Transcript ACTV-LRNG-6
Active Learning Lecture Slides For use with Classroom Response Systems Probability Distributions 6.1 All students in a class were asked how many times they had read the city newspaper in the past 5 days. The data is in the chart below. What proportion read the newspaper more than 3 times in the past 5 days? a) b) c) d) e) 0.1 0.5 0.6 1.0 None of the above Copyright © 2013 Pearson Education, Inc. No. Times Read Newspaper Probability 0 0.25 1 0.05 2 0.10 3 0.10 4 0.15 5 0.35 6.1 All students in a class were asked how many times they had read the city newspaper in the past 5 days. The data is in the chart below. What proportion read the newspaper more than 3 times in the past 5 days? a) b) c) d) e) 0.1 0.5 0.6 1.0 None of the above Copyright © 2013 Pearson Education, Inc. No. Times Read Newspaper Probability 0 0.25 1 0.05 2 0.10 3 0.10 4 0.15 5 0.35 6.2 All students in a class were asked how many times they had read the city newspaper in the past 5 days. The data is in the chart below. What is the expected number of times that someone will have read the newspaper in the past 5 days? a) b) c) d) e) 2.5 2.9 3 3.9 None of the above Copyright © 2013 Pearson Education, Inc. No. Times Read Newspaper Probability 0 0.25 1 0.05 2 0.10 3 0.10 4 0.15 5 0.35 6.2 All students in a class were asked how many times they had read the city newspaper in the past 5 days. The data is in the chart below. What is the expected number of times that someone will have read the newspaper in the past 5 days? a) b) c) d) e) 2.5 2.9 3 3.9 None of the above Copyright © 2013 Pearson Education, Inc. No. Times Read Newspaper Probability 0 0.25 1 0.05 2 0.10 3 0.10 4 0.15 5 0.35 6.3 Suppose there is a special new lottery in your state. Each lottery ticket is worth $20 and gives you a chance at being selected to win $2,000,000. There is a 0.0001% chance that you will be selected and win otherwise, you win nothing. Let X denote your winnings. What is the expected value of X? a) $2 b) $0 c) $2,000,000 d) $1,999,980 e) $200 Copyright © 2013 Pearson Education, Inc. 6.3 Suppose there is a special new lottery in your state. Each lottery ticket is worth $20 and gives you a chance at being selected to win $2,000,000. There is a 0.0001% chance that you will be selected and win otherwise, you win nothing. Let X denote your winnings. What is the expected value of X? a) $2 b) $0 c) $2,000,000 d) $1,999,980 e) $200 Copyright © 2013 Pearson Education, Inc. 6.4 Suppose that a random number generator can generate any number, including decimals, between 0 and 10 with any value being equally likely to be chosen. What is the probability that a number is drawn between 7 and 10? a) 0.4 b) 0.3 c) 0.2 d) 0.1 e) 0.273 Copyright © 2013 Pearson Education, Inc. 6.4 Suppose that a random number generator can generate any number, including decimals, between 0 and 10 with any value being equally likely to be chosen. What is the probability that a number is drawn between 7 and 10? a) 0.4 b) 0.3 c) 0.2 d) 0.1 e) 0.273 Copyright © 2013 Pearson Education, Inc. 6.5 Suppose that a random number generator can generate any number, including decimals, between 0 and 10 with any value being equally likely to be chosen. What would be the mean of this distribution? a) 4.5 b) 5 c) 5.5 d) 6 e) Cannot be determined Copyright © 2013 Pearson Education, Inc. 6.5 Suppose that a random number generator can generate any number, including decimals, between 0 and 10 with any value being equally likely to be chosen. What would be the mean of this distribution? a) 4.5 b) 5 c) 5.5 d) 6 e) Cannot be determined Copyright © 2013 Pearson Education, Inc. 6.6 Which of the following is NOT a property of the normal distribution? a) It is symmetric. b) It is bell-shaped. c) It is centered at the mean, 0. d) It has a standard deviation, . e) All of the above are correct. Copyright © 2013 Pearson Education, Inc. 6.6 Which of the following is NOT a property of the normal distribution? a) It is symmetric. b) It is bell-shaped. c) It is centered at the mean, 0. d) It has a standard deviation, . e) All of the above are correct. Copyright © 2013 Pearson Education, Inc. 6.7 Scores on the verbal section of the SAT have a mean of 500 and a standard deviation of 100. Scores are approximately normally distributed. What proportion of SAT scores are higher than 450? a) 0.5 b) 0.5557 c) 0.6915 d) 0.3085 e) 0.7257 Copyright © 2013 Pearson Education, Inc. 6.7 Scores on the verbal section of the SAT have a mean of 500 and a standard deviation of 100. Scores are approximately normally distributed. What proportion of SAT scores are higher than 450? a) 0.5 b) 0.5557 c) 0.6915 d) 0.3085 e) 0.7257 Copyright © 2013 Pearson Education, Inc. 6.8 Scores on the verbal section of the SAT have a mean of 500 and a standard deviation of 100. Scores are approximately normally distributed. If someone scored at the 90th percentile, what is their SAT score? a) 608 b) 618 c) 628 d) 638 e) 648 Copyright © 2013 Pearson Education, Inc. 6.8 Scores on the verbal section of the SAT have