Unit 4 Nature_Of_Matter
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Transcript Unit 4 Nature_Of_Matter
Physics 30 Unit 4 Review
The Nature of Matter
and Radioactivity
The Nature of Matter
Atomic Theories:
indivisible part of
The Greeks: The atom is the smallest, ____________
an element that can still be called an element.
Thomson:
negative
โขDiscovered that the electron has a _____________
charge
charge to mass
and also found the ____________________
ratio of the
electron.
cathode ray
โขHe performed his experiments with ____________________
tubes.
raisin bun
โขHis model of the atom is called the _________________
model.
Formulas:
CRT
x x x
x x x
Fm = Fc
2
mv
qvB =
r
q
v
=
m Br
Remember:
F = ma
2
v
ac=
r
mv2
Fc= r
Mass Spectrometer:
Velocity Selector
Perpendicular Electric
and Magnetic fields
+
Charged
particles
X
X
X
๐ธ=๐ธ
1
๐๐ = ๐๐ฃ 2
2
X
X
X
X
X
X
X
X
X
X
X
X
_
If accelerated by a potential
difference then the
formulas are:
Ion Separator
Just a magnetic or
electric field
If the particles travel
through undeflected, then
the formulas are:
๐น๐ = ๐น๐
๐๐ฃ๐ต = ๐ธ ๐
Formulas are:
๐น๐ = ๐น๐
๐๐ฃ 2
๐๐ฃ๐ต =
๐
Properties of Cathode Rays:
โขCathode rays have the same properties no matter which
metal
type of ____________
is used for the cathode.
straight
โขCathode rays travel in ______________
lines.
electric
E
โขCathode rays can be bent in both _________________
magnetic B
and ___________________
fields.
โขCathode rays can cause chemical reactions similar to
light
_______________
(develop photographic film).
โขCathode rays leave a vapour trail when they pass through
gas chamber
bubble chamber
a _________________
as well as a ___________________.
electrons
โขCathode rays are ________________.
Thomson Example:
A negatively charged particle is travelling with a speed of
1.43x106 m/s through a magnetic field of 2.50x10-3 T. The
particle follows a curved path of radius 3.25x10-3 m. What is
the charge to mass ratio of this particle?
Fm = Fc
mv2
qvB = r
6 m/s
q
v
1.43x10
=
m = Br
(2.5x10-3 T) (3.25x10-3 m)
= 1.76x1011 C/kg
Millikanโs Oil Drop Experiment:
negatively charged oil drops between
โขHe balanced ______________
electric plates. When the particles were suspended, the
electric
gravitational force.
____________
force equaled the _____________
+ plate
Fe
- Oil drop
Fg
- plate
Millikanโs Oil Drop Experiment (Formulas):
โขIf the oil drop is suspended: โขIf the oil drop accelerates up:
Fe = Fg
E q = mg
โขIf the oil drop moves with a
constant speed up or down:
Fe = Fg
E q = mg
Fe = Fg + Fa
E q = mg + ma
โขIf the oil drop accelerates down:
Fe = Fg - Fa
E q = mg - ma
Millikanโs Oil Drop Experiment (Graphing):
โขOil drops of different weights are suspended between electric
plates requiring different electric field strengths
Millikanโs Oil Drop Experiment (Graphing):
Line of best fit should:
โข Average the data points the best
โข Go through as many points as possible
โข You can leave some points above
and below the line.
Weight of Oil
Drops
(x10?? N)
Slope Calculation:
Electric Field Strength
(x10?? N/C)
Fe = Fg
E q = mg
mg
= q = eE
โข Try not to choose data points
โข Choose points as far apart
as possible
Rutherfordโs Scattering Experiment:
Rutherfordโs Planetary Model:
scattering
โขRutherford performed a ______________
experiment.
alpha
โข____________
particles were aimed at a layer of thin gold.
photographic film.
โขThe particles were detected by ______________
โขHe concluded that the nucleus is:
tiny
โขVery ____________
positive
protons
โขContains ________________
charges called __________.
electrons orbit the nucleus like planets orbit the sun.
โข__________
Rutherfordโs Planetary Model (Formulas):
electric
โขThere is an _______________
force between the
negative
positive
__________electrons
and __________protons.
This is because
opposite
______________
charges attract.
