Transcript Chapter 22
Chapter 22
Magnetism (Lecture II)
Dr. Jie Zou
PHY 1161
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Outline
Motion of charged particles in a
magnetic field
Magnetic force on a current-carrying
wire
Electric current and magnetic fields
Magnitude of the magnetic field of a
current-carrying wire
Solenoids
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The Motion of Charged
Particles in a Magnetic Field
The electromagnetic flowmeter
The operating
principle of a mass
spectrometer
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The Magnetic Force on a
Current-Carrying Wire
Magnitude of the magnetic
force on a current-carrying wire
Direction of the magnetic force
on a current-carrying wire
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F = ILBsin
I: Current in the wire (A); L:
Length of the wire (m); B:
Magnetic field (T); : The angle
between the direction of the
magnetic field and the current.
Given by the same Magnetic
Force RHR for charges
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Example 22-4: Magnetic Levity
A copper rod 0.150 m long
and with a mass of 0.0500
kg is suspended from two
thin, flexible wires. At right
angles to the rod is a
uniform magnetic field of
0.550 T pointing into the
page.
Dr. Jie Zou
Find the direction and
magnitude of the electric
current needed to levitate
the copper rod.
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Electric Current and Magnetic
Fields
The source of any
magnetic field is the
motion of electric
charge.
Magnetic field produced
by a straight and
infinitely long currentcarrying wire:
Dr. Jie Zou
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The magnetic field
“circulates” around the
wire.
Find the direction of the
magnetic field using the
magnetic field RHR.
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Conceptual Checkpoint 22-5
The magnetic field
shown in the sketch is
due to the horizontal,
current-carrying wire.
Dr. Jie Zou
Does the current in the
wire flow to the left or
to the right?
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Magnitude of the Magnetic Field
of a Current-Carrying Wire
Magnitude of the magnetic
field, B, produced by a straight
and infinitely long currentcarrying wire:
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B = (0I)/(2r)
0 = 4 x 10-7 Tm/A, the
permeability of free space.
The field doubles if the current I
is doubled; the field halves if the
distance from the wire, r, is
doubled.
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Example 22-6: An Attractive
Wire
A 52-C charged particle
moves parallel to a long wire
with a speed of 720 m/s.
The separation between the
particle and the wire is 13
cm, and the magnitude of
the force exerted on the
particle is 1.4 x 10-7 N.
Dr. Jie Zou
Find the magnitude of the
magnetic field, B.
Find the current in the wire, I.
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Solenoids
A solenoid carrying a current
produces an intense, nearly
uniform magnetic field inside the
loops.
Magnitude of the magnetic field
inside a solenoid:
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A solenoid is also called an
electromagnet.
The magnetic field inside the
solenoid is directed along its axis.
The field outside the solenoid is
almost zero.
B = 0 (N/L) I = 0 nI
n: the number of loops per unit
length
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Example 22-7: Through the
Core of a Solenoid
A solenoid is 20.0 cm long,
has 200 loops, and carries
a current of 3.25 A.
Dr. Jie Zou
Find the magnitude of the
force exerted on a 15.0-C
changed particle moving at
1050 m/s through the
interior of the solenoid, at
an angle of 11.5° relative to
the solenoid’s axis.
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Homework #7
Chapter 22, P. 793-795, Problems: #31,
33, 49, 57 (Physics, Walker, 4th edition).
Dr. Jie Zou
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