a mean of 500 and a standard deviation of 100. Scores are approximately normally distributed. If someone scored at the 90th percentile, what is their SAT score? a) 608 b) 618 c) 628 d) 638 e) 648 Copyright © 2013 Pearson Education, Inc. 6.9 What is the standard normal distribution? a) b) c) d) e) N ( , ) N ( , ) N (1, 0) N (0,1) N ( z, z ) Copyright © 2013 Pearson Education, Inc. 6.9 What is the standard normal distribution? a) b) c) d) e) N ( , ) N ( , ) N (1, 0) N (0,1) N ( z, z ) Copyright © 2013 Pearson Education, Inc. 6.10 There are two sections of Intro Statistics and they both gave an exam on the same material. Suppose that Megan made an 83 in 2nd period and Jose made an 85 in 3rd period. Using the information below. Who scored relatively higher with respect to their own period? 2nd period 3rd period Mean 80 82 Standard Deviation 5 6 a) Jose b) Megan c) They are the same d) Cannot be determined Copyright © 2013 Pearson Education, Inc. 6.10 There are two sections of Intro Statistics and they both gave an exam on the same material. Suppose that Megan made an 83 in 2nd period and Jose made an 85 in 3rd period. Using the information below. Who scored relatively higher with respect to their own period? 2nd period 3rd period Mean 80 82 Standard Deviation 5 6 a) Jose b) Megan c) They are the same d) Cannot be determined Copyright © 2013 Pearson Education, Inc. 6.11 Which of the following is NOT a condition of the binomial distribution? a) The trials are dependent. b) There are a set number of trials, n. c) The probability of success is constant from trial to trial. d) There are two possible outcomes. Copyright © 2013 Pearson Education, Inc. 6.11 Which of the following is NOT a condition of the binomial distribution? a) The trials are dependent. b) There are a set number of trials, n. c) The probability of success is constant from trial to trial. d) There are two possible outcomes. Copyright © 2013 Pearson Education, Inc. 6.12 Suppose that you flipped an unbalanced coin 10 times. Suppose that the probability of getting “heads-up” was 0.3 and that X equals the number of times that you get “heads-up”. If X has a binomial distribution, what is the probability that X = 4? a) 0.20 b) 0.25 c) 0.30 d) 0.50 Copyright © 2013 Pearson Education, Inc. 6.12 Suppose that you flipped an unbalanced coin 10 times. Suppose that the probability of getting “heads-up” was 0.3 and that X equals the number of times that you get “heads-up”. If X has a binomial distribution, what is the probability that X = 4? a) 0.20 b) 0.25 c) 0.30 d) 0.50 Copyright © 2013 Pearson Education, Inc. 6.13 Suppose that you flipped an unbalanced coin 10 times. Suppose that the probability of getting “heads-up” was 0.3 and that X equals the number of times that you get “heads-up”. If X has a binomial distribution, what is the expected value and standard deviation of X? a) Expected value = 3 b) Expected value = 3 c) Expected value = 0.3 d) Expected value = 0.3 e) Expected value = 3 Copyright © 2013 Pearson Education, Inc. Standard Deviation = 2.1 Standard Deviation = .145 Standard Deviation = .145 Standard Deviation = 1.45 Standard Deviation = 1.45 6.13 Suppose that you flipped an unbalanced coin 10 times. Suppose that the probability of getting “heads-up” was 0.3 and that X equals the number of times that you get “heads-up”. If X has a binomial distribution, what is the expected value and standard deviation of X? a) Expected value = 3 b) Expected value = 3 c) Expected value = 0.3 d) Expected value = 0.3 e) Expected value = 3 Copyright © 2013 Pearson Education, Inc. Standard Deviation = 2.1 Standard Deviation = .145 Standard Deviation = .145 Standard Deviation = 1.45 Standard Deviation = 1.45 6.14 Suppose that a college level basketball player has an 80% chance of making a free throw. Assume that the free throws can be considered independent of each other. Suppose that he shoots 8 free throws in a game. What is his expected number of baskets? a) 0.8 b) 1 c) 6.4 d) 7.2 Copyright © 2013 Pearson Education, Inc. 6.14 Suppose that a college level basketball player has an 80% chance of making a free throw. Assume that the free throws can be considered independent of each other. Suppose that he shoots 8 free throws in a game. What is his expected number of baskets? a) 0.8 b) 1 c) 6.4 d) 7.2 Copyright © 2013 Pearson Education, Inc. 6.15 Suppose that a college level basketball player has an 80% chance of making a free throw. Assume that the free throws can be considered independent of each other. Suppose that he shoots 8 free throws in a game. What is the probability that he makes 7 baskets? a) 0.042 b) 0.167 c) 0.294 d) 0.336 e) 0.80 Copyright © 2013 Pearson Education, Inc. 6.15 Suppose that a college level basketball player has an 80% chance of making a free throw. Assume that the free throws can be considered independent of each other. Suppose that he shoots 8 free throws in a game. What is the probability that he makes 7 baskets? a) 0.042 b) 0.167 c) 0.294 d) 0.336 e) 0.80 Copyright © 2013 Pearson Education, Inc.