Transcript Probability bingo

1. I am based on
uniform probability. I
am what SHOULD
happen in an
experiment.
ANSWER TO #1
Theoretical
Probability
2. I represent the set of
ALL possible outcomes of
an experiment. I can be
seen in the form of a tree
diagram, a table or even
a list.
ANSWER TO #2
Sample
Space
3. I am based on
relative frequency. I
am what actually
occurs during an
experiment.
ANSWER TO #3
Experimental
Probability
4. I am what you are
looking for in an
experiment – what you
want to happen. I am the
first part of the
probability of an event
ratio.
ANSWER TO #4
Favorable
Outcome
5. I am everything that
could happen in an
experiment. I am the
second part of the
probability of an event
ratio.
ANSWER TO #5
Possible
Outcome
6. I am the chance some
event will occur. I am the
ratio of the number of
favorable outcomes to
the number of possible
outcomes.
ANSWER TO #6
Probability
7. I am one outcome
or a collection of
outcomes in an
experiment.
ANSWER TO #7
Simple Event
8. I am an event
that consists of two
or more simple
events.
ANSWER TO #8
Compound
Event
9. I am a probability
model which assigns
equal probability to all
outcomes in an
experiment. I work with
theoretical probability.
ANSWER TO #9
Uniform
Probability
10. I am a method to
find the total number
of outcomes. I have
you multiple the total
possible outcomes for
each event together.
ANSWER TO #10
Counting
Principle
11. I am an experiment that
is designed to model the
action in a given situation.
Essentially, I am a method
of solving a problem by
conducting an experiment
that is similar to the
situation in the problem.
EXAMPLE: You flip a coin to predict if a baby will be a boy or a girl.
ANSWER TO #11
Simulation
12. I am when one event
does NOT affect the
outcome of the other. Our
probability can be
determined by multiplying
the probability of the first
event by the probability of
the second event.
ANSWER TO #12
Independent
Events
13. I am when one event
DOES affect the outcome of
the other. Our probability can
be determined by multiplying
the probability of the first
event by the probability of
the second event AFTER the
first event occurs.
ANSWER TO #13
Dependent
Events
14. There are 10 yellow,
6 green, 9 orange, and
5 red cards in a stack of
cards turned facedown.
Determine P (two yellow cards)
ANSWER TO #14
P=
𝟑
𝟐𝟗
15. There are 10 yellow,
6 green, 9 orange, and
5 red cards in a stack of
cards turned facedown.
Determine P (a red card then blue card)
ANSWER TO #15
P=0
*there are no blue cards
so it is not possible to
have both events occur.
16. What is the
theoretical probability
you will flip heads on a
coin?
ANSWER TO #16
P=
𝟏
𝟐
17. You conduct an
experiment of flipping a
coin. You flip heads twice
and tails once. What is the
experimental probability of
landing on heads?
ANSWER TO #17
P=
𝟐
𝟑
18. Use the counting
principle to help you
determine how many
different pair of shoes you
can get from a store that
has 6 different styles in 8
sizes.
ANSWER TO #18
6 styles x 8 sizes =
48 pairs of shoes
19. I consist of two events
in which either one or the
other must happen, but
they can’t happen at the
same time. The sum of
these two events is 1 or
100%.
EXAMPLE: P (blue eyes) and its complement P (not blue eyes)
ANSWER TO #19
Complementary
Events
20. What is the probability
of landing on a vowel?
ANSWER TO #20
𝟑
𝟏𝟎
P = which
is unlikely
21. Ms. Luna surveyed her
class and discovered that
30% of her students have
blue eyes. Identify the
probability of the
complement of this event.
ANSWER TO #21
P =70%
*(30% blue eyes +
70% not blue eyes
= 100%)
22. You flip a coin
and toss a cube.
What is the
probability you will
land on tails then roll
a 4?
ANSWER TO #22
P=
𝟏
𝟏𝟐
23. What do you call
the likelihood of an
event with a 50%
𝟏
or probability?
𝟐
ANSWER TO #23
As likely to
happen as not
24. A game requires players
to roll two number cubes to
move the game pieces. The
faces of the cubes are
labeled 1 through 6. What
is the probability of rolling a
2 or 4 on the first number
cube and then rolling a 5 on
the second?
ANSWER TO #24
P=
𝟏
𝟏𝟖
* Probability of the first event reduces from
2
1
to and the probability of the second
6
3
1
event is so you multiply them together to
6
1
get
18