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Energy Level Arrangements
How does one know how many electrons
are found in each energy level for a given
atom?
Here are some simple steps to follow when
determining the number of electrons in
each energy level.
First locate where the element is found in
the Periodic Table.
To demonstrate here’s how to determine the
energy level arrangement for S.
Next assign group numbers to the periodic table.
8
1 2
3 4 5 6 7
2 2 2 2 2 2 2 2 2 2
These numbers represent the number
of electrons in the last energy level
Next assign row numbers.
1
2
3
8
1 2
3 4 5 6 7
2 2 2 2 2 2 2 2 2 2
+
4
5
6
7
These numbers represent the number
of energy levels atoms of this element
have.
S has 3 energy levels and 6 e1- in the last
8
energy level
1 2
3 4 5 6 7
1
2
3
4
5
6
7
2 2 2 2 2 2 2 2 2 2
+
Draw blank lines for each of the energy levels
The number of e1- in the 2nd last energy level is
always determined by subtracting the number of
e1- already placed from the total number in a S
atom.
16 - (2+6) = 16-8 = 8
# of e1- in
each level
Energy
level
#
2
8
6
1
2
3
Here is a Bohr-Rutherford Diagram
S
16
6e18e1-
16 p1+ 2e1-
Now it’s your turn.
Determine the number
of electrons in each
energy level for an atom
of tin and then construct
a Bohr-Rutherford
Next assign row numbers.
1
2
3
4
5
8
1 2
3 4 5 6 7
2 2 2 2 2 2 2 2 2 2
+
6
7
These numbers represent the number
of energy levels atoms of this element
have.
Sn has 5 energy levelsand 4 e1- in the last
8
energy level
1 2
3 4 5 6 7
1
2
3
4
5
6
7
2 2 2 2 2 2 2 2 2 2
+
Draw blank lines for each of the energy levels
The number of e1- in the 2nd last energy level is
always determined by subtracting the number of
e1- already placed from the total number in a Sn
atom.
50 - (2+8+18+4) = 50-32 = 18
# of e1- in
each level
Energy
level
#
2
8
18
18
4
1
2
3
4
5
Here is a Bohr-Rutherford Diagram
Sn
50
4e1-
18e118e18e1-
50 p1+ 2e1-
Now it’s your turn.
Determine the energy level
arrangements and draw the
Bohr Rutherford Diagrams
for each of the following:
Co,
Rh,
Ba,
V.
27
45
56
23
Co has 4 energy levels and 2 e1- in the last
8
energy level
1 2
3 4 5 6 7
1
2
3
4
5
6
7
2 2 2 2 2 2 2 2 2 2
+
Draw blank lines for each of the energy levels
The number of e1- in the 2nd last energy level is
always determined by subtracting the number of
e1- already placed from the total number in a Co
atom (27 - (2+8+2) = 27-12 = 15
# of e1- in
each level
Energy
level
#
2
8
15
2
1
2
3
4
Here is a Bohr-Rutherford Diagram
27Co
2e115e18e1-
27 p1+ 2e1-
Rh has 5 energy levelsand 2 e1- in the last
8
energy level
1 2
3 4 5 6 7
1
2
3
4
5
6
7
2 2 2 2 2 2 2 2 2 2
+
Draw blank lines for each of the energy levels
The number of e1- in the 2nd last energy level is
always determined by subtracting the number of
e1- already placed from the total number in a Rh
atom (45 - (2+8+18+2) = 45-30 = 15
# of e1- in
each level
Energy
level
#
2
8
18
15
2
1
2
3
4
5
Here is a Bohr-Rutherford Diagram
45Rh
2e1-
15e118e18e1-
45 p1+ 2e1-
Ba has 6 energy levels and 2 e1- in the last
8
energy level
1 2
3 4 5 6 7
1
2
3
2 2 2 2 2 2 2 2 2 2
4
5
6
7
+
Draw blank lines for each of the energy levels
The number of e1- in the 2nd last energy level is
always determined by subtracting the number of
e1- already placed from the total number in a Ba
atom (56 - (2+8+18+18+2) = 56-48 = 8
# of e1- in
each level
2
Energy
level
1
#
8
18
18
8
2
2
3
4
5
6
Here is a Bohr-Rutherford Diagram
56Ba
8e1-
18e118e18e1-
56 p1+ 2e1-
2e1-
V has 4 energy levels and 2 e1- in the last
8
energy level
1 2
3 4 5 6 7
1
2
3
4
5
6
7
2 2 2 2 2 2 2 2 2 2
+
Draw blank lines for each of the energy levels
The number of e1- in the 2nd last energy level is
always determined by subtracting the number of
e1- already placed from the total number in a Va
atom (23 - (2+8+2) = 23-12 = 11
# of e1- in
each level
Energy
level
#
2
8
11
2
1
2
3
4
Here is a Bohr-Rutherford Diagram
23V
2e111e18e1-
27 p1+ 2e1-