Transcript Homework

7 Days
Two days
 y  x2  4

 y  2x 1
 x 2  2 y  10

 x y 7

p590 #2,5,11,13,19 - 21, 26 NO TI
 x 2  y 2  25
 2
 x  y  25
 x2 y2  9

2x  y  0

p590 #15, 18,25,26,48,50,52

11-1 WS #5-20all, 23,25
Two days
 y  x2  4

 y  2x  2
 x 2  y 2  25

2
 y  x  4x  5
x  22   y  12  9

2
y

x
 4x  3


pg 608 #5-11 odd, 15, 19, 23-29 odd

pg 608 #6-10 even, 16, 22-32 even

Field Trip: LD is preparing a trip to New York for 400 students. The
company who is providing the transportation has small buses of 40
seats each and large buses of 50 seats, but only has 9 drivers
available. Graph the system of inequalities to show all possible
combinations of small buses and large buses that could be used for
the trip.

Deal at the Outlets: Aeropostale at the Outlets in Hershey wants to
liquidate 200 of its shirts and 100 pairs of pants from last season.
They have decided to put together two offers, A and B. Offer A is a
package of one shirt and a pair of pants]. Offer B is a package of
three shirts and a pair of pants. The store does not want to sell less
than 20 packages of Offer A and no less than 10 of Offer B. Graph
the system of inequalities to show all possible combination of offer
A and offer B that can be sold.

pg 610 #35-38, 41

Chicken Feed: One of your friends who owns a local farm asks you to
use mathematics to help them save money. They have their
chickens a healthy diet to gain weight. The chickens have to
consume at least 15g of grain and at least 15g of protein. In the
local market there are only two types of chicken feed for sale: Type
X, with a composition of one gram of grain to five grams of protein,
and another type, Y, with a composition of five grams of grain to
one gram of protein. The price of a bag of Type X is $10 and Type Y
is $30. What are the quantities of each type of feed that have to be
purchased to cover the needs of the diet with a minimal cost?

Systems of Inequalities WS
Four Days
Inverses can be used to solve systems of
equations. Solving large systems requires
a different method using an augmented
matrix.
An augmented matrix consists of the
coefficients and constant terms of a
system of linear equations.
A vertical line separates the
coefficients from the constants.
To write an augmented matrix, be
sure your equations are in the form
ax + by = c or ax + by + cx = d.
Write the augmented matrix for the
system of equations.
Write the augmented matrix.
You can use the augmented matrix of a
system to solve the system. First you will
do a row operation to change the form of
the matrix. These row operations create a
matrix equivalent to the original matrix. So
the new matrix represents a system
equivalent to the original system.
For each matrix, the following row
operations produce a matrix of an
equivalent system.
Row reduction is the process of
performing elementary row operations on
an augmented matrix to solve a system.
The goal is to get the coefficients to
reduce to the identity matrix on the left
side.
This is called reduced row-echelon form
1x = 5
1y = 2
 2x  y  8

 x  3 y  3
 x  2 y  3z  4

 2x  y  4z  3
 3x  4 y  z  2


Get into groups of 4 students and solve the
following systems using matrices.
  x  y  3z  6

 2x  2 y  z  9
3x  y  2 z  7

 3x  y  5 z  8

 2x  3 y  z  6
 x  2 y  2 z  10


Pg 633 (#1, 3, 19)
 2x  8 y  6

5 x  3 y  19
 x  3 y  3z  5

 2 x  y  z  3
 6 x  3 y  3z  4

 x1  x2  3x3  2 x4  1
  2 x  4 x  3x  x  .5

1
2
3
4

3x1  x2  10 x3  4 x4  2.9
 4 x1  3x2  8 x3  2 x4  .6

pg 633 (# 2, 4, 18, 20)


Pg 633 (# 5,10 by hand; 7,8 w/ calc)
Pg 673 (# 9,10,16 w/ calc)
2 Days

The size of a matrix is #Rows x #Columns

Matrices to be added must the same size.
Scalar Multiplication - each element
in a matrix is multiplied by a
constant.
1.  27 1 0  
2
2. 4 
 4
-14
2 0
0 
-8 0 
 


5
16 -20
2
1
3.  5
4
5


7 8
3
-5 -10 15 



6   -20 25 -30

9
35 -40 45 


Matrix Multiplication
**Multiply rows times columns.
**You can only multiply if the number of columns in
the 1st matrix is equal to the number of rows in the 2nd
matrix.
8 2 
3 2 5  

5 
7 1 0  1

 
0 3

They must match.
Dimensions: 2 x 3
3x2
The dimensions of your answer.
Examples:
2 1 3 9 2 
1. 
 


3
4
5
7
6

 

2(3) + -1(5) 2(-9) + -1(7) 2(2) + -1(-6)
3(3) + 4(5)
3(-9) + 4(7)
1
29

3(2) + 4(-6)
25 10 

1 18
3 9 2  2 1
2. 



5 7 6   3 4 
Dimensions: 2 x 3
2x2
*They don’t match so can’t be multiplied
together.*
1 2 1  x  1 
3. 1 3 2   y   7 
 2 6 1   z  8 
x  2y  z  1
x  3y  2z  7
2x  6y  z  8
0 1  4 3 *Answer should be a
4. 



2x2
1
0

2
5



2x2
2x2
0(4) + (-1)(-2) 0(-3) + (-1)(5)
1(4) + 0(-2)
1(-3) +0(5)
2 -5
 

4 -3
3 2
A

1 3
1 2
B

3 4
Find A B
Find B A
Does A  B  B  A ???
 2 2
A

 4 3
Find A B
Find B A
1 0
B

0 1
1 0
Identity Matrix : I  

0 1
Identity Property of Matrices :
A I  A
IA A