Transcript Document
Chapter 1
Overview of static electricity( On Electric
Force , field and Gauss’ law, Electric
potential, capacitance and dielectrics).
http://www.fayoum.edu.eg/nmh
E-Mail: [email protected]
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اجندة العام الجامعى 2014/2015
•بدء العام الدراسي السبت الموافق .2014/10/11
•اجازة راس السنة الهجرية 25/10/2014
•امتحاااا ااماااف الالااف الدراساال اتوف الساابت 22/11/2014الاال
27/11/2014
.
•امتحانات الفصل الدراسي األول من السبت 3/1/2015الى
. 22/1/2015
2
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Hrs / week
Course No
Marks
Course Title
Lect
Tut
Lab
Final
Y.Work
oral
Lab
Total
Exam
hours
GEN 110
English Language (1)
)1( لغة إنجليزية
2
-
-
40
10
-
-
50
2
GEN 113
Computational Linguistics
لغويات حسابية
2
-
-
40
10
-
-
50
2
GEN 114
Humanities
انسانيات
2
-
-
40
10
-
-
50
2
GEN 120
Mathematics (1)
)1( رياضيات
4
3
-
115
20
15
-
150
3
GEN 125
Physics (1)
)1( فيزياء
4
3
2
90
25
10
25
150
3
4
-
4
105
15
10
20
150
3
Basics of
computer science
أساسيات علوم الحاسب
CSC160
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Physics 1 Gen 125 : Electricity and Magnetism
REF: Physics For Scientists And Engineers 6E By Serway And Jewett
Ch. 1 : Overview of static electricity( Ch. 3 - Direct current and circuit
on Electric field and Gauss’ law,
Electric potential, capacitance
and dielectrics).
Ch. 2 : Resistance and current:
2-1 Electric Current
2-2 Resistance
2-3 A Model for Electrical
Conduction
2-4 Electrical Power
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3 -1 Electromotive Force
3 -2 Resistors in Series and Parallel
3 -3 Kirchhoff’s Rules
3 -4 RC Circuits
3 -5 Electrical Meters
Inductance: Self learning
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Physics 1 Gen 125 : Electricity and Magnetism
Ref: Physics For Scientists And Engineers 6E By Serway And Jewett
Ch. 4 : AC circuits:
4.1 AC Sources
4.2 Resistors in an AC
Circuit
4.3 Inductors in an AC
Circuit
4.4 Capacitors in an AC
Circuit
4.5 The RLC Series Circuit
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4.6 Power in an AC Circuit
4.7 Resonance in a Series
RLC Circuit
4.8 The Transformer and
Power Transmission
4.9 Rectifiers and Filters
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The aim of the course
•
The graduates have to develop a clear understanding of the
basic concepts of electricity.
• The graduates have to develop a clear understanding of the basic
concepts of electronics.
• Developing the graduate's skills and creative thought needed to meet
new trends in science.
• Supplying graduates with basic attacks and strategies for solving
problems.
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- Intended Learning Outcomes
A- Knowledge and
Understanding:
B- Intellectual Skills:
1) Concept of electric field, electric flux.
2) Concept dc circuits and Ac circuits.
3) Investigate the characteristics of simple series circuits that contain
resistors, inductors, and capacitors and that are driven by a sinusoidal
voltage.
4) Strategies for solving problems related to the previous topics.
1)
2)
C- Professional and
Practical Skills:
1)
2)
3)
D- General and
transferable Skills
1)
2)
3)
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Utilizations of theories, rules and basic sciences to interpret physical
events.
Collecting information from its relevant sources and use it in discussion.
Being able to solve problem sheets related to the material course.
Collect and record data and information from libraries and summarize it in
suitable forms.
The student would be able to apply some experiments related to the course
contents.
Graduate should be able to access data and information from the Internet
related to the course subjects.
Graduate should develop self professional, scientific, and personal attitude
towards continuous education.
Graduate should be able to cooperate in teams
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Chapter 1
Electric Charge and Electric Fields
What is a field?
What causes fields?
