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Solving Force
Probmems
Physics
Mr. Maloney
Objectives
You will be able to
diagram Force problems
use FBDs to analyze and solve force
problems.
© 2002 Mike Maloney
“Picturing Force”
Free-Body Diagrams
Free
Body Diagrams are vector
diagrams.
We use them to graphically depict what
is acting on an object.
They represent the magnitude and
direction of all forces acting on an
object.
© 2002 Mike Maloney
Free Body
Diagrams
LET’S IDENTIFY SOME
The
diagram at right
shows all the forces
acting on this object.
Here we have Gravity, a Frictional
Force, an Applied Force, and a
Normal Force.
Objects can have any number of
forces acting on them, depending on
the situation.
© 2002 Mike Maloney
Balanced Forces (Statics) (N1L)
There
are often situations where a
number of forces are acting on something,
and the object has no motion –
it is STATIC or in EQUILIBRIUM.
This means the NET FORCE on the object
is zero, or in other words the forces
balance each other out.
What does this mean mathematically?
© 2002 Mike Maloney
unBalanced Forces
(Dynamics) (N2L)
There
are other situations where all the
forces acting on something do not cancel
each other out completely.
This means the NET FORCE on the object
is not zero, the object will change its motion
and accelerate proportional to the object’s
mass.
F = m ∙ a
Let’s try one of these.
© 2002 Mike Maloney
Solving Strategy
1.
2.
3.
4.
5.
6.
7.
Determine whether it is a static problem or a
dynamic problem if you can.
Sketch a Free Body diagram.
Draw and label vectors representing all forces.
Pick an “X” and “Y” direction. If there is any
motion, you should choose either X or Y to be in
the direction of motion.
Break forces into components if necessary
Sum the forces (F) in the X and Y directions, and
set them equal to either 0 or m∙a accordingly.
(If you are unsure, use m∙a)
Use the summation equations (F) you have
created to solve for unknown values.
Lets go back and try a few more.
© 2002 Mike Maloney
More Advanced Problems
There
are usually many types of forces
acting on objects where friction and motion
is occurring.
They can either be parallel to the motion,
or perpendicular to it.
This next example has a block on a table
where there is friction and an applied force
at an angle.
© 2002 Mike Maloney
Advanced Problems
FN
Ff
surface
FAy
FAx
Fg
What forces are acting parallel to the surfaces?
block
FA
The horizontal (x) part of the Applied Force {FA}, and
the Friction Force {Ff}
What about Perpendicular?
The vertical (y) part of the Applied force {FA}, the
Weight {Fg} and the Normal force {FN}
© 2002 Mike Maloney
Advanced Problems
FN
Ff
surface
block
FA
FAy
FAx
Fg
We
see that an applied force can be
applied at any angle. So it may act
perpendicular and/or parallel to the
motion.
© 2002 Mike Maloney
Advanced Problems
FN
Ff
surface
block
FA
FAy
FAx
Fg
However FN is always perpendicular to the
motion.
Ff is always parallel to the motion.
By the Way, what
On a flat surface Fg is perpendicular,
butis
we saw
how it can be both on an
incline.
wrong
with this Free
Each problem has to be looked at and analyzed
Body Diagram?
individually.
So lets try some.
© 2002 Mike Maloney
Block on hill
Let’s go back to a block just sitting on a track.
What happens when I slant the track?
The cart starts to move. I did not change any
of the forces acting on the cart … so what
changed?
© 2002 Mike Maloney
Objectives
Can you …
diagram Force problems
use FBDs to analyze and solve force
problems.
© 2002 Mike Maloney
APPENDIX
© 2002 Mike Maloney
Net Force
NET FORCE refers to the vector sum total
of all forces acting on an object. It is often
expressed as F
For example, if there were two leftward forces
of 10 lb each, the NET FORCE would be 20
lb leftward.
If there were one 10 lb rightward force and
one 8 lb leftward force, the NET FORCE
would be 2 lb rightward.
What about if the forces were in X and Y?
BACK
© 2002 Mike Maloney
Static problem
Static
problems are associated with
Newton’s 1st Law.
Static problems are problems in which
the net force is ZERO (0).
In this case the sum of the forces in the
X-direction and the Y-direction are both
ZERO (0).
BACK
© 2002 Mike Maloney
dynamic problem
Dynamic
problems are associated
with Newton’s 2nd Law.
Dynamic problems are problems in
which the net force is not ZERO.
In this case the sum of the forces in the
X-direction and/or the Y-direction are
not always zero, and may result in some
acceleration.
BACK
© 2002 Mike Maloney
x/y Components
If
the forces are acting in more than 2
directions (i.e. applied force at an angle)
break all the forces down into vertical
and horizontal components or parallel
and perpendicular components using
vector rules (sine and cosine).
Once they are broken up, you can Fx
and Fy to solve for the unknowns.
BACK
© 2002 Mike Maloney
1.
A
book is at rest on a table top.
FN
Fg
BACK TO LECTURE
© 2002 Mike Maloney
2.
A
girl is suspended motionless in the air
by two ropes attached to her.
FT
FT
BACK TO LECTURE
Fg
© 2002 Mike Maloney
3.
An
egg is free-falling from a nest in a
tree. Neglect air resistance.
Fg
BACK TO LECTURE
© 2002 Mike Maloney
4.
A
flying squirrel is gliding (no wing flaps)
from a tree to the ground at constant
velocity. Consider air resistance.
FAIR
BACK TO LECTURE
Fg
© 2002 Mike Maloney
5.
A rightward force is applied to a book in order
to move it across a desk with a rightward
acceleration. Consider frictional forces.
Neglect air resistance.
FN
FA
Ff
BACK TO LECTURE
Fg
© 2002 Mike Maloney
6.
A rightward force is applied to a book in order
to move it across a desk at constant velocity.
Consider frictional forces. Neglect air
resistance.
FN
FA
Ff
BACK TO LECTURE
Fg
© 2002 Mike Maloney
7.
A college student rests a backpack upon his
shoulder. The pack is suspended motionless
by one strap from one shoulder.
FA
BACK TO LECTURE
Fg
© 2002 Mike Maloney
8.
A
skydiver is descending with a
constant velocity. Consider air
resistance.
FAIR
Fg
BACK TO LECTURE
© 2002 Mike Maloney
9.
A
force is applied to the right to drag a
sled across loosely-packed snow with a
rightward acceleration.
FN
FA
Ff
BACK TO LECTURE
Fg
© 2002 Mike Maloney
10.
A
football is moving upwards towards its
peak after having been booted by the
punter. Neglect air resistance.
Fg
BACK TO LECTURE
© 2002 Mike Maloney
11.
Three smaller kids are pulling a rope against one
large kid.
A. They are at a stand still
B. The big kid is winning
BACK TO LECTURE
© 2002 Mike Maloney
11.
Three smaller kids are pulling a rope against one
large kid.
A. They are at a stand still
B. The big kid is winning
BACK TO LECTURE
© 2002 Mike Maloney
11.
Three smaller kids are pulling a rope against one
large kid.
A. They are at a stand still
B. The big kid is winning
BACK TO LECTURE
© 2002 Mike Maloney
12.
A
car is coasting to the right and
slowing down.
FN
Ff
BACK TO LECTURE
Fg
© 2002 Mike Maloney
13.
Mr.
M is holding a book against a flat
wall.
Ff
FA
FN
Fg
BACK TO LECTURE
© 2002 Mike Maloney