โขSince this force acts inwardly as the electron travels around
centripetal force.
the nucleus, it is also equal to the ____________
Example: Calculate the speed of the electron as it orbits the
nucleus of a hydrogen atom if itโs orbital radius is 5.29x10-7m.
Fe = Fc
kqq = mv2
r
r2
9 )(1.6 × 10โ19 )(1.6 × 10โ19 )
(8.99
×
10
v=
= 2.19x104m/s
โ7
โ31
5.29 × 10 (9.11 × 10 )
Maxwellโs Problem:
โขAccording to Maxwell, any accelerating charge produces
light (c)
_____________
which travels at the speed of ___________.
EMR
โขThis can be shown with symbols:
โ ฮ
ฮ๐ต
โ ฮ
โขSince the electron in an atom is traveling in a circular path (itโs
direction
_____________
is always changing) it can be considered to be
accelerating even though itโs speed is constant.
โขThe electrons within atoms are accelerating charged particles.
EMR
They should give off _____________
(a form of energy) as they
travel. They should thus lose energy and collapse into the atom.
Bohr Model of the Atom:
โขWithin certain orbitals (a certain distance from the nucleus),
EMR
electrons are free to travel without giving off any ___________.
energy
โขThese orbitals are also called ___________
levels. The lowest
ground
energy level (closest to the nucleus) is called a ______________
state. The energy required to free the electron from the atom
ionization
is called the _______________
energy.
EMR
โขWhen electrons drop energy levels, they give off ___________.
When electrons move up energy levels, they have either been hit
by an ___________
electron or an ______________.
EMR photon
Formulas used with the Bohr Model:
โ๐๐ก ๐๐ฆ ๐๐ ๐ โ
or photon
๐ธ๐๐
๐๐๐ฃ๐๐ ๐๐๐
positive
negative
โขEnergy levels can be written as ____________
or ____________
numbers.
subtract
โข_____________
the energy levels to find the energy difference
between orbitals.
EMR Formulas
๐=
โ๐
๐
๐ = โ๐
e- Formulas
๐ = ๐๐
1
๐ = m๐ฃ 2
2
Hydrogen Atom:
โขIf the electron drops to the first (lowest) orbital, then
ultraviolet
_______________
is most likely released.
โขIf the electron drops to the second orbital, then
visible light
_______________
is most likely released.
โขIf the electron drops to the third orbital, then
infrared
_______________
is most likely released.
Continuous Spectra:
โขLight from a hot glowing solid (like an incandescent light bulb)
will produce a continuous spectrum in the visible region.
Prism
White light
Diffraction Grating
๐
o
y
g
b
i
v
White light
๐
v
๐ฃ
r
Smaller wavelengths (blue) light is
refracted more.
Longer wavelengths (red) light is
diffracted more.
Blue bends more.
Think of the sky โ itโs blue because
the red light light is diffracted more.
Emmission Spectra:
electrons
โขLight from an excited elemental gas (excited by ___________
passing through it) will emit certain wavelengths of light. If this
bright
light is passed through a diffraction grating, a ______________
line pattern will be produced. Each element has a
unique
_____________
pattern.
Absorption Spectra:
โขWhen light passes through a cool elemental gas, certain
wavelengths of light are absorbed. These will appear as
______________
dark
_________
lines on a spectrum.
Example:
What is the wavelength of EMR released when an electron within
an atom drops from an energy level of 12.0 eV to 8.5 eV?
E= 12.0 eV โ 8.5 eV = 3.5 eV
๐ธ=
โ๐
๐
๐=
โ๐
๐ธ
(4.14 × 10โ15 )(3.00 × 108 )
๐=
3.5๐๐
๐ = 3.55 × 10โ7 m
Compton Effect:
โขHe performed a scattering experiment where EMR
photons
(___________)
were fired at electrons. He found that the
electrons moved off with speed after the collision and that the
longer
scattered x-rays had a ______________
wavelength.
โขHe concluded that EMR can have a mass property:
momentum
___________________.
โขMomentum formula for masses:
โขMomentum formula for EMR:
โขThe biggest angle an x-ray can
be scattered is straight back
180o
_________
๐ = ๐๐ฃ
๐=
โ
๐
ฮ๐ =
โ
(1
๐๐
๐ธ = ๐๐
โ ๐๐๐ ๐)
Example:
An X-Ray of wavelength 0.0500 nm scatters at an angle of 300.
