Independence
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Transcript Independence
Marginalization & Conditioning
• Marginalization (summing out): for any sets of
variables Y and Z:
P(Y) P(Y, z) ... P(Y, z1,..., zn)
z
z 1Z
znZ
• Conditioning(variant of marginalization):
P(Y) P(Y | z )P(z )
z
Often want to do this for P(Y|X ) instead of P(Y).
P( X Y )
Recall P(Y|X ) =
P( X )
Example of Marginalization
• Using the full joint distribution
P(cavity)
P(cavity, toothache , catch)
tootachecatch
P(cavity) = P(cavity, toothache, catch) +
P(cavity, toothache, catch) +
P(cavity, toothache, catch) +
P(cavity, toothache, catch)
= 0.108 +0.012 + 0.072 + 0.008
= 0.2
Inference By Enumeration using
Full Joint Distribution
• Let X be a random variable about which we
want to know its probabilities, given some
evidence (values e for a set E of other
variables). Let the remaining (unobserved,
so-called hidden) variables be Y. The query
is P(X|e), and it can be answered using the
full joint distribution by
P( X | e) = P(X, e) = y P(X, e, y)
Example of Inference By Enumeration using Full Joint
Distribution
P(cavity | toothache ) P(cavity, toothache )
P(cavity, toothache, catch)
catch
(P(cavity, toothache , catch)
P(cavity, toothache , catch) )
(0.108 0.012)
P(cavity | toothache ) P(cavity, toothache )
P(cavity, toothache, catch)
catch
(P(cavity, toothache , catch)
P(cavity, toothache , catch) )
(0.016 0.064)
(0.108 0.012) (0.016 0.064) 1
5
P(cavity | toothache ) (0.108 0.012) 0.6
P(cavity | toothache ) (0.016 0.064) 0.4
Independence
• Propositions a and b are independent if and
only if P(a b) = P(a ) P(b)
• Equivalently (by product rule): P(a|b) = P(a )
• Equivalently: P(b| a ) = P(b)
Illustration of Independence
• We know (product rule) that
P(toothache, catch, cavity ,Weather cloudy ) =
P(Weather cloudy| toothache, catch, cavity )
P(toothache, catch, cavity ). By independence:
P(Weather cloudy| toothache, catch, cavity ) =
P(Weather cloudy ). Therefore we have that
P(toothache, catch, cavity ,Weather cloudy ) =
P(Weather cloudy ) P(toothache, catch, cavity ).
Illustration continued
• Allows us to represent a 32-element table
for full joint on Weather, Toothache, Catch,
Cavity by an 8-element table for the joint of
Toothache, Catch, Cavity, and a 4-element
table for Weather.
• If we add a Boolean variable X to the 8element table, we get 16 elements. A new
2-element table suffices with independence.
Difficulty with Bayes’ Rule with
More than Two Variables
The definition of Bayes' Rule extends naturally to
multiple variables:
P( X 1,..., Xm|Y 1,..., Yn) =
P(Y 1,..., Yn| X 1,..., Xm) P( X 1,..., Xm).
But notice that to apply it we must know conditional
probabilities like
P( y1,..., yn| x1,..., xm)
for all 2 n settings of the Ys and all 2 m settings of the Xs
(assuming Booleans). Might as well use full joint.
Conditional Independence
• X and Y are conditionally independent given
Z if and only if P(X,Y|Z) = P(X|Z) P(Y|Z).
• Y1,…,Yn are conditionally independent given
X1,…,Xm if and only if P(Y1,…,Yn|X1,…,Xm)=
P(Y1|X1,…,Xm) P(Y2|X1,…,Xm) …
P(Ym|X1,…,Xm).
• We’ve reduced 2n2m to 2n2m. Additional
conditional independencies may reduce 2m.
Conditional Independence
• As with absolute independence, the
equivalent forms of X and Y being
conditionally independent given Z can also
be used:
P(X|Y, Z) = P(X|Z)
P(Y|X, Z) = P(Y|Z)
and
Benefits of Conditional
Independence
• Allows probabilistic systems to scale up
(tabular representations of full joint
distributions quickly become too large.)
• Conditional independence is much more
commonly available than is absolute
independence.
Decomposing a Full Joint by
Conditional Independence
• Might assume Toothache and Catch are
conditionally independent given Cavity:
P(Toothache,Catch|Cavity) =
P(Toothache|Cavity) P(Catch|Cavity).
• Then P(Toothache,Catch,Cavity) =[product rule]
P(Toothache,Catch|Cavity) P(Cavity)
=[conditional independence] P(Toothache|Cavity)
P(Catch|Cavity) P(Cavity).
