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The Stack Class
Final Review
Fall 2005
CS 101
Aaron Bloomfield
1
Motivation
Same as for Vectors
We want an easy way to store elements in a object
without having to worry about manipulating arrays
2
Properties of our Stack class
It needs to have an array to hold the values
That array will be fixed at size 1000
We’ll call it ‘array’
Thus, we also need a value to hold the number of elements in
the stack
We’ll call it ‘size’
Our Stack class so far:
public class Stack {
int array[] = new int[1000];
int size = 0;
3
About stacks
With a stack, you can only add and remove elements from
ONE end
Both occur from the same end
Think of a stack of papers – you are always adding a new
paper to the top or removing it from the top
Adding an element is called pushing an element
Removing an element is called popping an element
4
Methods in our Stack class
Create a Stack object
Insert and remove elements into/from the Stack
Get the top element
Find if the stack is empty
Print it out to the screen
Search the stack for a value
5
The Stack Constructor
Ready?
public Stack () {
}
Rather boring…
As we initialized the variables earlier, we don’t need to do so
here
But we could have done here just as well
6
Pushing an element onto the Stack
To add an element onto the Stack, we want to do two things
Insert it into the array at the proper position
Increment the size of the array
The code:
public void push (int value) {
array[size++] = value;
}
We could have done this in two lines as well:
public void push (int value) {
array[size] = value;
size = size + 1;
}
7
Popping an element from the Stack
To add an element onto the Stack, we want to do two things
Find (and return) the top element in the Stack
Decrement the size of the array
The code:
public int pop () {
return array[--size];
}
We could have done this in two lines as well:
public int pop () {
size = size – 1;
return array[size];
}
8
peek() and empty()
peek() is a quickie:
public int peek () {
return array[size-1];
}
empty() is also a quickie:
public boolean empty() {
return size == 0;
}
9
Searching the Stack
Note that we want to search up to the value in size, not the
entire (1,000 element) array
The method:
public boolean search (int forwhat) {
for ( int i = 0; i < size; i++ )
if ( array[i] == size )
return true;
return false;
}
10
Printing the Stack
The method:
public String toString() {
String ret = "Stack[";
for ( int i = 0; i < size; i++ ) {
ret += array[i];
This is just so that the
if ( i != size-1 )
method doesn’t print a
ret += ", ";
comma after the last
}
element
ret += "]";
Our for loop body could
also have been:
return ret;
ret += array[i] + ", ";
}
11
Using our Stack
public static void main (String args[]) {
Stack stack = new Stack();
System.out.println ("pushing elements 5 through 10 onto the stack");
for ( int i = 5; i <= 10; i++ )
stack.push(i);
System.out.println (stack);
System.out.println ("peek() returned: " + stack.peek());
System.out.println ("search(9) returned: " + stack.search(9));
int ret = stack.pop();
System.out.println ("pop() returned: " + ret);
System.out.println (stack);
System.out.println ("peek() returned: " + stack.peek());
ret = stack.pop();
System.out.println ("pop() returned: " + ret);
ret = stack.pop();
System.out.println ("pop() returned: " + ret);
System.out.println (stack);
System.out.println ("peek() returned: " + stack.peek());
System.out.println ("search(9) returned: " + stack.search(9));
}
12
Program Demo
Stack.java
13