Transcript Lecture #21

ECE 333
Renewable Energy Systems
Lecture 21: Photovoltaic Systems,
Water Pumping
Prof. Tom Overbye
Dept. of Electrical and Computer Engineering
University of Illinois at Urbana-Champaign
[email protected]
Announcements
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Exam 2 Average: 78
Read Chapter 8
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Amortizing PV Costs
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Simple payback is the easiest analysis, which assumes
there is no cost for money and no inflation. Annual
cost is just total cost divided by lifetime
This can give a quick ballpark figure
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•
Example: Assume 5 kW system with a capacity factor
of 18%, an installed cost of $ 5/W (after tax credits),
and a lifetime of 20 years with no maintenance costs.
What is $/kWh?

$5/W×5000 W

20 yrs
$1250/yr
=
=$0.158/ kWh
5 kW×0.18×8760
7884 kWh/yr
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Amortizing PV Costs
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More detailed analysis uses the capital recovery factor
using an assumed discount rate
Redo the previous example using a discount rate of 5%
per year
d (1  d )n
0.05  1.0520
A  P
 25, 000
n
(1  d )  1
1.0520  1
0.1327
A  25, 000
 2006.6
These values vary
1.6533
linearly with the
$2006.6/yr
assumed PV
=$0.2545/ kWh
installed cost
7884 kWh/yr
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Complications
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"It's tough to make predictions, especially about the
future", Yogi Berra (a baseball player/coach appearing
as a player or coach in 21 world series)
There is uncertainly about the rate of electric rate
inflation, and the decreasing costs of solar panels
Also, how long
will you own the
house, how is
PV included in
home's value
https://qzprod.files.wordpress.com/2014/11/us-consumer-price-indexes-year-on-year-change-core-cpi-headline-cpi_chartbuilder.png?w=1280
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Residential Solar Power
Purchase Agreements
• Solar PPAs are set so a customer has a developer design,
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permit, finance and install a PV system on the
customer's property
Customer then buys the solar power from the developer
at a fixed price (perhaps slowing inflating), typically
below the utility rate for a fixed time period (say 20
years)
The PPA requires little up front cost from the customer,
and the developer maintains the system
Can be transferred to a new owner if house is sold
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Utility Scale Solar Prices
Solar PV is
usually
purchased
on longterm
power
purchase
agreements
(PPAs)
Image Source: Steven Chu talk at NRC Next Generation Electric Grid Workshop, Irvine, CA, Feb 11, 2015
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In the News: Minnesota and
Renewable Energy
• This month Minnesota is considering changing a
requirement that the state get 1.5% of energy from solar
by 2020
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Proposed bill would allow utilities to meet requirements by
wind, hydro or biomass if cheaper than solar
It would also create rebates for geothermal heat pumps, wind,
solar thermal or storage; would also allow new nuclear
Also impacts net metering
Bill is getting a negative reception from some, " "Never
have I seen some people so upset over a bill that
reduces energy pollution and lowers energy costs."
Minnesota State Rep. Pat Garofalo
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Stand-Alone Configurations
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Key Issue is Intermittency of
Renewable Sources
• Unlike hydro, nuclear, and fossil, renewable energy from
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wind or solar PV cannot be stored in fuel form
In designing systems powered exclusively by such
systems some storage is usually needed
Image on right shows that
wind stopped in BPA area
for 11 days
In Dec 2014 Chicago had
ten days with only 30 minutes
of total sun, and only got 16%
of available sun up to Dec 22
Image Source: Steven Chu talk at NRC Next Generation Electric Grid Workshop, Irvine, CA, Feb 11, 2015
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Battery I-V Curves
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Energy is stored in batteries for most off-grid
applications
An ideal battery is a voltage source VB
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A real battery has internal resistance Ri
V  VB  Ri I
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Battery I-V Curves
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Charging– I-V line tilts right with a slope of 1/Ri,
applied voltage must be greater than VB
Discharging battery- I-V line tilts to the left with slope
1/Ri, terminal voltage is less than VB
A blocking diode
can be used
to prevent
the battery from
discharging
into the PV at
night.
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Hourly I-V Curves
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Current at any
voltage is
proportional to
insolation
VOC drops as
insolation
decreases
Can just adjust
the 1-sun I-V
curve by
shifting it up
or down
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Batteries and PV Systems
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Batteries in PV systems provide storage, help meet
surge current requirements, and provide a constant
output voltage.
Lots of interest in battery research, primarily driven by
the potential of pluggable hybrid electric vehicles
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$2.4 billion awarded in August 2009
There are many different types of batteries, and which
one is best is very much dependent on the situation
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Cost, weight, number and depth of discharges, efficiency,
temperature performance, discharge rate, recharging rates
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Lead Acid Batteries
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Most common battery for larger-scale storage
applications
Invented in 1859
There are three main types: 1) SLI (Starting, Lighting
and Ignition) : optimized for starting cars in which
they are practically always close to fully charged, 2)
golf cart : used for running golf carts with fuller
discharge, and 3) deep-cycle, allow much more
repeated charge/discharge such as in a solar
application
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Basics of Lead-Acid Batteries
Positive Plate: PbO2 + 4H + + SO42 + 2e  PbSO4  2H 2O (9.21)
