Transcript Barnett
Photons and Quantum Information
Stephen M. Barnett
1. A bit about photons
2. Optical polarisation
3. Generalised measurements
4. State discrimination
Minimum error
Unambiguous
Maximum confidence
1. A bit about photons
Photoelectric effect - Einstein 1905
eV h W
BUT …
Modern interpretation: resonance with the
atomic transition frequency.
We can describe the phenomenon
quantitatively by a model in which the
matter is described quantum mechanically
but the light is described classically.
Photons?
Single-photon (?) interference - G. I. Taylor 1909
Light source
Smoked glass screens
Screen with two slits
Photographic
plate
Longest exposure - three months
“According to Sir J. J. Thompson, this sets a limit on the size of the
indivisible units.”
Single photons (?) Hanbury-Brown and Twiss
P (1,2) RI TI RT I 2
1
P (1) R I
2
Blackbody light
g(2)(0)
Laser light
g(2)(0) = 1
=2
g ( 2 ) ( 0)
P ( 2) T I
I2
I
Single photon
2
1
g(2)(0) = 0 !!!
violation of Cauchy-Swartz
inequality
Single photon source - Aspect 1986
Detection of the first
photon acts as a herald
for the second.
Second photon available for Hanbury-Brown
and Twiss measurement or interference
measurement.
Found g(2)(0) ~ 0 (single photons) and
fringe visibility = 98%
Two-photon interference - Hong, Ou and Mandel 1987
“Each photon then interferes only with itself. Interference between different
photons never occurs” Dirac
50/50 beam splitter R=T=1/2
P = R T 2 = 1/2
Two photons in
overlapping
modes
Boson “clumping”. If one photon is
present then it is easier to add a
second.
Two-photon interference - Hong, Ou and Mandel 1987
“Each photon then interferes only with itself. Interference between different
photons never occurs” Dirac
50/50 beam splitter R=T=1/2
P = R T 2 = 1/2
Two photons in
overlapping
modes
Boson “clumping”. If one photon is
present then it is easier to add a
second.
Two-photon interference - Hong, Ou and Mandel 1987
“Each photon then interferes only with itself. Interference between different
photons never occurs” Dirac
50/50 beam splitter R=T=1/2
P = 0 !!!
Two photons in
overlapping
modes
Destructive quantum interference
between the amplitudes for two
reflections and two transmissions.
1. A bit about photons
2. Optical polarisation
3. Generalised measurements
4. State discrimination
Minimum error
Unambiguous
Maximum confidence
Maxwell’s equations in an isotropic dielectric medium take the form:
E 0
B 0
E, B and k are mutually orthogonal
B
E
t
E
B 2
c t
E
S
k
B
For plane waves (and lab. beams that are
not too tightly focussed) this means that
the E and B fields are constrained to lie in
the plane perpendicular to the direction of
propagation.
1
0 E B
Consider a plane EM wave of the form
E E 0 exp i (kz t )
B B 0 exp i (kz t )
If E0 and B0 are constant and real then the wave is said to be linearly polarised.
B
Polarisation is defined by an axis
rather than by a direction:
B
E
E
If the electric field for the plane wave can be written in the form
E E0 (i ij) exp i(kz t )
Then the wave is said to be circularly polarised.
For right-circular polarisation, an observer
would see the fields rotating clockwise as
the light approached.
B
E
The Jones representation
We can write the x and y components of the complex electric field amplitude
in the form of a column vector:
i
E0 x E0 x e x
E
i y
0 y E0 y e
The size of the total field tells us nothing about the polarisation so we can
conveniently normalise the vector:
Horizontal polarisation
Vertical polarisation
1
0
0
1
Left circular polarisation
1
2
1
i
Right circular polarisation
1
2
1
i
One advantage of this method is that it allows us to describe the effects of optical
elements by matrix multiplication:
Linear polariser
(oriented to horizontal):
Quarter-wave plate
(fast axis to horizontal):
1 0 0 0 1 1 1
0
,
90
,
45
0 0
0 1
2
1
1
1 0 1 0
0 i 0 , 0 i 90 ,
1 i
45
i 1
1 0
0 1
Half-wave plate
(fast axis horizontal or vertical):
The effect of a sequence
of n such elements is:
1
2
A an
B c
n
bn a1
d n c1
b1 A
d1 B
We refer to two polarisations as orthogonal if
E*2 E1 0
This has a simple and suggestive form when expressed in terms of the Jones
vectors:
A1
A2
B is orthogonal to B if
1
2
A2* A1 B2* B1 0
A
*
2
B2* A1
B 0
1
†
A2 A1
0
B2 B1
There is a clear and simple
mathematical analogy between
the Jones vectors and our
description of a qubit.
