Section 7.3 Second Day Central Limit Theorem
Download
Report
Transcript Section 7.3 Second Day Central Limit Theorem
Section 7.3
Second Day
Central Limit
Theorem
Quick Review
PCFS
The problem is that most
populations AREN’T normally
distributed.
Proportions
p = the proportion of
_____ who …
SRS
np≥10 and n(1-p)≥10
Population ≥ 10n
x mean
z
std . dev
Means
Parameter
Conditions
Random
Normality
Independence
Formula
Sentence
µ = the mean …
SRS
Population ~ Normally
Population ≥ 10n
z
x mean
std . dev
Houston,…
We have a problem…
Most
population distributions
are not Normal
Ex. - Household Incomes
So when a population
distribution is not Normal, what
is the shape of the sampling
distribution of x-bar?
Describe the shape of the sampling
distributions as n increases. What do
you notice?
Sample Means
Consider the strange population distribution from the Rice University
sampling distribution applet.
The Central Limit Theorem
If
the population is normal, the sampling
distribution of x-bar is also normal. THIS IS
TRUE NO MATTER HOW SMALL n IS.
As long as n is big enough, and there is a
finite population standard deviation, the
sampling distribution of x-bar will be
normal even if the population is not
distributed normally.
How big is “big enough?” We will use n > 30
This is called the Central Limit Theorem.
and
say, “since
Memorize
it. n > 30, the CLT says the
sampling distribution of x-bar is Normal.”
PCFS
Proportions
p = the proportion of
_____ who …
Means
Parameter
Conditions
SRS
µ = the mean …
Random
SRS
np≥10 and n(1-p)≥10
Normality
Population ≥ 10n
Independence
Population ~ Normally
OR “since n> 30, the
CLT says the sampling
distribution of x-bar is
Normal.”
Population ≥ 10n
x mean
z
std . dev
Formula
z
Sentence
x mean
std . dev
Example: Servicing Air
Conditioners
Based on service records from the past
year, the time (in hours) that a
technician requires to complete
preventative maintenance on an air
conditioner follows the distribution
that is strongly right-skewed, and
whose most likely outcomes are close
to 0. The mean time is µ = 1 hour and
the standard deviation is σ = 1
Your company will service an SRS of 70 air
conditioners. You have budgeted 1.1 hours per unit.
Will this be enough?