Naive Bayes Algorithm
Let Fi be the i-th feature having valuej and Out be the target feature.
• We can use training data to estimate:
P(Fi = v )
P(Fi = v | Out = True)
P(Fi = v | Out = False)
P(Out = True)
P(Out = False)
j
j
j
Naive Bayes Algorithm
•For a test example described by F1 = v , ..., Fn = v ,
we need to compute:
P(Out = True | F1 = v , ..., Fn = v )
Applying Bayes rule:
P(Out = True | F1 = v , ..., Fn = v ) =
P(F1 = v , ..., Fn = v | Out = True) P(Out = True)
_______________________________________
P(F1 = v , ..., Fn = v )
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1
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Naive Bayes Algorithm
•By independence assumption:
P(F1 = v , ..., Fn = v ) = P(F1 = v )x ...x P(Fn = v )
1
n
1
n
•This leads to conditional independence:
P(F1 = v , ..., Fn = v | Out = True) =
P(F1 = v | Out = True) x ...x P(Fn = v | Out = True)
1
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n
n
Naive Bayes Algorithm
P(Out = True | F1 = v , ..., Fn = v ) =
P(F1 = v | Out = True) x ...x P(Fn = v | Out = True)x
P(Out = True)
_______________________________________
P(F1 = v )x ...x P(Fn = v )
•All terms are computed using the training data!
•Works well despite of strong assumptions(see
[Domingos and Pazzani MLJ 97]) and thus provides
a simple benchmark testset accuracy for a new data
set
1
n
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Bayesian Networks: Motivation
• Although the full joint distribution can answer
any question about the domain it can become
intractably large as the number of variable
grows.
• Specifying probabilities for atomic events is
rather unnatural and may be very difficult.
• Use a graphical representation for which we
can more easily investigate the complexity of
inference and can search for efficient
inference algorithms.
Bayesian Networks
• Capture independence and conditional
independence where they exist, thus reducing
the number of probabilities that need to be
specified.
• It represents dependencies among variables and
encodes a concise specification of the full joint
distribution.
A Bayesian Network is a ...
• Directed Acyclic Graph (DAG) in which …
• … the nodes denote random variables
• … each node X has a conditional probability
distribution P(X|Parents(X)).
• The intuitive meaning of an arc from X to Y
is that X directly influences Y.
Additional Terminology
• If X and its parents are discrete, we can
represent the distribution P(X|Parents(X))
by a conditional probability table (CPT)
specifying the probability of each value of X
given each possible combination of settings
for the variables in Parents(X).
• A conditioning case is a row in this CPT (a
setting of values for the parent nodes). Each
row must sum to 1.
Bayesian Network Semantics
• A Bayesian Network completely specifies a
full joint distribution over its random
variables, as below
-- this is its meaning.
n
• P( x1,..., xn) = P( xi| Parents( Xi ))
i=1
• In the above, P(x1,…,xn) is shorthand
notation for P(X1=x1,…,Xn=xn).
Inference Example
• What is probability alarm sounds, but
neither a burglary nor an earthquake has
occurred, and both John and Mary call?
• Using j for John Calls, a for Alarm, etc.:
P( j m a b e) =
P( j| a ) P(m| a ) P(a| b e) P( b) P( e) =
(0.9)(0.7)(0.001)(0.999)(0.998) = 0.00062
Chain Rule
• Generalization of the product rule, easily
proven by repeated application of the
product rule.
• Chain Rule: P( x1,...xn) =
P( xn|xn-1,...,x1)P( xn-1|xn-2 ,...,x1)...P( x 2|x1)P( x1)
n
= P( xi|xi-1,...,xi )
i=1
Chain Rule and BN Semantics
n
BN semantics: P( x1,...,xn) = P( xi|Parents(Xi))
i=1
Key Property: P( Xi|Xi-1,...,X 1) = P( Xi|Parents(Xi))
provided Parents(Xi) X 1,...,Xi-1. Says a node is
conditionally independent of its predecessors in the
node ordering given its parents, and suggests
incremental procedure for network construction.
Example of the Key Property
• The following conditional independence
holds:
P(MaryCalls |JohnCalls, Alarm, Earthquake, Burglary) =
P(MaryCalls | Alarm)
Procedure for BN Construction
• Choose relevant random variables.
• While there are variables left:
1. Choose a next variable Xi and add a node for it.
2. Set Parents(Xi) to some minimal set of nodes such
that the Key Property (previous slide) is satisfied.
3. Define the conditional distribution P( Xi|Parents(Xi)).
Principles to Guide Choices
• Goal: build a locally structured (sparse)
network -- each component interacts with a
bounded number of other components.
• Add root causes first, then the variables that
they influence.