sy15_mar09_10
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Goals:
Lecture 15
• Chapter 11
Employ the dot product
Employ conservative and non-conservative forces
Use the concept of power (i.e., energy per time)
• Chapter 12
Extend the particle model to rigid-bodies
Understand the equilibrium of an extended object.
Understand rigid object rotation about a fixed axis.
Employ “conservation of angular momentum” concept
Assignment:
HW7 due March 10th
For Thursday: Read Chapter 12, Sections 7-11
do not concern yourself with the integration process in
regards to “center of mass” or “moment of inertia”
Physics 207: Lecture 15, Pg 1
Scalar Product (or Dot Product)
A B A B cosq
Useful for finding parallel components
A î = Ax
îî=1
îĵ=0
A
ĵ
q Ay
î Ax
Calculation can be made in terms of
components.
A B = (Ax )(Bx) + (Ay )(By ) + (Az )(Bz )
Calculation also in terms of magnitudes and relative angles.
A B ≡ | A | | B | cos q
You choose the way that works best for you!
Physics 207: Lecture 15, Pg 2
Work in terms of the dot product
Ingredients: Force ( F ), displacement ( r )
Work, W, of a constant force F
acts through a displacement r :
F
W F cosq r F r
q
r
F dr
Looks just like a Dot Product!
If the path is curved dW
and
r
W F dr
F dr at each point
f
ri
Physics 207: Lecture 15, Pg 4
Energy and Work
Work, W, is the process of energy transfer in which a
force component parallel to the path acts over a
distance; individually it effects a change in energy
of the “system”.
1. K or Kinetic Energy
2. U or Potential Energy (Conservative)
and if there are losses (e.g., friction, non-conservative)
3. ETh Thermal Energy
Positive W if energy transferred to a system
Physics 207: Lecture 15, Pg 6
A child slides down a playground slide at
constant speed. The energy transformation
is
A.
B.
C.
D.
E.
UK
U ETh
KU
K ETh
There is no transformation because
energy is conserved.
Physics 207: Lecture 15, Pg 7
Exercise
Work in the presence of friction and non-contact forces
A box is pulled up a rough (m > 0) incline by a rope-pulley-
weight arrangement as shown below.
How many forces (including non-contact ones) are
doing work on the box ?
Of these which are positive and which are negative?
State the system (here, just the box)
Use a Free Body Diagram
Compare force and path
v
A. 2
B. 3
C. 4
D. 5
Physics 207: Lecture 15, Pg 8
Work and Varying Forces (1D)
Area = Fx x
F is increasing
Here W = F · r
becomes dW = Fx dx
Consider a varying force F(x)
Fx
xf
W
x
x
Fx ( x ) dx
xi
Finish
Start
F
F
q = 0°
x
Work has units of energy and is a scalar!
Physics 207: Lecture 15, Pg 9
•
Example: Hooke’s Law Spring (xi equilibrium)
How much will the spring compress (i.e. x = xf - xi) to bring
the box to a stop (i.e., v = 0 ) if the object is moving initially at a
constant velocity (vi) on frictionless surface as shown below
with xi = xeq , the equilibrium position of the spring?
xf
Wbox
ti vi
Fx ( x ) dx
xi
xf
m
Wbox
- k ( x xeq ) dx
xi
spring at an equilibrium position
x
Wbox
V=0
t
F
Wbox
m
2
- 2 k ( x f xi ) 2 k 0 K
1
2
1
2
- 2 k x 2 m0 2 mvi
1
spring compressed
xf
- 2 k ( x xi ) |
xi
1
2
1
2
1
Physics 207: Lecture 15, Pg 10
2
Work signs
ti vi
Notice that the spring force is
opposite the displacement
m
spring at an equilibrium position
x
For the mass m, work is negative
V=0
t
F
For the spring, work is positive
m
spring compressed
They are opposite, and equal (spring is conservative)
Physics 207: Lecture 15, Pg 11
Conservative Forces & Potential Energy
For any conservative force F we can define a potential energy
function U in the following way:
W =
F ·dr ≡ - U
The work done by a conservative force is equal and opposite to
the change in the potential energy function. r
U
f
ri
f
Ui
Physics 207: Lecture 15, Pg 12
Conservative Forces and Potential Energy
So we can also describe work and changes in
potential energy (for conservative forces)
U = - W
Recalling (if 1D)
W = Fx x
Combining these two,
U = - Fx x
Letting small quantities go to infinitesimals,
dU = - Fx dx
Or,
Fx = -dU / dx
Physics 207: Lecture 15, Pg 13
Exercise
Work Done by Gravity
An frictionless track is at an angle of 30° with respect to the
horizontal. A cart (mass 1 kg) is released from rest. It slides
1 meter downwards along the track bounces and then
slides upwards to its original position.
