Transcript lecture19

Chapter 16
Capacitors
Batteries
Parallel Circuits
Series Circuits
Friday, February 26, 1999
in class
Ch. 15 - 16
Hint: Be able to do the homework (both the
problems to turn in AND the recommended ones)
you’ll do fine on the exam!
You may bring one 3”X5” index card (hand-written
on both sides), a pencil or pen, and a scientific
calculator with you.
2
1
Q
1
2
W  U  QV 
 CV
2
2C 2
U = INTERNAL ENERGY of the capacitor.
This is where the energy comes from to
power many of our cordless, rechargeable
devices…When it’s gone, we have to plug
the devices into the wall socket to recharge
the capacitors!
Just so you know...
Insulating materials between capacitor plates are
known as dielectrics. In the circuits we have dealt
with, that material is air. It could be other insulators
(glass, rubber, etc.).
Dielectric materials are characterized by a dielectric
constant k such that when placed between the plates
of a capacitor, the capacitance becomes
C = k Co
Co is the vacuum (air) capacitance.
Dielectrics, therefore, increase the charge a
capacitor can hold at a given voltage, since...
Q = C V = k Co V
k Co
Current and Resistance
It’s time to develop an understanding of
electrical systems that are NOT in electrostatic
equilibrium. In these systems, charges move,
under the influence of an externally imposed
electric fields. Such systems provide us with
the useful electricity we get out of flashlight
batteries and rechargeable devices.
We’ve already used this concept, even though
we haven’t formally introduced it.
What do you think of when you hear
the word “current?”
Electrical Current is simply the
flow of electrical charges.
charge carriers
moving charges.
can be + or -
A
The current is the number
of charges flowing
through a surface A per
unit time.
Q
I
t
Q
I
t
By convention, we say that
the direction of the current
is the direction in which the
positive charge carriers
move.
Note: for most materials we examine, it’s
really the negative charge carriers that move.
Nevertheless, we say that electrons move in
a direction opposite to the electrical current.
Leftover from Ben Franklin!
Why do charges move?
Well, what happens when you put an
electric field across a conductor?
E
electrical force on the charges in the conductor.
charges can move in conductors.
a current flows!
Vd t
E
A
The charge carriers, each with charge q, move with
v
an average speed d in response to the electric field.
If there are n charge carriers per volume in the
conductor, then the number of charge carriers
passing a surface A in a time interval t is given by
Q  nqAvd t
Q
I
 nqAvd
t
Electric fields exert an electrical force on
charges given by


F  qE
And I remember from last semester that


Newton’s 2nd Law says
F  ma
So shouldn’t the charges be accelerating
instead of moving with an average velocity
vd?
Let’s follow the path of one of the charge
carriers to see what’s really going on...
Vd t
E
A
The thermal motion of the charges in the conductor keep the
charges bouncing around all over the places, hitting the
fixed atoms in the conductor.
The electric field exerts a force which “gently” guides the
positive charges toward the right so that over time, they
appear to drift along the electric field.
You might think of the collisions as a frictional force
opposing the flow generated by the electric field.
You are probably asking yourself, “So, just
how long does it take the average electron to
traverse a 1m length of 14 gauge copper wire if
the current in the wire is 1 amp?
How long does it take the average
electron to traverse a 1m length of
14 gauge copper wire if the current
in the wire is 1 amp?
Let’s try to guess first:
a) years
b) weeks
c) days
d) hours
e) minutes
f) seconds
g) microseconds
h) nanoseconds
14 gauge wire is a common size of wire
having a radius of 0.0814 cm
Let’s assume that atom of copper is able to
supply one free charge to the current.
The mass density of copper is 8.92 g/cm3
1 mole of copper weighs 63.5 g.
So, the number density of charge carriers in
the copper is...
n
(6.02  10
23 atoms
mol
g
mol
(635
.
)(8.92
)
g
cm3
)
n = 8.46 X 1022 atoms/cm3
Q
I
 nqAvd
t
I
vd 
nq A
q = 1.6 X 10-19 C
A = p r2 = 2.1 X 10-2 cm2
1A
vd 
22 chgs
19
(8.46  10
.  10
3 )(16
C
chg
cm
2
)(2.1  10 cm )
3 cm
s
vd  355
.  10
d
100 cm
4
t

