Transcript Chapter_1_Review[1] - AP-Stat

Chapter 1 Review
CONSTRUCTING AND INTERPRETING
GRAPHICAL DISTRIBUTIONS
Review Procedure
On each page, you will see a problem. You will be
timed using the dotted yellow line below. Your goal
is to finish each problem correctly before the line
vanishes.
You will hear a horn to symbolize
the expired time!
Get Ready
Here comes your first question. The
solution will follow on the next
slide
Question 1
What is the difference between Categorical and
Quantitative variables? What graphs are you able to
draw with each variable?
Stop Working!
Question 1-Answer
Categorical
Quantitative
 The placement of an
 The numerical values
individual into one
group or category
 This variable can use a
Bar Graph and/or a
Pie Chart for a
graphical display
in which it makes sense
to calculate the mean
 This variable can use a
Stemplot (Stem & Leaf
Plot), Dotplot,
Histogram, and/or
Boxplot (Box &
Whisker Plot)
Question 2
Among persons aged 15 to 24 years in the US, the
leading causes of death and number of deaths in a
recent year were as follows: accidents, 15,567;
homicide, 5,359; suicide, 4,139; cancer 1,717; heart
disease, 1,067; congenital defects, 483. Identify
the individuals and variables for the
problem.
Stop Working!
Question 2-Answer
The individuals in the study are the 15 to 24 year olds
in the United States
The variables in the study are the causes of death
among 15 to 24 year olds in the United States
Question 3
Create a bar graph for the data from question 2. Make
a conclusion about your graph.
Accidents, 15,567; Homicide, 5,359; Suicide, 4,139;
Cancer 1,717; Heart disease, 1,067; Congenital
defects, 483
Stop Working!
Question 3-Answer
Question 4
Here are the data from a survey conducted at eight
high schools on smoking among students and their
parents.
Number of Parent Smokers
Student Smokes
Doesn't Smoke
Neither
One
Two
1168
1823
1380
188
416
400
What percent of students smoke?
Provide marginal distribution of
parents’ smoking behavior in
percents.
Stop Working!
Question 4-Answer
 The counts and percents are as follows
Neither Parent One Parent Two Parents
Count
1356
Percent 25.23%
2239
1780
41.66%
33.12%
The table shows that almost half of the data comes
from families where one parent smokes.
Question 5
I have a set of data that shows a right-skewed
graphical display. Can we make any statements
about the mean and median without seeing the data?
If so, what statements can we make.
Stop Working!
Question 5-Answer
YES! The mean will be larger than the median due to
the shape of the distribution. We cannot make any
further statements regarding the spread of the data
though.
Question 6
Create a Stemplot for the following data and then
describe the distribution
114 100 104
89
102
91
114 114 103 105
108 130 120 132 111 128 118 119
86
111 103
112 112
74
112 107 103
98
Stop Working!
96
72
Question 6-Answer
7 24
8 69
9 168
10 023334578
11 1122244489
12 08
13 02
5 7 means 57
The distribution is
approximately
normal. (symmetric)
We can also say this
distribution is
unimodal
Question 7
Provide a 5 number summary for the 20 travel
times of Philadelphia commuters measured in
minutes.
40 60 60 15 15 10 30 25 85
5
10
65
45
15
20
20
30
40
15
Draw the appropriate graphical display for your
findings
Stop Working!
20
Question 7-Answer
Travel Times of Philadelphia Commuters
Box Plot
Min: 5
Q1: 15
M: 22.5
Q3: 42.5
Max: 85
0
10
20
30
40 50
Minutes
60
70
80
90
Question 8
For question 7, which method of central tendency
would be sufficient to help identify the outliers.
What are the lower and upper boundaries for outliers?
Stop Working!
Question 8-Answer
Since the median was 22.5 and the mean can be
calculated to equal 31.25, the best measure of central
tendency would be the use of the median. The
comparison shows the distribution to be skewed to
the right.
The IQR rule creates the extension of 41.25 from Q1
and Q3. Therefore, 85 is a suspected outlier. The
collection of more data is required.
Question 9
Calculate the standard deviation for each sample of
data.
Data A 1692 1666
1462
1614
1667
1539
1560
Data B
118
115
5
73
47
60
2
What comparison can we make about the
data?
Stop Working!
Question 9-Answer
The standard deviation for Data A and Data B are
83.54 and 46.75 respectively.
This informs us that Data B has a closer spread of
values relative to the mean than does Data A.
Question 10
The mean weight for a sample of students at Interboro
is 184 lbs.
If one of our students who weighs 240 lbs decided to
not participate in the study, how would our mean
change? How would our standard deviation change?
Stop Working!
Question 10-Answer
We are unable to determine the affect of removing one
value without knowing the other values.
*Caution* There will be scenarios that allow us to
accurately predict the change