Slides: C1 Chapter 6 - Sequences
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Transcript Slides: C1 Chapter 6 - Sequences
C1 Chapter 6 Arithmetic Series
Dr J Frost ([email protected])
Last modified: 7th October 2013
Types of sequences
common difference
π
?
+3
+3
+3
2, 5, 8, 11, 14, β¦
This is a:
Arithmetic
? Series
common?ratio π
×2 ×2
×2
3, 6, 12, 24, 48, β¦
1, 1, 2, 3, 5, 8, β¦
? Series
Geometric
This is the Fibonacci Sequence. The
terms follow a recurrence relation
because each term?can be generated
using the previous ones.
The fundamentals of sequences
ππ
π
π = 3?
The πth? term.
If πΌπ is the βcurrent termβ, how
could we describe:
?
The position.
The previous term:
The term before that:
π3 = 8?
?
2, 5, 8, 11, 14, β¦
?
πΌπβπ
πΌπβπ
?
Thus the following sequence:
1, 1, 2, 3, 5, 8, β¦
Could be described using:
πΌπ = π,
πΌπ = π,
? + πΌπβπ
πΌπ = πΌπβπ
Term-to-term and position-to-term
2, 5, 8, 11, 14, 17, β¦
What is the formula for the πth term based on:
β¦the position of the term π:
ππ = 3π β?1
β¦the previous term:
ππ = ππβ1 + 3
?
πβ₯1
πth term of an arithmetic sequence
We often use π to denote the first term. Recall that π is the difference between
terms, and π is the position of the term weβre interested in.
1st Term
π ?
2nd Term
π +?π
3rd Term
π +?2π
...
...
ππ = π + π β 1 π
πth term
π + (π?β 1)π
πth term of an arithmetic sequence
Find the requested term of the following sequences.
2, 5, 8, 11, 14, 17, β¦
100th term
10, 8, 6, 4, β¦
50th term
π = 10,
? π = β2,
? π = 50
?
π50 = β88
?
5π₯, π₯, β3π₯, β7π₯, β¦
20th term
π = 5π₯,
? π = β4π₯,
? π = 20
?
π20 = β71π₯
?
π = 2,
? π =?3, π = 100
?
π100 = 299
?
Give that the 3rd term of an arithmetic series is 20 and the 7th term is 12. Find
a) The first term.
b) The 20th term.
24?
β14
?
Exercises
1
The first term of an arithmetic sequence is 14. If the fourth term is 32, find the
common difference.
π
=? π
2
Given that the 3rd term of an arithmetic series is 30 and the 10th term is 9, find π
and π.
π = ππ,?π
= βπ
3
In an arithmetic series the 20th term is 14 and the 40th term is -6. Find the 10th
term.
ππ
?
4
For which values of π₯ would the expression β8, π₯ 2 and 17π₯ form the first three
terms of an arithmetic series.
π
π= ?
,π = π
π
The number of terms
Bro Tip: If youβre trying to work out the number of terms in a sequence, you can do
whatever you like to the terms in the sequence until you get 1 to π, after which the
number of terms becomes obvious.
1, 3, 5, 7, 9, β¦ , 111
? β¦ , 112
2, 4, 6, 8, 10,
1, 2, 3, 4,? 5, β¦ , 56
So there are 56 terms.
Add or subtract such
that the numbers are
now multiples of the
common difference.
Then divide.
The number of terms
How many terms? (work out in your head!)
1
2
3
4
5
5, 10, 15, 20, β¦ , 200
2, 5, 8, 11, 14, β¦ , 449
9, 19, 29, 39, β¦ , 1999
11, 16, 21, 26, β¦ , 151
5, 9, 13, 17, β¦ , 409
π = 40?
?
π = 150
?
π = 200
π = 29?
π = 102
?
Sum of the first π terms of a sequence.
πth term
ππ = π + π β 1 π
sum of first π terms
π
ππ = 2π ?+ π β 1 π
2
Letβs prove it!
Find the sum of the first 30 terms of the following arithmetic sequencesβ¦
1
2 + 5 + 8 + 11 + 13 β¦
π30 = 1365?
2
100 + 98 + 96 + β―
π30 = 2130?
3
π + 2π + 3π + β―
π30 = 465π?
Bro Tips: Explicitly write out "π =
β― , π = β― , π = β―β. Youβre less
likely to plug in numbers wrong
into the formula.
Make sure you write ππ = β― so
you make clear to yourself (and
the examiner) that youβre finding
the sum of the first π terms, not
the πth term.
Sum of the first π terms of a sequence.
Find the greatest number of terms for the sum of 4 + 9 + 14 + β― to exceed 2000.
πΊπ > ππππ,
π = π,
π
=π
π
ππ + π β π π
> ππππ
π
π
π + π β π π > ππππ
π
?
πππ + ππ β ππππ > π
π < βππ. π ππ π > ππ. π
So 28 terms needed.
Exam Question
Edexcel C1 Jan 2012
π =?400
π = £24450
?
Exam Question
Exercise 6F
Q1a, c, e, g
Q2a, c
Q5, Q6, 8, 10
Using Ξ£
What do these summations mean?
10
2π = 2 + 4 + 6 + 8 +?β― + 18 + 20
π=1
This is commonly seen
in exams.
4
ππ = π1 + π2 + π3 + ?
π4
π=1
15
10 β 2π = 0 + β2 + β4? + β― + β20
π=5
Using Ξ£
Bro Tip: As
always, start by
explicitly writing
out your π, π
and π values.
20
4π + 1 = 860 ?
π=1
5
10
3 + 2π = 48 ?
π=0
3 β π = β25 ?
π=1
More on recurrence relations
There will occasionally be two series questions, one on nth term/sum of n terms, and the
other on recurrence relations. Note that the sequence may not be arithmetic.
Edexcel C1 May 2013 (Retracted)
How would you say
this in words?
π₯2 =?1 β π
π₯3 = π₯22 β ππ₯2
= 1βπ 2βπ ?
1βπ
= 1 β 3π + 2π 2
? 32
π=
1
1
+1+ β
+β―
2
2
1
= 50 × 1 + β × 50 = 25
2
= 1+ β
?
More on recurrence relations
Edexcel C1 Jan 2012
π₯2 =?π + 5
π₯3 = π π +?5 + 5 = β―
π2 + 5π + 5 = 41
π2 + 5π β 36 = 0
π + 9 π?β 4 = 0
π = β9 ππ 4