Field Type
gravity
electric
magnetic
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Caused By
mass
charge
moving charge
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Electric Charge
Types: Two types of charges
Positive: Lack of electrons
Negative: surplus of electrons
Unit : Coulomb
+ +
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C
- 9
Materials
Insulators: do not allow charges to move
through them(wood , paper…… )
Conductors: allow charges to move through
them ( copper……
Semiconductors: partially allow charges to
move through them ( Si , Ge …….
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Charging:
1-Contact
2-Friction(Rubbing)
3-Induction
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Charging:
-Contact
+++
+++
2
1
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+++
+++
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Charging:
-Contact
+++
+++
3
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Charging:
-Friction(Rubbing)
Ebonite
Glass
Wool
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Cloth
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Charging:
3-Induction
2
1
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3
15
Coulomb`s Law
+
+
K= 8.89 x109Nm2/C2
r
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Coulomb`s Law
(N)
Ɛo- Another constant called permittivity of
vacuum
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Coulomb`s Law
Several Charges
y
+q
1
F
13
F
F
13
+q
2
+q
3
X
F
23
F
23
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Electric Field
Force acting on a unit positive charge at
the point.
q
+++
(N/C)
r
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Electric Field
Force acting on a unit positive charge at
the point.
q
+++
(N/C)
r
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Lines of Force
Point Charge
-
+
positive
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negative
21
Lines of Force
Dipole
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Lines of Force
Two positive charges
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Lines of Force
Charged plane
+q
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-q
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Lines of Force
Two charged plates
-q
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+q
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More Coulomb’s Law
kq1q 2
F12 2 rˆ12
r12
ˆ12
r
r12
r12
+q1
rˆ12
+q2
r12
F12
r12
Coulomb’s constant:
permittivity of free space:
Charge polarity:
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N m2
1
9 Nm
k 8.988x10
9.0x10
2
C2
C
4o
2
1
C
o
8.85x1012
4k
N m2
9
Same sign
Opposite sign
Force is right
Force is Left
Electrostatics
--- Charges must be at rest!
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Superposition of Forces
F0 F10 F20 F30 ....
r10
+Q1
r20
+Q2
r30
+Q3
F30
F20
+Q0
F10
kq 0q1
kq 0q 2
kq 0q3
F0 2 rˆ10 2 rˆ20 2 rˆ30 ....
r10
r20
r30
N
q1
q3
q2
qi
F0 kq 0 2 rˆ10 2 rˆ20 2 rˆ30 .... kq 0 2 rˆi0
r20
r30
i 1 ri0
r10
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Zero Resultant Force,
Example
Where is the resultant
force equal to zero?
q1 = 15.0 mC
q2 = 6.0 mC
The magnitudes of the
individual forces will be
equal
Directions will be
opposite
Will result in a quadratic
Choose the root that gives
the forces in opposite
directions
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Electrical Force with Other
Forces, Example
The spheres are in
equilibrium
Since they are separated,
they exert a repulsive
force on each other
Charges are like charges
Proceed as usual with
equilibrium problems,
noting one force is an
electrical force
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Electrical Force with Other
Forces, Example cont.
The free body
diagram includes the
components of the
tension, the electrical
force, and the weight
Solve for |q|
You cannot determine
the sign of q, only that
they both have same
sign
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More Field Lines
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Q dq
A dA
Surface Charge Density:
Volume Charge Density:
Q dq
V dV
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Superposition of Fields
EP E1P E2P E3P ....
r10
+q1
E 30
E 20
r20
+q2
r30
+q3
P
E10
kq3
kq1
kq 2
E P 2 rˆ10 2 rˆ20 2 rˆ30 ....
r10
r20
r30
N
q1
q3
q2
qi
E P k 2 rˆ10 2 rˆ20 2 rˆ30 .... k 2 rˆi0
r20
r30
i 1 ri0
r10
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Superposition Example
Find the electric field due
to q1, E1
Find the electric field due
to q2, E2
E = E1 + E2
Remember, the fields add
as vectors
The direction of the
individual fields is the
direction of the force on a
positive test charge
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Gauss’s Law
The total of the electric flux out of a closed surface
is equal to the charge enclosed divided by the
permittivity.
Gauss's Law is a general law applying to any
closed surface.
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Gauss' law permits the
evaluation of the electric field
in many practical situations by
forming a symmetric Gaussian
surface surrounding a charge
distribution and evaluating
the electric flux through that
surface.
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