Transcript Review - ND

Orbital velocity
What is the orbital velocity of a
geostationary satellite?
We know that the period is 24 h
and that the satellite is in orbit around
the earth.
Solve for r first, then find v.
F cent = Fgrav for anything in orbit
4 2 m 2 r
Gm1m 2
=
T2
r2
r
3
Gm1T 2
4 2
-11
24
2
(6.67
x
10
)(5.98
x
10
)(24
x
3600)
r 3
4 2
r  4.9114 x 107 m
2 r
v=
T
2 x 4.9114 x 107
v=
24 x 3600
m
v = 3.57 x 103
s
curve banking
• What normal force will a 60.0 kg woman feel while traveling at 25.0
m/s on the booster-bike through a 50.0 m circular arc, with a
banking of 40.0o? How many times her normal weight is this?
Fcent
FN 
,
sin
F cent
mv 2
=
r
mv 2
FN 
sin r
40o
FN
Fgrav
Fcent
40o
60(25)2
FN 
sin(40o ) 50
FN  1166.79 N
1166.79
= 1.98 x her normal weight
60 x 9.81
Kepler
• An asteroid of frozen water
and dirt in the Kuiper belt
passes close to Neptune
and is pulled from its orbit
towards Neptune.
• A) What will happen if this
asteroid misses Neptune but
continues to travel towards
the sun?
The asteroid will become a
comet in a highly elliptical
orbit around the sun.
Kepler
• How fast will the asteroid be traveling as it reaches its perigee just
inside of Mercury if its apogee is just beyond Neptune where its
velocity is 5.412 km/s?
r1
v 22
= 2
r2
v1
v 2p
ra
= 2
rp
va
vp =
ra va2
rp
vp =
2.83 x 1013 (5.412 x 103 ) 2
3.60 x 1011
vp = 4.80 x 104
m
s
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