How much total work is done by gravity on the cart when it
reaches its original position? (g = 10 m/s2)
30°
(A) 5 J
(B) 10 J
(C) 20 J
h = 1 m sin 30°
= 0.5 m
(D) 0 J
Physics 207: Lecture 15, Pg 14
A Non-Conservative Force
Path 2
Path 1
Since path2 distance >path1 distance the puck will be traveling
slower at the end of path 2.
Work done by a non-conservative force irreversibly removes
energy out of the “system”.
Here WNC = Efinal - Einitial < 0 and reflects Ethermal
Physics 207: Lecture 15, Pg 19
Work & Power:
Two cars go up a hill, a Corvette and a ordinary
Chevy Malibu. Both cars have the same mass.
Assuming identical friction, both engines do the same
amount of work to get up the hill.
Are the cars essentially the same ?
NO. The Corvette can get up the hill quicker
It has a more powerful engine.
Physics 207: Lecture 15, Pg 20
Work & Power:
Power is the rate at which work is done.
Average
Power:
P
W
t
Instantaneous
Power:
P
dW
Units (SI) are
Watts (W):
1 W = 1 J / 1s
dt
Example:
A person, mass 80.0 kg, runs up 2 floors (8.0 m). If
they climb it in 5.0 sec, what is the average power
used?
Pavg = F h / t = mgh / t = 80.0 x 9.80 x 8.0 / 5.0 W
P = 1250 W
Physics 207: Lecture 15, Pg 21
Work & Power:
Power is also,
P
W
t
Fx x
t
P Fx v x
If force constant, W= F x = F ( v0 t + ½ at2 )
and
P = W / t = F (v0 + at)
Physics 207: Lecture 15, Pg 22
Exercise
Work & Power
Starting from rest, a car drives up a hill at constant
acceleration and then quickly stops at the top.
(Hint: What does constant acceleration imply?)
The instantaneous power delivered by the engine during
this drive looks like which of the following,
A. Top
time
B. Middle
C. Bottom
time
time
Physics 207: Lecture 15, Pg 23
Chap. 12: Rotational Dynamics
Up until now rotation has been only in terms of circular motion
with ac = v2 / R and | aT | = d| v | / dt
Rotation is common in the world around us.
Many ideas developed for translational motion are transferable.
Physics 207: Lecture 15, Pg 24
Rotational Variables
Rotation about a fixed axis:
Consider a disk rotating about
an axis through its center:
q
Recall :
dq
dt
2
T
(rad/s) vTangential /R
(Analogous to the linear case v
dx
)
dt
Physics 207: Lecture 15, Pg 25
Rotational Variables...
At a point a distance R away from the axis of rotation, the
tangential motion:
v=R
x (arc)
= qR
x
vT (tangential) = R
R
q
=R
aT
constant
2
(angular accelation in rad/s )
0 t
(angular v elocity in rad/s)
1
q q 0 0 t t 2 (angular position in rad)
2
Physics 207: Lecture 15, Pg 26
Lecture 15
Assignment:
HW7 due March 10th
For Thursday: Read Chapter 12, Sections 7-11
Do not concern yourself with the integration process in
regards to “center of mass” or “moment of inertia”
Physics 207: Lecture 15, Pg 28