Spin and polarisation Qubits
Poincaré and Bloch Spheres
Two state quantum system
Bloch Sphere
Electron spin
Poincaré Sphere
Optical polarization
We can realise a qubit as the state of single-photon polarisation
Horizontal
0
Vertical
1
Diagonal up
1
2
Diagonal down
1
2
Left circular
1
2
Right circular
1
2
0
1
0
1
0
i 1
0
i 1
1. A bit about photons
2. Optical polarisation
3. Generalised measurements
4. State discrimination
Minimum error
Unambiguous
Maximum confidence
Probability operator measures
Our generalised formula for measurement probabilities is
P(i) Tr ˆi ˆ
The set probability operators describing a measurement is
called a probability operator measure (POM) or a positive
operator-valued measure (POVM).
The probability operators can be defined by the properties
that they satisfy:
Properties of probability operators
I. They are Hermitian
II. They are positive
III. They are complete
ˆ ˆ n
†
n
ˆ n 0
ˆ
n
Î
Observable
Probabilities
Probabilities
n
IV. Orthonormal
ˆ iˆ j ijˆ i
??
Generalised measurements as comparisons
Prepare an ancillary system in
a known state:
A
S
Perform a selected unitary
transformation to couple the system
and ancilla:
S+A
S
S A
Uˆ S A
A
Perform a von Neumann measurement
on both the system and ancilla:
i Si Ai
The probability for outcome i is
P(i) i Uˆ A S S A Uˆ † i
S
A Uˆ † i
i Uˆ A S
ˆi
The probability operators ˆ i
act only on the system
state-space.
POM rules:
I. Hermiticity:
A Uˆ † i
i Uˆ A
†
ˆ
AU i
†
i Uˆ A
II. Positivity:
ˆi i Uˆ S A
2
III. Completeness follows
from:
i
i
i Î A,S
0
Generalised measurements as comparisons
We can rewrite the detection probability as
P(i) A S Pˆi S A
†
ˆ
ˆ
Pi U i
i Uˆ
is a projector onto correlated (entangled) states of the system
and ancilla. The generalised measurement is a von Neumann
measurement in which the system and ancilla are compared.
ˆi A Pˆi A
ˆ nˆ m A Pˆn A A Pˆm A 0
Simultaneous measurement of position and momentum
The simultaneous perfect measurement of x and p would violate
complementarity.
p
Position measurement gives no
momentum information and
depends on the position probability
distribution.
x
Simultaneous measurement of position and momentum
The simultaneous perfect measurement of x and p would violate
complementarity.
Momentum measurement gives no
position information and
p
depends on the momentum probability
distribution.
x
Simultaneous measurement of position and momentum
The simultaneous perfect measurement of x and p would violate
complementarity.
p
Joint position and measurement
gives partial information on both
the position and the momentum.
x
Position-momentum minimum
uncertainty state.
POM description of joint measurements
Probability density:
( xm , pm ) Trˆˆ ( xm , pm )
Minimum uncertainty states:
xm , pm 2
2 1 / 4
( x xm ) 2
dx exp 4 2 ipm x x
1
dxm dpm xm , pm xm , pm Î
2
This leads us to the POM elements:
1
ˆ ( xm , pm )
xm , p m xm , p m
2
The associated position probability distribution is
( x xm ) 2
( xm ) dx x ˆ x exp
2
2
Var ( xm ) x 2 2
2
& Var ( pm ) p 2
4 2
Increased uncertainty is the price we pay for measuring x and p.
1. A bit about photons
2. Optical polarisation
3. Generalised measurements
4. State discrimination
Minimum error
Unambiguous
Maximum confidence
The communications problem
‘Alice’ prepares a quantum system in one of a set of N possible
signal states and sends it to ‘Bob’
i selected.
prob. pi
Preparation
device
̂ i
Measurement
device
P( j | i ) Tr ˆ j ˆ i
Bob is more interested in
Tr ˆ j ˆ i pi
P (i | j )
Tr (ˆ j ˆ )
Measurement
result j
In general, signal states will be non-orthogonal. No measurement
can distinguish perfectly between such states.
Were it possible then there would exist a POM with
1 ˆ1 1 1 2 ˆ 2 2
2 ˆ1 2 0 1 ˆ 2 1
Completeness, positivity and 1 ˆ1 1 1
ˆ1 1 1 Aˆ
2 ˆ1 2 1 2
Aˆ positive and Aˆ 1 0
2
2 Aˆ 2 1 2
2
0
What is the best we can do? Depends on what we mean by ‘best’.
