Transcript Document

Math 3680
Lecture #8
Continuous Random
Variables
Suppose we throw a dart at a number line in such a way that it
always lands in the interval [1,3]. Let X be the number that
the dart hits. Since the possible values of X consist of an entire
interval, we call X a continuous random variable.
P( c  X  d )
Discrete
Continuous
Definition: A continuous random variable X on an
interval [a, b] has a probability density function (pdf)
f ( x) that satisfies the following three conditions:
1. f ( x ) ≥ 0 for all values of x.
b
2.
 f ( x)dx  1.
a
d
3. P (c  X  d ) 
 f ( x)dx.
c
The cumulative distribution function (cdf) of X is
FX ( x ) = P( X  x ).
Example: Let X be a random variable with density
function
f ( x ) = (3 / 14) (x + x2) over [0,2].
A) Verify that f ( x ) is a density function.
B) Compute P ( X  1).
C) Compute F( x )
for x < 0,
for 0  x  2, and
for x > 2.
Graph of cumulative distribution function
1
0.8
0.6
0.4
0.2
0.5
1
1.5
2
2.5
3
Properties of cumulative distribution functions
• F( x ) = P( X  x )
• 0  F( x )  1
• F is non-decreasing
• F is right-continuous: F(x+) = F(x) for each x
• For a continuous r.v. X, F is always continuous
• For any a < b, P( a < X  b ) = F( b ) - F( a )
b
  f ( x)dx
a
Theorem: F ’ ( x ) = f ( x ).
x
Proof. By definition,
F ( x) 
 f (t )dt.

Therefore, by the Fundamental Theorem of Calculus,
F ’ ( x ) = f ( x ).
Definition: For a random variable X, the r th
percentile (denoted by x r/100) is the value x so that
r
F ( x) 
.
100
The idea is that r % of the area under the curve lies to
the left of x r/100.
Example: Suppose a random variable X has pdf
1
f(x)= 2
x
over
(1, ).
Find the median (50th percentile) of the distribution.
Definition: In statistics, we will often have occasion
to compute the critical value that corresponds to a
predetermined significance level. The significance
level, denoted by a, sets a desired probability, or an
area under a tail of the pdf.
This kind of calculation is entirely equivalent to
finding percentiles.
Example: Suppose a random variable X has pdf
1
f(x)= 2
x
over
• Find the right-tail critical value if the significance
level is a = 0.01.
Moments
Definition:

m  E ( X )   x f ( x)dx


E( X ) 
2
x
f
(
x
)
dx

2

Var( X ) = E[ (X - m)2 ]
s = SD( X ) =  Var( X )
Var( X ) = E[ X 2 ] - m2
Theorem: If a and b are real constants, then
E( a X + b ) = a E( X ) + b
Var( a X + b ) = a2 Var( X )
SD( a X + b ) = | a | SD( X )
Proof:
Example: Suppose a random variable X has pdf
f ( x ) = 6 x - 6 x2
over [0,1].
Find the mean, variance, and standard deviation of X.
1.4
1.2
1
0.8
0.6
0.4
0.2
0.2
0.4
0.6
0.8
1
Example: A random variable X is said to have the c2(4)
distribution if its pdf is
x x / 2
f ( x)  e , x  0.
4
0.175
0.15
0.125
0.1
0.075
0.05
0.025
2
4
6
8
Find the mean and standard deviation of X.
10
12
14
The Uniform Distribution
UNIFORM DISTRIBUTION
A continuous random variable X is said to have a
Uniform(a, b) distribution if its density function is
given by
1
f ( x) 
ba
for a  x  b.
Example: Compute the mean and standard deviation
of the Uniform(a, b) distribution.
The Exponential Distribution
EXPONENTIAL DISTRIBUTION
A continuous random variable X is said to have an
Exponential(q ) distribution if its density function is
given by
f ( x) 
1
q
for x  0.
e
 x /q
Exercise: Confirm that
f ( x) 
1
q
e
 x /q
is a probability density function (for x  0).
Exercise: Compute the mean, variance, and standard
deviation of the Exponential(q ) distribution.
Memoryless Property of the Exponential
Distribution
Theorem: Let X be an exponential random
variable. Then for all t ≥ 0 and all s ≥ 0,
P( X  t  s | X  t )  P( X  s)
Proof:
Example: In the Luria-Delbrück mutation model, it is
assumed that a certain population experiences 0.25 mutations
per hour. A mutation just occurred. Compute the probability
that
a) At least four hours pass until the next mutation occurs.
b) At least four hours, but not more than 8 hours pass until
the next mutation occurs.
c) Repeat (a) and (b), but given that the last mutation
occurred three hours ago.