Transcript Document

Physics 212
Lecture 12
Today's Concept:
Magnetic Force on moving charges
F  qv  B
Physics 212 Lecture 12, Slide 1
Main Point 1
First, we introduced some observations involving forces exerted by bar magnets
and between current carrying wires to indicate the existence of a new kind of
phenomena in the world that we call magnetism
Physics 212 Lecture 12, Slide 2
Main Point 2
Second, we made the claim that all magnetic effects can be described in terms of a
magnetic field that is created by the motion of electric charges, i.e., electric
currents.
Physics 212 Lecture 12, Slide 3
Main Point 3
Third, these magnetic fields exert forces on electric charges that are in motion.
We introduced the mathematical form for this force in terms of a cross product of
vectors. In particular, the magnetic force on charge q moving with velocity v
through a region containing a magnetic field B is given by qv cross B.
Physics 212 Lecture 12, Slide 4
Magnetic Observations
• Bar Magnets
N
S
N
S
S
N
N
S
• Compass Needles
N
S
Magnetic Charge?
N
07
S
cut in half
N
S
N
S
Physics 212 Lecture 12, Slide 5
Magnetic Observations
• Compass needle deflected by electric current
I
• Magnetic fields created by electric currents
• Magnetic fields exert forces on electric currents (charges in motion)
V
V
I
F
F
I
F
I
I
F
V
12
Physics 212 Lecture 12, Slide 6
Magnetism & Moving Charges
All observations are explained by two equations:
F  qv  B
0 I ds  rˆ
dB 
2
4 r
14
Today
Next Week
Physics 212 Lecture 12, Slide 7
Cross Product Review
• Cross Product different from Dot Product
– A●B is a scalar; A x B is a vector
– A●B proportional to the component of B parallel to A
– A x B proportional to the component of B perpendicular to A
• Definition of A x B
– Magnitude: ABsinq
– Direction: perpendicular to plane defined by A and B with sense given
by right-hand-rule
16
Physics 212 Lecture 12, Slide 8
Checkpoint 1a
Three points are arranged in a uniform magnetic
field. The B field points into the screen.
1) A positively charged particle is located at point A and is stationary.
The direction of the magnetic force on the particle is:
A
B
C
D
E
18
Physics 212 Lecture 12, Slide 9
Physics 212 Lecture 12, Slide 10
Checkpoint 1b
Three points are arranged in a uniform magnetic
field. The B field points into the screen.
A
B
C
D
E
21
1) A positively charged particle is located at point A and is stationary.
The direction of the magnetic force on the particle is:
Physics 212 Lecture 12, Slide 11
Physics 212 Lecture 12, Slide 12
Cross Product Practice
F  qv  B
• protons (positive charge) coming out of screen
• Magnetic field pointing down
• What is direction of force on POSITIVE charge?
A) Left
-x
B) Right
+x
C) UP
+y
D) Down
-y
E) Zero
y
x
B
24
z
Physics 212 Lecture 12, Slide 13
Motion of Charge q in Uniform B Field
• Force is perpendicular to v
– Speed does not change
– Uniform Circular Motion
• Solve for R:
F  qv  B  F  qvB
x vx x x x x x
q
x R x x x x vx x
x x x Fx x x x
q
F
F
q
x x xF x x x x
xv x x x x x x
q
x x x x xv x x
Uniform B into page
Demo
30
Physics 212 Lecture 12, Slide 14
Checkpoint 2a
The drawing below shows the top view
of two interconnected chambers. Each
chamber has a unique magnetic field. A
positively charged particle is fired into
chamber 1, and observed to follow the
dashed path shown in the figure.
A
B
C
D
.
B
34
Physics 212 Lecture 12, Slide 15
Physics 212 Lecture 12, Slide 16
Checkpoint 2b
The drawing below shows the top view
of two interconnected chambers. Each
chamber has a unique magnetic field. A
positively charged particle is fired into
chamber 1, and observed to follow the
dashed path shown in the figure.
A
B
C
36
Physics 212 Lecture 12, Slide 17
Physics 212 Lecture 12, Slide 18
Calculation
A particle of charge q and mass m is accelerated
from rest by an electric field E through a
distance d and enters and exits a region
q,m
containing a constant magnetic field B at the
points shown. Assume q,m,E,d, and x0 are known.
x0/2
E
d
enters here
What is B?
exits here
XXXXXXXXX
X X X X X X X X X x0
XXXXXXXXX
XXXXXXXXX
B
B
• Conceptual Analysis
–
What do we need to know to solve this problem?
(A) Lorentz
ForceLaw

 
( F  qv  B  qE )
(B) E field definition
(C) V definition
(D) Conservation of Energy/Newton’s Laws
(E) All of the above
Physics 212 Lecture 12, Slide 19
Physics 212 Lecture 12, Slide 20
Physics 212 Lecture 12, Slide 21