Negative Plate: PbO2 + SO42  PbSO4  2e  (9.22)
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Basics of Lead-Acid Batteries
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During discharge, voltage and specific gravity drops
Sulfate adheres to the plates during discharge and comes
back off when charging, but some of it becomes
permanently attached
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Battery Storage
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Battery capacity has tended to be specified in amphours (Ah) as opposed to an energy value; multiply by
average voltage to get watt-hours
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Value tells how many amps battery can deliver over a
specified period of time.
Amount of Ah a battery can delivery depends on its
discharge rate; slower is better
Figure shows
how capacity
degrades with
temperature
and rate
Battery Costs have Been Decreasing
Image Source: Steven Chu talk at NRC Next Generation Electric Grid Workshop, Irvine, CA, Feb 11, 2015
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Battery Technologies
Type
Density,
Wh/kG
Cost
$/kWh
Cycles
Charge
time,
hours
Power
W/kg
Lead-acid,
deep cycle
35
50-100
1000
12
180
Nickel-metal
hydride
50
350
800
3
625
Lithium Ion
170
500-100
2000
2
2500
The above values are just approximate; battery technology is rapidly changing,
and there are many different types within each category. For stationary
applications lead-acid is hard to beat because of its low cost. It has about a 75%
efficiency. For electric cars lithium ion batteries appear to be the current front
runner
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Number of Cycles Depends on
Depth of Discharge
• The below graph shows results for a lead acid battery
Image Source: http://www.mpoweruk.com/life.htm
Ballpark would
be 1000 cycles
at 50% discharge;
if cost is $100
per kWh, or $200
per useable
kWh, then the
capital cost is
$0.20/kWh
This does not
include energy cost;
ballpark roundtrip
efficiency is 80% 20
Stand-Alone System Energy Needs
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In many locations clouds can greatly reduce the
available peak sun hours, sometimes for days at a time
As a minimum the average peak sun hours must at
least meet the average load
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Peak sun hours and perhaps the load have a seasonal
dependence
Sufficient storage is needed to supply full load at times
when the sun isn’t available
Probabilistic depending on location – how likely is a
string of low sun days
Inverter and battery efficiencies need to be considered
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Estimating Storage Needs
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Common PV System Usage:
Pumping Water
PV systems are widely used for pumping water,
particularly in developing countries; if water is stored,
when it is pumped does not much matter
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PV Powered Water Pumping
http://www.rajkuntwar.com/html/Solar.html
http://www.oksolar.com/pumps/
http://solar-investment.us/solar-pv-surface-and-bore-waterpumping/
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DC Motors
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DC motors have a magnetic field produced in the
stator, and then some mechanism to change the current
flow in the rotor (armature) (either brushes or
electronic)
Advantages include high starting torque and speed
control over a wide of values
Disadvantages include higher initial cost and the need
for a dc source
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A luxury car may have more than 100 dc motors
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DC Motors
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Main types are based on how the stator is powered:
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Separately excited (separate windings)
Permanent magnet
Shunt connection (field winding is in parallel with the
armature); these motors have near constant speed
regardless of load
Series connection (field winding is in series with
armature); these motors have high torque at low speed,
but can have high speed with low torque
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Separately Excited DC Motor
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The equations are:
v f  if Rf  Lf
di f
dt
dia
va  ia Ra  La
 Gmi f
dt
In steady-state (our
concern) the derivatives
are zero; if a permanent
magnet then Gif is a
replaced by a constant k
With a shunt
configuration,
vf = va
Image Source: M.A. Pai, Power Circuits and Electromechanics, Stipes Publishing, 2007
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Torque, Speed and Voltage
Relationships
• For a permanent magnetic dc machine in steadystate we get
va  ia Ra  km
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If Ra were zero then speed only depends on voltage
Power to motor is
va  km
Pmotor  km ia  a  km
Ra
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Motor torque is Tmotor 
Pmotor
m
va  km
k
 k ia
Ra
Motor will not start until solar PV has enough current so
torque is high enough to overcome static friction
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Permanent Magnet DC Motor
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DC Motor I-V Curve
Linear Current
Booster (LCB) helps
the motor be able to
start in low sunlight
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Hydraulic Pumping Curves
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For pumping, the two key values are head, H (height
water is pumped), and flow rate, Q (rate at which
water is pumped)
Mechanical power is then
Pmech   HQ
Pmech (W )  0.1885  H ( ft )  Q ( gal / min)
Pmech (W )  9.81  H (m)  Q( L / s )
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Required electrical power depends on the efficiency
0.1885  H ( ft )  Q ( gal / min)
Pelec (W ) 
Efficiency
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Example: Energy to Pump Water
from Shallow Well
• How many kWh/day are required to pump 250
gallons/day with a 66 ft head, assuming 35% efficiency?
With efficiency given, the below equation works for any rate, so
calculate power required if the 250 gallons is pumped in one hour
0.1885  H ( ft )  Q( gal / min)
Cost is
Pelec (W ) 
Efficiency
higher when
250gal / day
pumping
Q( gal / min) 
 4.167 gal / min
into a
60 min/ day
pressure
0.1885  66  4.167
Pelec (W ) 
 148 W (for one hour) tank (1 psi
0.35
= 2.31 ft)
Cost is about $0.02 or
Answer  0.148 kWh
$0.08 per 1000 gallons
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