Transcript exp01

Electronic Instrumentation
Experiment 1
* Part A: Circuit Basics, Equipment, Sound Waves
* Part B: Resistors, Circuit Analysis, Voltage Dividers
* Part C: Capture/PSpice
Course Web Resources and Logistics
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http://hibp.ecse.rpi.edu/%7Econnor/education/Ele
cInst.html
Open Shop and Office Hours
Announcements (printers)
Calendar
Links by Experiment
(http://hibp.ecse.rpi.edu/~connor/education/EILink
s.html )
Homework Assignments (LMS)
Quiz Information
Motivation
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Modern Systems
• mechanical component
• electrical component
• (computer component)
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You will be able to communicate with EE’s
You will be able to take the electronics
sections of the FE exam
You will be using Engineering problem
solving skills.
Automobile Electronics
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Previously all mechanical systems have
become increasingly electronic
Over the past few years, for example, the
automobile has begun to use more
computers (microcontrollers)
How many microcontrollers are typically
found in a modern automobile?
Automobile Electronics
Part A
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Circuit Basics
 Equipment
 Sound Waves
Physical Model for a DC circuit
pump = voltage source
water = flow of current
ocean = ground
pipe = wire
Physical Model for Resistance
pebbles in pipe = resistance to flow of current
Symbols
Physics vs. Electronics
Ohm’s Law : V = IR
High pressure
P1
I
Constriction
Pump
I
P2
Low pressure
Alternating Current Generators
http://micro.magnet.fsu.edu/electromag/java/generator/ac.html
http://www.walter-fendt.de/ph11e/generator_e.htm
AC Circuits
v(t )  i (t )  R
Note symbol for AC
voltage source
Review of Sinusoids
Vrms explanation
http://www.practicalphysics.org/go/Guidance_107.html
More on Phase Shift
Negative phase shift: “Lag in phase, lead in time”
1.0V
0V
-1.0V
0s
0.4ms
0.8ms
1.2ms
1.6ms
2.0ms
V(V1:+)
t0  0.08ms   2 (1K )   (0.08m)( 2K )( )  0.5 rad
Time
Positive phase shift: “Lead in phase, lag in time”
1.0V
0V
-1.0V
0s
0.4ms
0.8ms
1.2ms
1.6ms
2.0ms
V(V1:+)
t0  0.08ms   2 (1K )   (0.08m)( 2K )( )  0.5 rad
Time
Special Cases of Phase Shift
 t0 
   t0  2ft0  2  
T 
  0 rad
1.0V
   rad
1.0V
0V
0V
-1.0V
-1.0V
0s
0.5ms
1.0ms
0s
V(V1:+)
0.5ms
V(V1:+)
Time
Time
    2 rad
1.0V
0V
-1.0V
-1.0V
0.5ms
V(V1:+)
    2 rad
1.0V
0V
0s
1.0ms
1.0ms
0s
0.5ms
V(V1:+)
Time
Time
1.0ms
Sinusoid Units
DC Source E3631A –
Only for section 2
ADJUST
VOLTAGE
LEVEL
TOGGLE
OUTPUT
ON/OFF
-25 to 0 VOLTS
0 to 6 VOLTS
GROUND
GROUND
0 to 25 VOLTS
Do Not Use
Note: The connection that looks like the ground symbol is the
ground for the building, not the return path for the circuit.
DC Source for JEC-4201
Function Generator 33120A – Only
available in JEC 4107
Note: The SYNC connection will give you a signal,
but it will not be the one you have set the function
generator to display. Do not accidentally plug into it.
Function Generator
Figure A-1 (referred to in experiment)
We have a new board example: Func Gen 1 = AWG1
Digital Multimeter 34401A – We will have
some hand held meters in section 1 for
resistance measurements
Note: Always use the voltage plugs on the right as
indicated.
Digital Multimeter
Figure A-1 (referred to in experiment)
We have a new board example: ADC+ and GND =A1+ and GND
The IOBoard can read voltages but it isn’t an
Ohmmeter, We will use hand held meters for
resistance measurements
Oscilloscope 54600B – you
guessed it – JEC 4107
Note: Black lead of scope channel is ALWAYS ground
Protoboards
Note: Banana connectors are not connected internally to
the holes in the board.
Check continuity of power rails at top and bottom.
Reading Resistors
Bands: XYZT Resistance = XY 10 Z  T % 
http://www.dannyg.com/javascript/res/resload.htm
How Ears Work
Pitch = frequency Amplitude = loudness
Some pitches sound louder to your ears.
http://members.aol.com/tonyjeffs/text/dia.htm
In Class Problem
Across the top please put:
Name:
Section ((MR) or (TF)):
Date
Question 1: From diagram A: Which of the following
statements is true given the direction of the current flow.
a.) P2 < P1
b.) P2 = P1
c.) P2 > P1
Question 2: Draw the circuit equivalent of diagram A,
label current flow and voltage (+ and – on the voltage
source).
Question 3: Draw an AC signal with the following
parameters
Vp-p=6V
Vave=0V
Frequency=2KHz
Label the axis, label the amplitude and period
P1
I
Pump
I
Constriction
P2
Diagram A
Part B

