule, placing your fingers in the direction of
I instead of v
15
How is force determined?
Force on each charge carrier.
Fi  qvd B sin 
Total number of charge carriers.
N  nAl
Total Force
Ftotal  nAqvd Bl sin   IBl sin 
In lecture 5 we derived
I  nAqvd
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17

Demo

Wire in Magnetic Field
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19
θ
┴

θ

20
Torque on a Current Loop




Applies to any shape
loop
N is the number of turns
in the coil
Torque has a maximum
value of NBIA


When  = 90°
Torque is zero when the
field is perpendicular to
the plane of the loop
21
Motors
22
μ=
┴


θ
μ
μ
θ
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μ

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μ
   B sin 
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