Transcript How do resistors affect circuits?

Factors Affecting
Resistance
&
Power
Resistance Across a Circuit
Quick Review: What is resistance?
Resistance is what hinders the flow of current.
Resistance Across a Circuit
Quick Review: What is resistance?
Resistance is what hinders the flow of current.
All materials have some resistance.
Circuit elements (lights, motors, etc.) have much,
much more resistance than the wires, and are
often just called ‘resistors’.
Resistance Across a Circuit
How do resistors affect circuits?
Charges lose energy / potential due to resistance.
You can calculate the loss of potential – called
voltage drop – due to resistance using Ohm’s Law.
V2 – V1 = voltage drop = IR
Resistance in Wires
The resistance wires that connect most circuits can
be completely ignored!
But, in some cases, the wire is designed to have
high resistance (and high ‘loss’ of energy to heat),
usually by making the wire very very long …
Resistance in Wires
The resistance of a conducting wire
depends on four main factors:
• length
(longer = more resistance)
• cross-sectional area
(thinner = more resistance)
• temperature
(hotter = more resistance)
• resistivity of material
(ρ – different materials have different values)
Resistance of a wire when the temperature is
kept constant is:
L
R=ρ
A
L – length
A – cross-sectional area
Resistance in Wires
R=ρ
L
A
L – length
A – cross-sectional area
What kind of wire is the best conductor?
If you double the length of a wire, how
does the resistance change?
If you double the cross sectional area of a
wire, how does resistance change?
Resistance in Wires
R=ρ
L
A
L – length
A – cross-sectional area
What kind of wire is the best conductor?
A short fat cold wire
If you double the length of a wire, how
does the resistance change?
The resistance doubles.
If you double the cross sectional area of a
wire, how does resistance change?
The resistance is reduced by half.
Example Problem – We Do
A copper wire (r = 1.72x10-8 Wm) has a length of 1.67 m and a
radius of 1.00 mm. If the wire is connected to a 1.5-volt battery,
how much current flows through the wire?
Example Problem – We Do
A copper wire (r = 1.72x10-8 Wm) has a length of 1.67 m and a
radius of 1.00 mm. If the wire is connected to a 1.5-volt battery,
how much current flows through the wire?
The current can be found from Ohm's Law, V = IR. The V is the battery
voltage, so if R can be determined then the current can be calculated.
The first step, then, is to find the resistance of the wire:
L = 1.60 m.
r = 1.00 mm
r = 1.72x10-8 Wm, copper - books
The resistance of the wire is then:
R = r L/A = (1.72x10-8 Wm)(1.67)/(3.14x10-6m2 ) = 9.2 W
The current can now be found from Ohm's Law:
I = V / R = 1.5 / 9.2 = 0.16 A
Electric Power
Electric power is the rate at which …
…energy is supplied to or used by a device
OR
… electric energy is converted into another form
such as mechanical energy, heat, or light.
Electric Power
Electric power is the rate at which …
…energy is supplied to or used by a device
OR
… electric energy is converted into another form
such as mechanical energy, heat, or light.
Where is that energy coming from?
This energy is equal to the potential energy lost by the
charges as they move through the circuit elements
Electric Power
Electric power is the rate at which …
…energy is supplied to or used by a device
OR
… electric energy is converted into another form
such as mechanical energy, heat, or light.
Where is that energy coming from?
This energy is equal to the potential energy lost by the
charges as they move through the circuit elements
Power is measured in J s-1 called watts W.
Electric Power
Electric power is the rate at which …
…energy is supplied to or used by a device
OR
… electric energy is converted into another form
such as mechanical energy, heat, or light.
Where is that energy coming from?
This energy is equal to the potential energy lost by the
charges as they move through the circuit elements
Power is measured in J s-1 called watts W.
What does a 60W light bulb mean?
-- It converts electrical energy into light/heat
energy at a rate of 60 J per second.
Deriving expressions for determining power
Basic definition of power:
Remember: W = qV → P =
P=IV
W
P=
t
qV
t
and I = q/t, so
1W =
P = IV
P= V2/R
P= I2 R
1J
= 1A 1V
1s
Electric Power – We Do
• How much current is drawn by a 60 Watt light bulb
connected to a 120 V power line?
• What is the resistance of the bulb?
Electric Power – We Do
• How much current is drawn by a 60 Watt light bulb
connected to a 120 V power line?
P = 60 W = I V = I x 120
so I = 0.5 A
• What is the resistance of the bulb?
I = V/R
R = V/I = 120 V/0.5 A
R = 240 W
Electric Power – You Do
1. Calculate the resistance and the current of a 1500-Watt
electric hair dryer plugged into a US household outlet
(120 V).
2. The sticker on a compact disc player says that it draws
288 mA of current when powered by a 9 Volt battery. What
is the power (in Watts) of the CD player?
Electric Power – You Do
1. Calculate the resistance and the current of a 1500-Watt
electric hair dryer plugged into a US household outlet
(120 V).
I = P / V = (1500 W) / (120 V) I = 12.5 Amp
R = V / I= (120 V) / (12.5 Amp) R = 9.6
2. The sticker on a compact disc player says that it draws
288 mA of current when powered by a 9 Volt battery. What
is the power (in Watts) of the CD player?
P = I • V = (0.288 A) • (9 V) P = 2.59 W
Paying for electricity
You pay for electricity by the Kilowatt-hour (kWh).
What is a kWh? Simply another unit for energy.
Paying for electricity
You pay for electricity by the Kilowatt-hour (kWh).
What is a kWh? Simply another unit for energy.
Physicists measure energy in joules, but utility companies
customarily charge energy in units of kilowatt-hours (kW h), where :
Kilowatt-hour (kWh) = 1000 W x 3600 s
1 kWh = 3.6 x 106 J
1W x 1s = 1J
Paying for electricity
You pay for electricity by the Kilowatt-hour (kWh).
What is a kWh? Simply another unit for energy.
Physicists measure energy in joules, but utility companies
customarily charge energy in units of kilowatt-hours (kW h), where :
Kilowatt-hour (kWh) = 1000 W x 3600 s
1W x 1s = 1J
1 kWh = 3.6 x 106 J
At a rate of 14 cents per kWh, how much does it cost to keep a 100 W light bulb
on for one day?
• energy (kWh) = power (kW) x time (h)
•
energy (kWh) = 0.1 kW x 24 h = 2.4 kWh
cost / day = 2.4 kWh x 14 cents/kWh = 33.6 ¢
 for one month that amounts to $ 10.1.