Calculate the wavelength of the scattered photon.
30o
ฮ๐ =
โ
(1
๐๐
ฮ๐ =
6.63×10โ34
(9.11×10โ31 )(3.00×108 )
โ ๐๐๐ ๐)
(1 โ ๐๐๐ 30)
ฮ๐ = 3.25 × 10โ13 m
๐๐ = ๐๐ + ฮ๐ = 0.0500 × 10โ9 + 3.25× 10โ13 = 5.03× 10โ11 ๐
de Broglie Wavelength:
โขProposed that masses can have an EMR property:
wavelength
___________.
โขObjects with mass and speed travel with a ______________.
wavelength
The effect is only detectable for very small masses traveling at
high speed. The formula below should be given to you on a
diploma exam.
๐๐๐๐ ๐ ๐๐ = ๐๐ธ๐๐
๐๐ฃ =
๐=
โ
๐
6.63 × 10โ34
โ
๐๐ฃ
๐๐๐ ๐ ๐๐๐ ๐ ๐๐๐๐ ๐๐ ๐กโ๐ ๐๐๐๐ก๐๐๐๐
Example:
Calculate the wavelength of an electron that has been
accelerated through a potential difference of 2 000 V using the
de Broglie wavelength formula ๐ = โ
๐๐ฃ
๐=
6.63×10โ34
9.11×10โ31 (??)
๐= ๐
1
๐๐ฃ 2 = ๐๐
2
๐ = 2.75 × 10โ11 ๐
๐ฃ=
๐ฃ=
2๐๐
๐
2(2000๐)(1.6 × 10โ19 )
9.11 × 10โ31
๐ฃ = 2.65 × 107
Electron Orbitals:
โขElectrons really travel in a ____________
pattern as they
wave
travel around the nucleus of the atom.
โขThere must be a whole number multiple of wavelengths as
nucleus
the electron orbits the ___________.
๐๐ = 2๐๐
You do not have to memorize
this formula for the diploma.
The Standard Model of the Atom:
โขParticles responsible for Forces are called
boson
______________
particles.
Boson
โข______________
particles responsible for the following
Forces (listed from strongest to weakest):
โขThe strong nuclear force: __________________
gluons
โขThe electromagnetic force: __________________
photons
โขThe weak nuclear force: __________________
W+ W- Zo
graviton
โขThe gravitational force: __________________
(undetected)
The Standard Model of the Atom:
โขParticles that make up matter are called ______________.
fermions
โขVery small particles that are elementary particles are
leptons
called ___________________.
The electron and itโs
leptons
neutrino are _________________.
โขLarger particles, like neutrons and protons are called
hadrons
___________________.
They are made up of
quarks
___________________.
โข_____________
are made up of 2 quarks.
Mesons
โข_____________
baryons
are made up of 3 quarks.
The Standard Model of the Atom:
uud
โขProtons are made up of the following quarks: _____________
1
n
0
1
+
p
1
0๐ฝ
-1
+
๐
udd
โขneutrons are made up of the following quarks: _____________
1
p
1
1
+
n
0
0๐ฝ
1
+
๐
Radioactivity:
half
โขParticles that undergo radioactive decay, lose __________
their
mass over a certain period of time. This time is called
half life
_________________.
โขDuring this process, a radioactive element changes into
another element, giving off particles or EMR. This is
called __________________.
transmutation
โขFormulas:
Graphing Radioactivity:
Bq
โขRadioactivity has lots of different units: __________,
Bq/s
rads
decays / s
___________,
____________,
______________
to list a few.
Terms:
neutron or a proton
Nucleon: __________________________
number of protons (bottom number)
Atomic Number: _______________
The atomic number identifies the element.
number of protons and neutrons (top number)
Mass Number: _______________
the sum of the top numbers on both
Conservation of Nucleons: _____________________________
___________________________________________________
sides of an equation must be equal.
the sum of the bottom numbers on
Conservation of Charge: _____________________________
___________________________________________________
both sides of an equation must be equal.
