Work and Energy
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Transcript Work and Energy
Work and Energy
Physics
Mr. Day
Work
Work
- the product of the magnitudes of
the component of a force along the
direction of displacement and the
displacement
W = F d
Work
– Push a chair from rest to a velocity
Not
Work
– Hold a book in the air
– Carry a chair across the room at a constant
velocity
Work (cont.)
Work
is only done when the
components of a force are parallel to a
displacement
d
F
W=Fd
•All of the force is acting on the box
d
F
W = F d cos
•Only the horizontal component of the
force does work
Sign Convention for Work
Visual Concept
F
Work (cont.)
d
• Examples
W = F d cos
d
W = F d cos
W = F d cos 90
W=0
F
d
F
F
d
W = F d cos
W = F d cos
W = F d cos 0
W= F d
Work (cont.)
Units
–Fd=W
– N m = Joule (J)
Work
is a scalar quantity
– Work can be positive or negative
• Positive Work - Force and displacement are in the
same direction
• Negative Work - Force and displacement are in
opposite directions
Work Defined
Video
EX: A 20.0 kg suitcase is raised 3.0 m above a
platform by a conveyor belt. How much work is
done on the suitcase
m = 20.0 kg
d = 3.0 m
W=Fd
W = (m a) d
W = (20.0 kg)(9.8 m/s2)(3.0 m)
W = 588 J
EX: A person drags a suitcase with a
100.0 N force at an angle of 60.0° for
200.0 m. How much work does she do?
F
d
F = 100.0 N
= 60.0°
d = 200.0 m
W = F d cos
W= (100.0 N)(200.0 m) cos 60°
W = 10,000 J
W = 1.0 X 104 J
Types of Energy
Video
Energy
Kinetic
Energy - the energy of an object
due to its motion
– Depends on speed and mass
– KE = 1/2 m v2
– Units Joules (J)
Potential
Energy - energy associated
with an object due to its position
– Units Joules (J)
Kinetic and Potential Energy
Video
Kinetic Energy
Visual Concept
EX: A 6.0 kg cat runs after a mouse at
10.0 m/s. What is the cat’s kinetic
energy?
mc = 6.0 kg
vc = 10.0 m/s
KEc = 1/2 mc vc2
KEc = 1/2 (6.0 kg)(10.0 m/s)2
KEc = 300 J
EX: If a .10 kg mouse runs as fast as the
cat, what is its kinetic energy?
mm = .10 kg
vm = 10.0 m/s
KEm = 1/2 mm vm2
KEm = 1/2 (.10 kg)(10.0 m/s)2
KEm = 5 J
EX: A 24 kg dog begins to chase the cat
and has the same kinetic energy as the
cat. What is the dog’s velocity?
md = 24 kg
KEd = 300 J
KEd = 1/2 md vd2
vd = √(2 Ked / md)
vd = √(2 (300 J) / 24 kg)
vd = 5.0 m/s
Potential Energy
Gravitational
Potential Energy potential energy associated with an
object due to its position relative to
Earth or some other gravitational source
PEg = m g h
Elastic
Potential Energy - the potential
energy in a stretched or compressed
elastic object
– Spring
– Rubber band
Potential Energy
Visual Concept
Elastic Potential Energy
The
length of a spring when no external
forces are acting on it is called the relaxed
length
PEe = 1/2 k x2
– PEe = 1/2 (spring constant)(distance stretched
or compressed)2
Spring
constant - a parameter that
expresses how resistant a spring is to being
compressed or stretched
Elastic Potential Energy
Spring Constant
spring constant stiff spring
Low spring constant flexible spring
k = F / d
High
– Units N / m
Spring Constant
Visual Concept
EX: When a 2.00 kg mass is attached to a
vertical spring, the spring is stretched 10.0 cm
so the mass is 50.0 cm above the table.
m = 2.00 kg
x = 10. cm = .10 m
h = 50.0 cm = .50 m
A. What is the gravitational potential energy
associated with the mass relative to the table?
m = 2.00 kg
x = 10. cm = .10 m
h = 50.0 cm = .50 m
PEg = mgh
PEg = (2.00 kg)(9.8 m/s2)(.50 m)
PEg = 9.8 J
B. What is the elastic potential energy if the
spring constant is 400.0 N/m?
m = 2.00 kg
x = 10. cm = .10 m
h = 50.0 cm = .50 m
k = 400.0 N/m
PEe = 1/2 k x2
PEe = 1/2 (400.0 N/m)(.10m)2
PEe = 2.00 J
C. What is the total potential energy of the
system?
m = 2.00 kg
x = 10. cm = .10 m
h = 50.0 cm = .50 m
k = 400.0 N/m
∑PE = PEg + PEe
∑PE = 9.8 J + 2.00 J
PEe = 11.8 J
Mechanical Energy
There
are many types of energy
associated with a system
– Kinetic
– Gravitational potential
– Elastic potential
– Chemical
– Thermal
• Most can be ignored because they are
negligible or not relevant
Mechanical Energy
Mechanical
energy - the sum of the
kinetic and all forms of potential energy
ME = ∑KE + ∑PE
All other forms of energy are classified
as non-mechanical energy
Conservation of Energy
Conserve
means it remains the same
Conservation of mechanical energy
MEi = MEf
∑KEi + ∑PEgi + ∑PEei = ∑KEf + ∑PEgf + ∑PEef
In
the presence of friction, energy is “lost” to
heat energy
Niagara Falls and Energy
Transformation
Video
Conservation of Mechanical
Energy
Visual Concept
Energy of a roller coaster
As the roller coaster falls the energy is transformed
from potential energy to kinetic energy
The energy is then transferred back into potential
energy, etc.
