STA 291-021 Summer 2007
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Transcript STA 291-021 Summer 2007
Lecture 15
Dustin Lueker
The width of a confidence interval
◦
◦
◦
◦
Increases
Increases
Increases
Increases
as
as
as
as
the
the
the
the
confidence level increases
error probability decreases
standard error increases
sample size n decreases
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n≥30
x Z / 2
s
n
x t / 2
s
n
n<30
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Start with the confidence interval formula
assuming that the population standard
deviation is known
x Z / 2
s
x ME
n
Mathematically we need to solve the above
equation for n
2
Z / 2
ns
ME
2
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The sample proportion is an unbiased and
efficient estimator of the population
proportion
◦ The proportion is a special case of the mean
pˆ Z / 2
pˆ (1 pˆ )
n
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To calculate the confidence interval, we use
the Central Limit Theorem (np and nq ≥ 5)
◦ What if this isn’t satisfied?
Instead of the typical p̂ estimator, we will
use
x2
~
p
n4
Then the formula for confidence interval
becomes
~
~
p (1 p )
~
p Z 2
n4
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As with a confidence interval for the sample
mean a desired sample size for a given
margin of error (E) and confidence level can
be computed for a confidence interval about
the sample proportion
2
Z / 2
n pˆ (1 pˆ )
E
◦ This formula requires guessing p̂ before taking the
sample, or taking the safe but conservative
approach of letting p̂ = .5
Why is this the worst case scenario? Or the
conservative approach?
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Two independent samples
◦ Different subjects in the different samples
◦ Two subpopulations
Ex: Male/Female
◦ The two samples constitute independent samples from two
subpopulations
Two dependent samples
◦ Natural matching between an observation in one sample
and an observation in the other sample
Ex: Two measurements of the same subject
Left/right hand
Performance before/after training
◦ Important: Data sets with dependent samples require
different statistical methods than data sets with
independent samples
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Is the proportion who favor national health
insurance different for Democrats and
Republicans?
◦ Democrats and Republicans would be your two samples
◦ Yes and No would be your responses, how you’d find
your proportions
Is the proportion of people who experience pain
different for the two treatment groups?
◦ Those taking the drug and placebo would be your two
samples
Could also have them take different drugs
◦ No pain or pain would be your responses, how you’d
find your proportions
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Take independent samples from both groups
Sample sizes are denoted by n1 and n2
◦ To use the large sample approach both samples
should be greater than 30
Subscript notation is same for sample means
( x1 x2 ) Z / 2
2
1
2
2
s
s
n1 n2
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In the 1982 General Social Survey, 350
subjects reported the time spent every day
watching television. The sample yielded a
mean of 4.1 and a standard deviation of 3.3.
In the 1994 survey, 1965 subjects yielded a
sample mean of 2.8 hours with a standard
deviation of 2.
◦ Construct a 95% confidence interval for the
difference between the means in 1982 and 1994.
Is it plausible that the mean was the same in both
years?
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For large samples
◦ For this we will consider a large sample to be those
with at least five observations for each choice
(success, failure)
All we will deal with in this class
Large sample confidence interval for p1-p2
pˆ1 pˆ 2 Z / 2
pˆ1 (1 pˆ1 ) pˆ 2 (1 pˆ 2 )
n1
n2
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Two year Italian study on the effect of condoms
on the spread of HIV
◦ Heterosexual couples where one partner was infected
with HIV virus
171 couples who always used condoms, 3 partners became
infected with HIV
55 couples who did not always use a condom, 8 partners
became infected with HIV
◦ Estimate the infection rates for the two groups
◦ Construct a 95% confidence interval to compare them
What can you conclude about the effect of condom use on
being infected with HIV from the confidence interval?
Was your Sex Ed teacher lying to you?
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