Transcript PAPER 2 SECTION A

PAPER 2
SECTION A
ZULAILI BT YAACOB
QUESTION 4
WHICH CHAPTER ?
WHICH PRINCIPLE OR LAW
HOW MANY MARK /S
EXPLAIN : WHY
1 – PRESSURE INVERSELY PROPORTIONAL TO VOLUME
2 – PRESSURE AT SURFACE IS DECREASES, VOLUME OF
AIR IS INCREASES
BOYLE’S LAW
Fresh water replace by higher density?
Density higher  pressure higher ( P = ρgh)
Pressure higher  volume less
The volume will decreases at R.
An air bubble of volume 5 cm3 is released by an air pump
at depth of 0.5 m.
Calculate the volume of the air bubble when it reaches
the surface of the water.
[ Assume that the atmospheric pressure is 10 m water ]
EXTRACT INFORMATION FROM QUESTION :
V1 = 5 cm 3 , depth = 0.5 m, atm pressure = 10 m
P 1 V 1 = P2 V2
V2 = (P 1 V 1) / P2
Depth = 0.5, atm pressure 10 m
 P1 = 0.5 + 10

= 10.5 m
P2 = 10 m
V2 = ( 5 x 10.5) / 10
= 5.25 cm3
WHICH CHAPTER ?
Forces and motion
Observed diagram
Info from diagram :
High ram , low ramp
Graph of velocity vs time
Quantity by the gradient
Velocity  ms-1
Time
s
Unit  ms-2
acceleration
Comparing gravitational potential energy :
The gravitational potential energy in diagram 5.1 is
higher compare to diagram 5.2
Comparing velocity :
Velocity of diagram 5.1 is greater compare to diagram 5
Comparing kinetic energy:
Kinetic energy of diagram 5.1 is higher compare to 5.2
Relationship between gravitational energy and
kinetic energy
When the gravitational energy increases, the
kinetic energy increases
Physics concept :
Conservation of energy
Skate from Z to Q
Velocity decreases
Kinetic energy at Z > Kinetic energy at Q
Q = mcθ
Need Q more
High
low
Meaning :
The amount of energy needed to increase the
temperature of 1 kg material
by 10 C or 1 K
Cooking rapidly : material :
copper
Spesific capacity low
Material for handle :
polymer
insulator
Mass of the pot :
Low mass
Easy to carry
•The pot are heated by using an electric hot plate of power 800 W.
Based on the information in table 8 , calculate the time to achieve
a temperature rise of 900 for :
Extract information from given statement.
P = 800 W, m = 3.5, θ = 900
Pt = mc θ
t = (mc θ)
P
354.4 s / 5.91 min
109.7 s / 1.83 min
PAPER 2 SECTION B
Weight : Force exerted on every object
Compare weight of the boy with his father :
The weight of his father is greater than the boy
The volume of water displaced :
The volume of water displaced by ball B is
greater than ball A
The buoyant force acted on them
The buoyant force acted on the father is greater
than the boy
Relationship buoyant force and volume of water displaced
When the water displaced increases, the buoyant force
increases
Relationship buoyant force and weight of water displaced
When the weight of water displaced increases, the
buoyant force increases
Archimedes principle
Bouyant force
increases
when the volume of
Immersed wooden
block
increases
Wooden block moving up
when
Buoyant force > weight
B . F equals to weight,
the wooden block is
floating
Explain why the wooden block moves upwards and then floats on the
water surface
Design a raft to accommodate 15 participant and able to move quickly
Aspects
Suggestions
reasons
Shape of the raft
streamline
Reduce water
resistance
Material for the raft
Low density
Can float easily
Bigger size
Can accommodate all
participant
Size of the raft
Design of the raft
Layers of bamboo
Higher buoyant force
Attach big fan / motor
/wide sail
Increase the speed