Minimum-error discrimination
We can associate each measurement operator ˆ i with a signal
state ̂ i . This leads to an error probability
Pe 1 p jTr ˆ j ˆ j
N
j 1
Any POM that satisfies the conditions
ˆ j ( p j ˆ j pk ˆ k )ˆ k 0
N
p ˆ ˆ
k 1
k
k
k
p j ˆ j 0
will minimise the probability of error.
j , k
j
For just two states, we require a von Neumann measurement with
projectors onto the eigenstates of p1 ˆ1 p2 ˆ 2 with positive (1)
and negative (2) eigenvalues:
Pemin 12 1 Tr p1 ˆ1 p2 ˆ 2
Consider for example the two pure qubit-states
1 cos 0 sin 1
1 2 cos(2 )
2 cos 0 sin 1
The minimum error is achieved by measuring in
the orthonormal basis spanned by the states 1
and 2 .
1
1
2
2
We associate 1 with 1 and 2 with 2 :
Pe p1 1 2
2
p2 2 1
2
The minimum error is the Helstrom bound
Pemin
1
2 1 1 4 p1 p2 1 2
1/ 2
2
A single photon only gives one “click”
P = |a|2
a
+b
P = | b| 2
But this is all we need to discriminate between our two states
with minimum error.
A more challenging example is the ‘trine ensemble’ of three
equiprobable states:
0
31
1 12 0 3 1
p1
2 12
p2
3 0
1
3
p3
1
3
1
3
It is straightforward to confirm that the minimum-error conditions
are satisfied by the three probability operators
ˆi 23 i i
Simple example - the trine states
Three symmetric states of photon polarisation
3
2
3
1
2
3
2
Minimum error probability
is 1/3.
This corresponds to a POM
with elements
2
ˆ
j j j
3
How can we do a polarisation
measurement with these three
possible results?
Polarisation interferometer - Sasaki et al, Clarke et al.
1 / 6 2 / 3 1 / 6
0 0 0
0 0 0
1 / 6 1 / 6 2 / 3
PBS
2
0 0 0
0 3 / 2 3 / 2
PBS
1 1 / 2 1 / 2
0 3 / 2 3 / 2
2
11/ 2 1/ 2
0 0 0
PBS
0 0 0
2 / 3 1 / 6 1 / 6
1 / 3 1 / 12 1 / 12
2 / 3 1 / 6 1 / 6
Unambiguous discrimination
The existence of a minimum error does not mean that error-free
or unambiguous state discrimination is impossible. A von Neumann
measurement with
Pˆ1 1 1
ˆ
P1 1 1
will give unambiguous identification of 2 :
result
1 2
error-free
result
1 ?
inconclusive
There is a more symmetrical approach with
ˆ1
ˆ 2
1
1 1 2
1
1 1 2
2 2
1 1
ˆ ? Î ˆ1 ˆ 2
Result 1
Result 2
Result ?
State 1
1 1 2
0
1 2
State 2
0
1 1 2
1 2
How can we understand the IDP measurement?
Consider an extension into a 3D state-space
b
a
a
b
Unambiguous state discrimination - Huttner et al, Clarke et al.
a
?
b
a
b
A similar device
allows minimum
error discrimination
for the trine states.
Maximum confidence measurements seek to maximise the
conditional probabilities
P( i | i )
for each state.
For unambiguous discrimination these are all 1.
Bayes’ theorem tells us that
pi i ˆi i
pi P(i | i )
P( i | i )
P(i )
k pk k ˆi k
so the largest values of those give us maximum confidence.
The solution we find is
ˆi ˆ ˆ j ˆ
1
1
where
ˆ j j j
ˆ pi ˆ i
i
Croke et al Phys. Rev. Lett. 96, 070401 (2006)
Example
• 3 states in a 2dimensional
space
• Maximum Confidence Measurement:
• Inconclusive outcome needed
Optimum probabilities
• Probability of correctly
determining state
maximised for minimum
error measurement
• Probability that result
obtained is correct
maximised by maximum
confidence measurement:
Results:
Maximum confidence
Minimum error
Conclusions
• Photons have played a central role in the development of
quantum theory and the quantum theory of light continues to
provide surprises.
• True single photons are hard to make but are, perhaps, the ideal
carriers of quantum information.
• It is now possible to demonstrate a variety of measurement
strategies which realise optimised POMs
• The subject of quantum optics also embraces atoms, ions
molecules and solids ...