Chapter 10-part 2

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Transcript Chapter 10-part 2

Chapter 10
Chemical
Bonding II
Valence Bond Theory
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Linus Pauling and others applied the principles of quantum mechanics
to molecules
they reasoned that bonds between atoms would arise when the orbitals
on those atoms interacted to make a bond
the kind of interaction depends on whether the orbitals align along the
axis between the nuclei, or outside the axis
Valence Bond Theory: A quantum mechanical model which shows
how electron pairs are shared in a covalent bond.
◦ Bond forms between two atoms when the following conditions are met:
◦ Covalent bonds are formed by overlap of atomic orbitals, each of which contains one
electron of opposite spin.
◦ Each of the bonded atoms maintains its own atomic orbitals, but the electron pair in
the overlapping orbitals is shared by both atoms.
◦ The greater the amount of overlap, the stronger the bond.
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Orbital Interaction
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In some cases, atoms use “simple” atomic orbital (e.g., 1s, 2s, 2p, etc.) to
form bonds.
In other case, they use a “mixture” of simple atomic orbitals known as
“hybrid” atomic orbitals.
as two atoms approached, the partially filled or empty valence atomic
orbitals on the atoms would interact to form molecular orbitals
the molecular orbitals would be more stable than the separate atomic
orbitals because they would contain paired electrons shared by both
atoms
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Valence Bond Theory - Hybridization
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one of the issues that arose was that the number of partially filled or
empty atomic orbital did not predict the number of bonds or orientation
of bonds
◦ C = 2s22px12py12pz0 would predict 2 or 3 bonds that are 90° apart, rather
than 4 bonds that are 109.5° apart
to adjust for these inconsistencies, it was postulated that the valence
atomic orbitals could hybridize before bonding took place
◦ one hybridization of C is to mix all the 2s and 2p orbitals to get 4
orbitals that point at the corners of a tetrahedron
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Valence Bond Theory Main Concepts
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2.
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the valence electrons in an atom reside in the quantum mechanical
atomic orbitals or hybrid orbitals
a chemical bond results when these atomic orbitals overlap and
there is a total of 2 electrons in the new molecular orbital
a) the electrons must be spin paired
the shape of the molecule is determined by the geometry of the
overlapping orbitals
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Types of Bonds
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a sigma (s) bond results
when the bonding atomic
orbitals point along the axis
connecting the two bonding
nuclei
◦ either standard atomic
orbitals or hybrids
 s-to-s, p-to-p, hybrid-tohybrid, s-to-hybrid, etc.
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a pi (p) bond results when the
bonding atomic orbitals are
parallel to each other and
perpendicular to the axis
connecting the two bonding
nuclei
◦ between unhybridized
parallel p orbitals
the interaction between parallel
orbitals is not as strong as
between orbitals that point at
each other; therefore s bonds
are stronger than p bonds
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Tro, Chemistry: A Molecular
Approach
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Hybridization
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some atoms hybridize their orbitals to maximize bonding
◦ hybridizing is mixing different types of orbitals to make a new set of
degenerate orbitals
◦ sp, sp2, sp3, sp3d, sp3d2
◦ more bonds = more full orbitals = more stability
better explain observed shapes of molecules
same type of atom can have different hybridization depending on the
compound
◦ C = sp, sp2, sp3
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Hybrid Orbitals
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H cannot hybridize!!
the number of standard atomic orbitals combined = the number of
hybrid orbitals formed
the number and type of standard atomic orbitals combined determines
the shape of the hybrid orbitals
the particular kind of hybridization that occurs is the one that yields
the lowest overall energy for the molecule
◦ in other words, you have to know the structure of the molecule
beforehand in order to predict the hybridization
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sp3 Hybridization of C
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3
sp
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Hybridization
atom with 4 areas of electrons
◦ tetrahedral geometry
◦ 109.5° angles between hybrid orbitals
atom uses hybrid orbitals for all bonds and lone pairs
H
s
H
sp3 •• sp3
C
N
H
s
H
H
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Methane Formation
with sp3 C
Ammonia Formation with sp3 N
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2
sp
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atom with 3 areas of electrons
◦ trigonal planar system
 C = trigonal planar
 N = trigonal bent
 O = “linear”
◦ 120° bond angles
◦ flat
atom uses hybrid orbitals for s bonds and
lone pairs, uses nonhybridized p orbital for p
bond
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3-D representation of ethane (C2H4)
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Bond Rotation
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because orbitals that form the s bond point along the internuclear axis,
rotation around that bond does not require breaking the interaction
between the orbitals
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but the orbitals that form the p bond interact above and below the
internuclear axis, so rotation around the axis requires the breaking of
the interaction between the orbitals
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sp
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atom with 2 areas of electrons
◦ linear shape
◦ 180° bond angle
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atom uses hybrid orbitals for s bonds
or lone pairs, uses nonhybridized p
orbitals for p bonds
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3
sp d
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atom with 5 areas of electrons around it
◦ trigonal bipyramid shape
◦ See-Saw, T-Shape, Linear
◦ 120° & 90° bond angles
use empty d orbitals from valence shell
d orbitals can be used to make p bonds
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3
2
sp d
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atom with 6 areas of electrons around it
◦ octahedral shape
◦ Square Pyramid, Square Planar
◦ 90° bond angles
use empty d orbitals from valence shell
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d orbitals can be used to make p bonds
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Five types of hybrid are shown below
# of e- groups around
central atom
2
Hybrid orbitals
used
sp
3
sp2
4
sp3
5
sp3d
6
sp3d2
Orientation of Hybrid
Orbitals
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Predicting Hybridization and
Bonding Scheme
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Start by drawing the Lewis Structure
Use VSEPR Theory to predict the electron
group geometry around each central atom
Use Table 10.3 to select the hybridization
scheme that matches the electron group
geometry
Sketch the atomic and hybrid orbitals on the
atoms in the molecule, showing overlap of the
appropriate orbitals
Label the bonds as s or p
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Examples:
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Predict the Hybridization and Bonding Scheme of All the Atoms in
Then sketch a σ framework and a π framework
••
•O
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N
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CH3CHO
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CH2NH
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H3BO3
••
Cl ••
••
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Problems with Valence Bond Theory
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VB theory predicts many properties better
than Lewis Theory
◦ bonding schemes, bond strengths, bond lengths,
bond rigidity
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however, there are still many properties of
molecules it doesn’t predict perfectly
◦ magnetic behavior of O2
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