Transcript Ch 19
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Correction to Problem 19.6:
Part (a) asks you to derive expression for Voc and Isc in terms of the
variables F = fs / finf, Vg, n = Cs / Cp, and Rinf. There is a square root
missing from Rinf, i.e. it should read
R
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L
Cs C p
Chapter 19: Resonant Conversion
A series resonant link inverter
Same as dc-dc series resonant converter, except output rectifiers are
replaced with four-quadrant switches:
i(t)
+
L
dc
source +
–
vg (t)
Cs
v(t)
R
–
Switch network
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Resonant tank network
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Switch network
Low-pass ac
filter
load
network
Chapter 19: Resonant Conversion
19.4.4 Design Example
Select resonant tank elements to design a resonant inverter that meets the
following requirements:
• Switching frequency fs = 100 kHz
• Input voltage Vg = 160 V
• Inverter is capable of producing a peak open circuit output voltage
of 400 V
• Inverter can produce a nominal output of 150 Vrms at 25 W
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Solve for the ellipse which meets requirements
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Calculations
The required short-circuit current can be found by solving the elliptical
output characteristic for Isc:
hence
Use the requirements to evaluate the above:
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Solve for the open circuit transfer function
The requirements imply that the inverter tank circuit have an open-circuit
transfer function of:
Note that Voc need not have been given as a requirement, we can solve
the elliptical relationship, and therefore find Voc given any two required
operating points of ellipse. E.g. Isc could have been a requirement
instead of Voc
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Solve for matched load
(magnitude of output impedance )
Matched load therefore occurs at the operating point
Hence the tank should be designed such that its output impedance is
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Solving for the tank elements
to give required ||Zo0|| and ||Hinf||
Let’s design an LCC tank network for this example
The impedances of the series and shunt branches can be represented by
the reactances
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Analysis in terms of Xs and Xp
The transfer function is given by the voltage divider equation:
The output impedance is given by the parallel combination:
Solve for Xs and Xp:
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Analysis in terms of Xs and Xp
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||Hinf||
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||Zo0||
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||Zo0||
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Analysis in terms of Xs and Xp
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Chapter 19: Resonant Conversion
Analysis in terms of Xs and Xp
The transfer function is given by the voltage divider equation:
The output impedance is given by the parallel combination:
Solve for Xs and Xp:
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Chapter 19: Resonant Conversion
Evaluate tank element values
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Discussion
Choice of series branch elements
The series branch is comprised of two elements L and Cs, but there is only
one design parameter: Xs = 733 Ω. Hence, there is an additional
degree of freedom, and one of the elements can be arbitrarily chosen.
This occurs because the requirements are specified at only one operating
frequency. Any choice of L and Cs, that satisfies Xs = 733 Ω will meet
the requirements, but the behavior at switching frequencies other than
100 kHz will differ.
Given a choice for Cs, L must be chosen according to:
For example, Cs = 3Cp = 3.2 nF leads to L = 1.96 mH
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Rcrit
For the LCC tank network chosen, Rcrit is determined by the parameters of
the output ellipse, i.e., by the specification of Vg, Voc, and Isc. Note that
Zo is equal to jXp. One can find the following expression for Rcrit:
Since Zo0 and H are determined uniquely by the operating point
requirements, then Rcrit is also. Other, more complex tank circuits may have
more degrees of freedom that allow Rcrit to be independently chosen.
Evaluation of the above equation leads to Rcrit = 1466 Ω. Hence ZVS for
R < 1466 Ω, and the nominal operating point with R = 900 Ω has ZVS.
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Chapter 19: Resonant Conversion
Ellipse again with Rcrit, Rmatched, and Rnom
Showing ZVS and ZCS
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Chapter 19: Resonant Conversion
Converter performance
For this design, the salient tank frequencies are
(note that fs is nearly equal to fm, so the
transistor current should be nearly
independent of load)
The open-circuit tank input impedance is
So when the load is open-circuited, the transistor current is
Similar calculations for a short-circuited load lead to
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Extending ZVS range
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Extending ZVS range
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Extending ZVS range
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Dynamic Modeling and Analysis
of Resonant Inverters
Closed-loop control
system to regulate
amplitude of ac output
(Lamp ballast example
shown, but other
applications have similar
needs) (frequency
modulation control shown)
Issues for design of closed-loop
resonant converter system:
• Need open-loop control-to-output
transfer function to model loop gain,
closed-loop transfer functions
• How does control-to-output transfer
function depend on the tank transfer
functionofH(s)?
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Power Electronics
Chapter 19: Resonant Conversion
Sinusoidal steady-state resonant inverter behavior
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Chapter 19: Resonant Conversion
Dynamic analysis of resonant inverters
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DC gain of control-to-output envelope transfer function
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Spectrum of v(t)
The control input is varied at
modulation frequency fm
Spectrum
of v(t)
This leads to sidebands at
frequencies fs ± fm (true for both
AM and narrowband FM)
Carrier (s witching)
frequency
Sideband
fs – fm
The spectrum of v(t) contains
no component at f = fm.
Sideband
fs
fs + f m
frequency
Effect of the tank transfer function H(s) on the output:
• Changing the amplitude of the carrier affects the steady-state output amplitude
• Changing the amplitudes of the sidebands affects the ac variations of the
output amplitude— i.e., the envelope
• The control-to-output-envelope transfer function Genv(s) depends on the tank
transfer function H(s) at the sideband frequencies fs ± fm. It doesn’t depend on
H(s) at f = fm.
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How frequency modulation of tank input voltage introduces
amplitude modulation of output envelope
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Poles of Genv(s)
Example:
Spectrum
of v(t)
Carrier (s witching)
frequency
H(s) has resonant poles at f = fo
Sideband
These poles affect the sidebands
when fs ± fm = fo
fs – fm
Sideband
fs
fs + f m
frequency
Tank
H(s)
Hence poles are observed in
Genv(s) at modulation frequencies
of fm = fs – fo
fo
Genv(s)
fs – fo
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fm
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Outline of discussion
DIRECT MODELING APPROACH
1. How small-signal variations in the switching frequency affect the
spectrum of the switch network output voltage vs1(t)
2. Passing the frequency-modulated voltage vs1(t) through the tank
transfer function H(s) leads to amplitude modulation of the output
voltage v(t)
3. How to recover the envelope of the output voltage and determine the
small-signal control-to-output-envelope transfer function Genv(s)
PHASOR TRANSFORMATION APPROACH
1. Equivalent circuit modeling via the phasor transform
2. PSPICE simulation of Genv(s) using the phasor transform
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