Resistors
 Voltage Dividers
 Impedance
 Capacitors and Inductors
 Equipment Impedances
 Circuit Analysis
 Agilent Intuilink Software
Combining Resistors in Series
Combining Resistors in Parallel
Measuring Voltage
Total Voltage: V 1  VR1  VR 2
Voltage across resistors: VR1  VA  VB
VR 2  VB  VC
Voltage at points wrt GND: VA  V 1 VB  VR 2 VC  0
Voltage Dividers
The voltage is divided up in a manner
that is proportional to the resistances of
the resistors in a series circuit.
More on Voltage Dividers
4V 
4V 
3K  1K  5V 
1K  3K  1K
8K  5V 
1K  8K
You cannot use a voltage
divider on a non-series circuit.
Always add up resistors
relative to ground to get
the voltage at a point.
2V 
4 K  4V 
4K  4K
You can use a voltage divider
on a series portion of a circuit.
Impedance vs. Resistance
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Resistance is a property of a material that causes a
reduction in the rate of flow of electrons.
Impedance is the reduction in the rate of flow of
electrons caused by the material (resistance) AND
other the properties of the component involved
(reactance).
Resistors have no reactance. So the impedance of
a resistor is equal to its resistance only.
Reactance varies with the frequency of the input.
Resistance remains the same at all frequencies.
Both impedance and resistance are measured in
ohms.
Impedance
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Definition: A general measure of how a component
or group of components pushes against the current
flowing through it.
 Impedance = resistance + reactance
 Impedance is used to refer to the behavior of
circuits with resistors, capacitors and other
components.
 When we consider components in a theoretical
circuit diagram, the impedance of inductors and
capacitors is their reactance only. Any resistance is
modeled separately as a resistor. So theoretical
capacitors and inductors have impedance, but no
resistance.
Comparison of Components
V  IR
RT  R1  R2
RT1  R11  R21
R
R
Capacitors
Capacitors consist of two plates with a dielectric material
in-between. When a potential difference is placed across
the plates, a charge builds up until it is large enough to
cause a discharge across the plates through the material.
Reading Capacitors
- towards ground
Larger capacitors have the number of microfarads
written on them directly. Smaller capacitors use a
code based on the number of picofarads. We
generally use microfarads, so…
XYZ = XY * 10Z * 10-6 mF
Capacitors in Series
Capacitors in Parallel
Understanding Capacitor Behavior
Capacitor Impedance
Note: Real capacitors have effectively no resistance, so
impedance is reactance for all capacitors.
Comparison of Components
C
VR  I R R
IC  C
dVC
dt
RT  R1  R2 CT1  C11  C21
RT1  R11  R21 CT  C1  C2
R
open circuit
R
short circuit
Inductors
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An inductor is a coil of wire through which
a current is passed. The current can be
either AC or DC.
Inductors
dI L
VL  L
dt
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This generates a magnetic field, which
induces a voltage proportional to the rate of
change of the current.
Combining Inductors
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Inductances add like resistances
Series
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Parallel
L  L1  L2 ... LN
1
1
1
1


