Light polarisation and related instabilities in 4 mirror cavities.
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Transcript Light polarisation and related instabilities in 4 mirror cavities.
Polarisation effects in 4
mirrors cavities
•Introduction
•Polarisation eigenmodes
calculation
•Numerical illustrations
F. Zomer LAL/Orsay
Posipol 2008 Hiroshima 16-19 june
1
3D: tetrahedron
cavity
2D: bow-tie cavity
V0
h~100mm
h~100mm
L~500mm
L~500mm
V0
V0 = the electric vector of the incident laser beam,
What is the degree of polarisation inside the resonator ?
Answer: ~the same if the cavity is perfectly aligned
different is the cavity is misaligned
numerical estimation of the polarisation effects is case
of unavoidable mirrors missalignments
2
Calculations (with Matlab)
• First step : optical axis calculation
– ‘fundamental closed orbit’ determined using iteratively
Fermat’s Principal Matlab numerical precision
reached
• Second step
– For a given set of mirror misalignments
• The reflection coefficients of each mirror are computed as a
function of the number of layers (SiO2/Ta2O5)
– From the first step the incidence angles and the mirror
normal directions are determined
– The multilayer formula of Hetch’s book (Optics) are then
used assuming perfect lambda/4 thicknesses when the
cavity is aligned.
• Third step
– The Jones matrix for a round trip is computed
following Gyro laser and non planar laser standard
techniques (paraxial approximation)
3
Planar mirror
y
V0
x
y
P1
k1
p2
S1
Planar mirror
p1
k2
P2
s1
s2
z
p2’
k3
s2
Spherical mirror
S2
Spherical mirror
ni is the normal vector of mirror i
We have si=ni×ki+1/|| ni×ki+1||
and pi=ki×si/|| ki×si||,
pi’=ki+1×si/|| ki+1×si||,
where ki and ki+1 are the
wave vectors incident and
reflected by the mirror i.
Example of a 3D cavity.
Denoting by
• Ri the reflection matrix of the mirror i
• Ni,i+1 the matrix which describes the change of the basis {si,p’i,ki+1}
to the basis {si+1,pi+1,ki+1}
| rs | eis
R
0
Er , s
Ei , s
, such
R
i p
E
E
| rp | e
r, p'
i, p
0
With s≠p when mirrors are misaligned !!!
rs ≠ rp when incidence angle ≠ 0
s i s i+1 p'i s i+1
Ni ,i 1
s
p
p'
p
i i+1
i
i+1
4
J R1 N 41R4 N34 R3 N 23 R2 N12
Taking the mirror 1 basis as the reference
basis one gets the Jones Matrix
for a round trip
And the electric field circulating inside the cavity
where V0 is the incident polarisation vector in
the s1,p1 basis
Ecirculating
n
J T1V0
n 0
Transmission matrix
The 2 eigenvalues of J are ei = |ei|exp(ifi) and f1≠f2 a priori.
The 2 eigenvectors are noted ei . One gets
1
1 e eif1 ei
1
Ecirculating U
0
s 1 e1 s 1 e 2
,
U
p ' e1 p ' e 2
1
1
0
1
1 e2 eif2 ei
with the normalised eignevectors e i =
ei
ei
U 1T V
1 0
is the round trip phase:
=2pn L
if the cavity is locked on
one phase,
e.g. the first one
f1=2p,
then
f2=2p f2f1
5
Experimentally one can lock on the maximum mode coupling, so that the
circulating field inside the cavity is computed using a simple algorithm :
1
0
1 e
1
U 1T V
If e1 T1V0 e 2 T1V0 : Ecirc U
1 0
1
0
i (f2 f1 )
1
e
e
2
1
0
1 e e i (f2 f1 )
1
U 1T V
If e 2 T1V0 e1 T1V0 : Ecirc U
1 0
1
0
1
e
2
Numerical study : 2D and 3D
•L=500mm, h=50mm or 100mm for a given V0
•Only angular misalignment tilts dqx,dqy = {-1,0,1} mrad or mrad
with respect to perfect aligned cavity
•38=6561 geometrical configurations (it takes ~2mn on my laptop)
•Stokes parameters for the eigenvectors and circulating field
computed for each configuration histograming
6
An example of a mirror misalignments configuration :
2D with 3D misalignments
Planar mirror
Spherical mirror
Planar mirror
Spherical mirror
7
An example of a mirror misalignments configuration :
3D with 3D missalignments
planar
mirror
Spherical
mirror
planar
mirror
Spherical
mirror
8
Results are the following:
For the eigen polarisation
•2D cavity : eigenvectors are linear for low mirror reflectivity
and elliptical at high reflect.
•3D cavity : eigenvectors are circular for any mirror reflectivities
Eigenvectors unstables for 2D cavity at high finesse
eigen polarisation state unstable
For the circulating field
•In 2D the finesse acts as a bifurcation parameter for the polarisation state
of the circulating field
The vector coupling between incident and circulating beam is unstable
the
circulating power is unstable
•In 3D the circulating field is always circular at high finesse because only
one of the two eigenstates resonates !!!
9
Numerical examples of eigenvectors
for 1mrad misalignment tilts
Stokes parameters for the
eigenvectors shown using the
Poincaré sphère
S3
3D
28 entries/plots
(misalignments
configurations)
S3=1
S1
S2
q0,p Circular polarisation
qp/2 Linear polarisation
Elliptical polarisation otherwise
3 mirror coef. of reflexion considered
Nlayer=16, 18 and 20
2D
S3=0
10
The circulating field is computed for :
For 1mrad misalignment tilts
and
V0 =
3D
1
2
S3,in 1
i
2
Then the cavity gain is computed
gain = |Ecirculating|2 for |Ein|2=1
2D
11
Stokes Parameters distributions
1
2
V0 =
i
2
S3,in 1
3D
1mrad
tilts
2D
12
X check
Low finesse
2D
Eigen
vectors
V0 =
Cavity
gain
1
2
1
2
S 2,in 1
1mrad
tilts
Stokes
parameters
Stokes
parameters
13
X-check
low finesse
3D
Cavity
gain
V0 =
1
2
1
2
Stokes
parameters
S 2,in 1
1mrad
tilts
Stokes
parameters
Stokes
parameters
14
Numerical examples for U or Z 2D & 3D cavities (6reflexions for 1 cavity round-trip)
Z 2D
(proposed by KEK)
1
2
V0 =
i
2
S3,in 1
U 2D
1mrad
tilts leads
to ~10% effect
on the gain
for the
highest
finesse
N=20
‘closed orbits’ are
always self retracing
highest sensitivity to
misalignments viz
bow-tie cavties
U 3D
15
Summary
• Simple numerical estimate of the effects of mirror
misalignments on the polarisation modes of 4 mirrors
cavity
– 2D cavity
• Instability of the polarisation of the eigen modes
Instability of the polarisation mode matching
between the incident and circulating fields
power instability growing with the cavity finesse
– 3D cavity
• Eigen modes allways circular
• Power stable
– Z or U type cavities (4 mirrors & 6 reflexions) behave like 2D
bow-tie cavities with highest sensitivity to misalignments
• Most likely because the optical axis is self retracing
• Experimental verification requested …
16
U 2D L=500.0;h=150.0, ra=1.e-7, S3=1
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