Energy is a sling shot
It starts with elastic potential energy
It quickly transfers into kinetic energy
As the height increases it transfers into gravitational
energy
As it falls the energy transfers into kinetic energy
EX: A small 10.0 g ball is held to a slingshot that
is stretched 6.0 cm. The spring constant of the
band on the slingshot is 2.0 X 102 N/m.
A. What is the elastic potential energy of the
slingshot before it is released
m = 10.0 g = .0100 kg
x = 6.0 cm = .06 m
k = 2.0 X 102 N/m
PEe = 1/2 k x2
PEe = 1/2 (2.0 X 102 N/m)(.06 m)2
PEe = .36 J
B. What is the kinetic energy of the ball just after
the slingshot is released?
MEi = MEf
∑KEi + ∑PEgi + ∑PEei = ∑KEf + ∑PEgf + ∑PEef
∑PEei = ∑KEf
.36 J = ∑KEf
C. What is the balls speed at the instant it
leaves the slingshot?
KEf = 1/2 m v2
v = √ (2KEf / m)
v = √(2(.36 J) / (.01 kg))
v = 8.5 m/s
D. How high would the ball travel if it were shot
directly upward?
MEi = MEf
∑KEi + ∑PEgi + ∑PEei = ∑KEf + ∑PEgf + ∑PEef
∑KEi = ∑PEgf
.36 J = ∑PEf
PEf = mgh
h = PEf / mg
h = .36 J / ((.01 kg)(9.8 m/s2))
h = 3.7 m
Work and Energy
Work-kinetic
energy theorem - the net
work done on an object is equal to the
change in the kinetic energy of the
object
Wnet = ∆ KE
Wfriction = ∆ ME
Work Kinetic Energy Theorem
Visual Concept
Potential Energy is transferred into Kinetic Energy
Next the change in the Kinetic Energy is equal to the
net work
Stopping Distance
If an object
has a
higher
kinetic
energy,
more work
is required
to stop the
object
Ex: On a frozen pond, a person kicks a 10.0 kg
sled, giving it an initial speed of 2.2 m/s. How far
does it travel if the coefficient of kinetic friction
between the sled and the ice is .10?
vi
W = ∆KE
µk = Fk / FN
F d = KEf - KEi Fk = µk (-mg)
µk (-mg) d = 1/2 m vf2 - 1/2 m vi2
µk (-mg) d = - 1/2 m vi2
m = 10.0 kg
d = (- 1/2 m vi2) / µk (-mg)
vi = 2.2 m/s
d = (- 1/2 (10.0 kg) (2.2 m/s)2) /
vf = 0 m/s
(.10 (-10.0 kg) (9.8 m/s2))
µk = .10
d = 2.47 m
EX: A 10.0 kg shopping cart is pushed
from rest by a 250.0 N force against a
50.0 N friction force over 10.0 m distance.
m = 10.0 kg
vi = 0
Fp = 250.0 N
Fk = 50.0 N
d = 10.0 m
FN
Fp
Fk
Fg
A. How much work is done by each force
on the cart?
Wg = 0
WN = 0
Wp = Fp d cos
Wp = (250.0 N)(10.0 m)cos 0
Wp = 2500 J
Wk = Fk d cos
Wk = (50.0 N)(10.0 m)cos 180
Wk = -500 J
B. How much kinetic energy has the cart
gained?
Wnet = ∆KE
Wp + Wk = KEf - KEi
2500 J + -500 J = KEf - 0
KEf = 2000J
C. What is the carts final speed?
KE = 1/2 m v2
v = √((2KE)/(m))
v = √((2(2000 J))/(10.0 kg))
v = 20 m/s
Power
Power
- the rate at which energy is
transferred
P = W / ∆ t
– Units J / s watt (w)
Since
P = W / ∆ t and W = F d;
– P = F d / ∆ t P = F (d / t)
–P=Fv
Horsepower
is another unit of power
– 1 hp = 746 w
Power Defined
Video
Power
Visual Concept
EX: A 100.0 N force moves an object 20.0
m in 5.0 s. What is the power?
F = 100.0 N
d = 20.0 m
F = 100.0 N
d = 20.0 m
t = 5.0 s
P = F (d / t)
P = 100.0 N (20.0 m / 5.0 s)
P = 400 w
EX: Two horses pull a cart. Each exerts a
250 N force at a 2.0 m/s speed for 10.0
min.
Fh1 = 250 N
Fh2 = 250 N
v = 2.0 m/s
v = 2.0 m/s
∆ t = 10.0 min
F = 250 N
= 600 s
F = 250 N
A. Calculate the power delivered by the
forces.
Ph1 = Fh1 v
Ph1 = (250 N)(2.0 m/s)
Ph1 = 500 w
Ph2 = Fh2 v
Ph2 = (250 N)(2.0 m/s)
Ph2 = 500 w
∑P = Ph1 + Ph2
∑P = 500 w + 500w
∑P = 1000 w
B. How much work is done by the two
horses?
P=W/∆t
W=P∆t
W = (1000 w)(600 s)
W = 6.0 X 105 J
Work Cited
Sources
– www.classroomphysics.com
– www.clipart.com
– Holt Physics
– United Streaming