...
L L1 L2
LN
Inductor Impedance
Note: Real inductors always have a small resistance
(that is not shown in these circuits). The impedance of
the theoretical inductor shown is only its reactance.
Comparison of Components
C
VR  I R R
IC  C
dVC
dt
L
VL  L
dI L
dt
RT  R1  R2 CT1  C11  C21 LT  L1  L2
RT1  R11  R21 CT  C1  C2 LT1  L11  L21
R
open circuit
R
short circuit open circuit
short circuit
Equipment Impedances
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Each measuring device changes the circuit
when you use it.
The impedance of the device helps you
understand how much.
Device Impedances
•
•
•
•
•
Function Generator: 50 ohms
‘Scope: 1Meg ohms
DMM (DC voltage): 10Meg ohms
DMM (AC voltage): 1Meg ohms
DMM (DC current): 5 ohms (negligible)
Effect of Impedance on Circuit
Function generator thinks it
is putting out the same thing.
Output is clearly different.
Effect of Impedance on Circuit
Vout
Vout
Vout
Vout
50
Vin 

50  50
Vin
Better power transfer

2
1 10 6
Vin 

6
1 10  50
 Vin
Better efficiency
The IOBoard function generator has an output impedance of
much less than 50Ω, so we can ignore it. Our battery
however is a different story, as you will see in the experiment.
Kirchoff’s Laws
sum of voltages in
any loop is zero
sum of currents entering a
junction is the same as the sum of
the currents leaving a junction
Circuit Analysis (Combination Method)
Useful Aside: SI Suffixes
pico
nano
micro
milli
Kilo
Mega
Giga
Tera
p
n
m (u)
m
k
M (Meg)
G
T
10-12
10-9
10-6
10-3
103
106
109
1012
1
1
n
G
G
n
1
1
m
M
M
m
1
1
m
k
k
m
ex.
1
1 1

 0.1m
10k 10 k
Part C
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Capture
• Create circuits visually
• Set up simulation parameters
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PSpice
• Analyzes circuit
• Displays results
Capture
Simulations
run to time 
# cycles
freq
step size 
run to time
1000
PSpice
Note: To get copy of trace into word use Window
menu  ”copy to clipboard”
Cursors
Note: You can drag the left mouse button to move one
cursor and the right mouse button to move the other.
Adding Traces
Note: To add a trace use Trace menu 
”Add Trace”
Part D
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Oscilloscopes
 Lissajous Figures
Cathode Ray Tubes
y input
x input
Variation in potential difference (voltage) placed on
plates causes electron beam to bend different amounts.
“Sweep” refers to refreshing repeatedly at a fixed rate.
http://www.chem.uiuc.edu/clcwebsite/video/Cath.avi
Cathode Ray Tube Animation
http://webclass.cqu.edu.au/Units/81120_FOCT_Har
dware/Study_Material/Study_Guide/chap2/toc.html
Oscilloscopes
Horizontal sweeps at a constant rate. Vertical plates are
attached to an external voltage, the signal you attach to
the scope.
http://boson.physics.sc.edu/~hoskins/Demos/Cath
odeRay.html
Lissajous Figures
http://encyclozine.com/Science/Mathematics/Graphs/Lissajous/
Lissajous Figures
Normally the scope will plot a voltage signal with respect to time. In
a Lissajous figure, two voltage signals are plotted against each other.
Lissajous Example 1
t1
Lissajous Example 2
Lissajous Example 3
More Figures
In Class Problem
Across the top please put:
Name:
Section ((MR) or (TF)):
Date
P1
Question 1: From diagram A: Which of the following
statements is true given the direction of the current flow.
c.) P2 > P1
I
Pump
Current flow from high pressure to low pressure
therefore P2 must be greater than P1.
Question 2: Draw the circuit equivalent of diagram A,
label current flow and voltage (+ and – on the voltage
source).
Question 3: Draw an AC signal with the following
parameters
Vp-p=6V
Vave=0V
Frequency=2KHz
Label the axis, label the amplitude and period
I
Constriction
P2
Diagram A
Vsour ce
R1