3 Types of Radioactivity:
1. Beta Decay: assume beta negative for just โbeta decayโ
Beta Negative Decay: is an _________________.
electron
0๐ฝ
๐-1
-1
symbols are: __________________
๐
an antin-eutrino is also released _________.
Example: Write the decay equation for carbon 14 emitting a
beta negative particle.
14
c
6
14
+
N
7
0๐ฝ
-1
+
๐
3 Types of Radioactivity:
Beta Positive Decay: is an _____________________________.
antimater electron (positron)
0
1๐ฝ
symbols are: __________________
๐
a neutrino is also released __________.
Example: Write the decay equation for carbon 14 emitting a
beta positive particle.
14
c
6
14
+
B
5
0๐ฝ
1
+
๐
3 Types of Radioactivity:
2. Alpha decay: is the nucleus of a ____________
helium
atom.
4 2+
4
2+
Symbols are: ___________________
2๐ผ
2๐ป๐
Example: Write the decay equation for nitrogen 15 emitting an
alpha particle.
15
7๐
4 2+
2๐ผ
+
11
5๐ต
3 Types of Radioactivity:
3. Gamma decay: is a high energy, high ____________,
frequency small
wavelength
______________
EMR photon.
0
๐พ
Symbol is: __________________
0๐พ
Example: Write the decay equation for cobalt 56 emitting a
gamma ray.
56
27๐ถ๐
๐พ +
56
27๐ถ๐
Penetrating Ability:
In order of increasing ability to penetrate objects:
thick paper or cardboard
Alpha particles: ___________________
Beta particles: ___________________
thin metal
lead (dense metal)
Gamma Rays: __________________________
Ability to Ionize (danger / risk):
In order of increasing risk:
higher energy due to increased speed
Beta particles: __________________________
higher energy due to larger mass
Alpha particles: __________________________
higher energy due to larger frequency
Gamma Rays: __________________________
or smaller wavelength
Binding Energy:
neutrons of an atom to hold
โขIs the energy exerted by the ___________
the ______________
charged protons tightly in the nucleus.
positively
โขSome mass of the ___________
neutrons
is converted into energy.
โขFormula:
Example: The mass of a lithium-7 nucleus is 7.015989 u.
Whatโs the binding energy?
7
Li
3
3๐+ = 3(1.6726 × 10โ27 ๐๐)
4๐ = 4(1.6749 × 10โ27 ๐๐)
1.17174 × 10โ26 ๐๐
7.015989๐ข (1.66 × 10โ27 ๐๐/๐ข) = 1.16465417× 10โ26 ๐๐
1.17174 × 10โ26 โ 1.16465417 × 10โ26 = 7.08583 × 10โ29
๐ธ = ๐๐ 2 = 7.08585 × 10โ29 3.00 × 108
2
= 6.38 × 10โ12 ๐ฝ
Nuclear Fission:
splitting
โขIs the ____________
of an atom into other elements.
nuclear
โขIs the process used in ________________
power plants.
โขFormula:
Example: Calculate the energy produced in the following fission reaction.
235
1
U + 0n
235
140
U=3.9029x10-25 kg
1
-27
0n =1.6749x10
kg
140
Xe=2.3234x10-25 kg
94
Sr =1.5595x10-25 kg
Xe +
94
Sr
1
+ 2 0n Mass of reactants 3.919649 × 10โ25
Mass of products 3.916398 × 10โ25
Mass difference
3.251 × 10โ28
Binding Energy E=mc2
3.251 × 10โ28 (3.00 × 108 )2
2.9259 × 10โ11 ๐ฝ
Nuclear Fusion:
โขIs the ____________
fusing
of simpler atoms into heavier elements.
sun
โขIs the process going on inside the ________________.
โขFormula:
Example: Calculate the energy produced in the following fusion reaction.
2
1
3
H + 1H
4
2
2
-27 kg
1 H=3.4444x10
1
-27 kg
0n =1.6749x10
4
He =6.6463x10-27 kg
3
H
1
=5.0082x10-27 kg
1
He + 0n
Mass of reactants 8.4526 × 10โ27
Mass of products 8.3212 × 10โ27
Mass difference
1.314 × 10โ28
Binding Energy E=mc2
1.314 × 10โ28 (3.00 × 108 )2
1.1826 × 10โ11 ๐ฝ