Transcript 87 ÷ 6

Objective:
• Divide numbers beyond the times tables using
‘chunking’
© Hamilton Trust
Stepping Up Term 2
Week 5 Day 1
87 ÷ 6
Are there more than ten 6s in 87?
ten 6s
four 6s
= 60
0
= 24
60
r3
84
87
So, how many 6s are in 87? 14 remainder 3
We can also write this using a vertical layout...
© Hamilton Trust
Stepping Up Term 2
Week 5 Day 1
87 ÷ 6
? x 6 = 87
10 x 6 = 60
27
4 x 6 = 24
3
what’s left over?
this is the remainder.
So, 87 ÷ 6 = 14 remainder 3
© Hamilton Trust
Stepping Up Term 2
Week 5 Day 1
With a partner, have a go at 95 ÷ 7
____ 7s =
____ 7s =
0
r__
95
Or try using the vertical layout - whichever you find easiest…
© Hamilton Trust
Stepping Up Term 2
Week 5 Day 1
Now have a go at 85 ÷ 3
Use chunking on the number line, or use the vertical
layout – remember to show a jump for the largest
possible multiple of 10 of the divisor…
Will the first jump be ten 3s, twenty 3s, thirty 3s…?
© Hamilton Trust
Stepping Up Term 2
Week 5 Day 1
85 ÷ 3
twenty 3s
eight 3s
= 60
0
= 24
60
r1
84
85
So, how many 3s are in 85? 28 remainder 1
© Hamilton Trust
Stepping Up Term 2
Week 5 Day 1
Aim to complete 1, 2 or
3 of these groups of
division calculations…
÷7
÷4
85
÷6
÷5
÷5
÷6
© Hamilton Trust
97
÷7
÷5
÷4
÷4
Stepping Up Term 2
78
÷6
÷7
Week 5 Day 1