 2.8  10 s
3 cm
vd 355
.  10 s
t = 7.8 hours!
2
Describes the degree to which a current
through a conductor is impeded.
In particular, if a voltage V is applied
across a conductor, a current I will flow.
The resistance R is defined to be:
R=V/I
R=V/I
[R] = [V] / [I]
[R] = Volt / Amp
= Ohm (W)
Georg Ohm (early 19th century) systematically
examined the electrical properties of a large
number of materials. He found that the
resistance of a large number of objects is NOT
dependent upon the applied voltage. That is...
V=IR
The objects for which Ohm’s Law
holds are known as OHMIC.
Objects for which resistance
IS a function of the applied
voltage (i.e., Ohm’s Law is
invalid) are known as NON-OHMIC.
V
Slope = R
I
V
I
Every material has its own characteristic
resistivity to the conduction of electric charge.
On what does the Resistance (R) of an
object depend? (OHMIC CONDUCTORS)
length
cross-sectional area
R~L
Certainly, if two wires
have the same crosssectional area, the longer
of the two will have the
greater resistance.
For two wires of the same
length, the one with the
larger cross-sectional area
will have the smaller
resistance. Think of water
flowing in a pipe.
R~1/A
So if we plotted the resistance (R) versus the
ratio of the length (L) to the cross-sectional
area (A)
R
L/A
We define the slope to be the
resistivity (r) of the material.
R=rL/A
The proportionality constant, r, is the resistivity.
r=RA/L
[r] = [R] [A] / [L]
= W m2 / m
=Wm
Resisitivity and Resistance are also a
function of Temperature.
r = ro [ 1 + a ( T - To) ]
R = Ro [ 1 + a ( T - To) ]
To is usually taken to be 20o C.
a is the temperature coefficient of resistivity
and is a characteristic of the particular
material.
The temperature dependence of
resistance holds for everyday to
warm temperatures.
At very low temperatures, for some materials, the
resistance can fall to zero. These materials are
known as superconductors.
The temperature at
which their resistance
falls off rapidly is
known as the critical
temperature.
R
Tc
T
Charge
Insulators/Conductors
Coulomb’s Law
Electric Fields
Potentials & Potential Energy
Capacitors
Series & Parallel Circuits
+
Two Kinds of Charge
-
Charge is Quantized
An electron carries a charge of -1e.
A proton carries a charge of +1e.
1e = 1.6 X 10-19 C
Conservation of Charge.
RUBBER
The charges remain
near the end of the
rubber rod--right
where we rubbed
them on!
GROUND
COPPER
Rub charges on here
They move down the
conductor toward our hand
Eventually ending up in the ground.
GROUND
Rubber
COPPER
Bring negatively charged
rubber ball close to the a
copper rod. The copper
rod is initially neutral.
Negative charges on the copper run
away from the rubber ball and into the
ground.
GROUND
Rubber
+
++
COPPER + The copper rod is now
+
positively charged. The
+
electrons originally on it
+
were forced away into the
ground by the negative
charges on the rubber
ball.
GROUND
Rubber
+
++ Finally, remove the
COPPER +
+
rubber ball...
+
+
Put a rubber glove on
your hand to insolate the
copper rod from ground.
GROUND
The excess positive
charge is trapped on
the copper rod with
+
no path to ground. It
COPPER + +
+
redistributes itself
+
uniformly over the
+
+
copper rod. We have taken
an initially neutral copper
rod and induced a positive
charge on it!
GROUND
Electrostatic Forces

kq 1q 2

F
r
2
r
k = 9 X 109 N m2/C2
Superposition Principle

kq
E = 2 r
r
superposition principle applies
So….

 

Etotal  E1  E2  E3 ...


F = qE
+
Field lines
Far apart.
-
Field lines
close together.
Work in a UNIFORM electric field
W=qEd
Scalar quantity!
No directions!
Electrical work is “Quite Easily Done!”
NOTE: d is the distance along
the Electric field only!!!
r
q
d
E
As long as the
electric field
is uniform, this
is the answer!
PE = -W = -q E d
The Electrical Potential:
V = Vb-Va = PE/q
In a uniform field
V = - E d,
Wilbur!
It’s EASY!
+q
Va
E
d
Vb
Vb - Va = - E d
It decreases in the direction of the electric field,
REGARDLESS OF THE SIGN OF THE CHARGE!
The electrical potential ALWAYS
decreases in the direction of the
electric field! It does not depend
upon the sign of the charge.
The electrical potential energy
depends upon the sign of the charge.
It decreases in the direction of the
electrical force.
-q
A
Fe
d
B
E
What happens to the potential energy of a
negative charge (-q) as it moves in the
direction of the electric field?
PE = - q E d = - (-q) E d = + q E d
-q
A
Fe
B
d
E
What happens to the potential of a negative
charge (-q) as it moves in the direction of the
electric field?
V = - E d
For point
charges
The superposition
principle applies to
potentials!
kq
V
r
Vtot = V1 + V2 + V3 + ...
Electrostatic Potential Energy
kq 1q 2
PE 
r
Equipotential surfaces are perpendicular to
the electric field lines everywhere!
Work is only done when a charge moves
parallel to the electric field lines.
So no work is done by the electric field as
a charge moves along an equipotential
surface.
When in electrostatic equilibrium (i.e.,
no charges are moving around), all
points on and inside of a conductor
are at the same electrical potential!
Insulators and Conductors
1) no electric field exists inside conductor.
2) Excess charges on an isolated
conductor are found entirely on its
surface.
3) The electric field just outside of a
conductor must be perpendicular
to the surface of the conductor.
Capacitors
C = eoA/d
C=Q/V
eo = permittivity of free space
= 8.85 X 10-12 C2/Nm2
2
1
Q
1
2
W  U  QV 
 CV
2
2C 2
+
V
_
Ceq = C1 + C2
C1
Capacitors in parallel ADD.
+
1
Ceq
C2
=
+Q -Q
C1, V1
V
_
1
C1
C2
+
1
+Q
C2, V2
-Q
Capacitors in series
ADD INVERSELY.