15.060 Data, Models and Decisions
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Transcript 15.060 Data, Models and Decisions
15.Math-Review
Review 2
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Exercises
P1. Historical data indicates that the starting salary for a new MBA graduate
in a leading management consulting firm can be modeled as a normal
distribution with mean $90,000 and standard deviation $20,000. Second year
salaries increase by 20%. The bonus each year, for the first and following
years, can be modeled as a normal distribution with mean $25,000 and
standard deviation $5,000. We assume that the bonus is independent of the
initial salary increase. For the purpose of this problem annual compensation is
salary plus bonus.
(a) What is the expected annual compensation for a new hire?
(b) What is the standard deviation of the annual compensation for a new hire?
(c) What is the expected annual compensation after completing a year in the firm,
I.e., just after the salary increase is announced?
(d) What is the probability that the annual compensation after completing a year in
the firm, i.e., just after the salary increase is announced, will exceed $140,000?
(Hint: The annual compensation is also normally distributed).
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Exercises
P2. Suppose 5% of the microchips produced by a leading microchip
manufacturer are defective. An inspector inspects 10 microchips.
Historically, given that a microchip is defective, the inspector accepts it 10%
of the time thinking it has no defect. If a microchip is not defective, he always
correctly accepts it.
(a)
(b)
(c)
(d)
What is the probability that all 10 microchips in the sample are not defective?
What is the probability that the inspector accepts the first microchip?
What is the probability that the inspector accepts 9 (out of 10) microchips?
Given that the inspector accepts a microchip, what is the probability that it has no
defect?
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Exercises
P3. To the best of our knowledge, with probability 0.8 Al is guilty of the
crime for which he is about to be tried. Bo and Ci, each of whom knows
whether or not Al is guilty, have been called to testify. Bo is a friend of Al’s
and will tell the truth if Al is innocent, but will lie with probability 0.2 if Al is
guilty. Ci hates every body but the judge and will tell the truth if Al is guilty
but will lie with probability 0.3 if Al is innocent. Given this model:
(a) Determine the probability that the witnesses give conflicting testimony.
(b) Which witness is more likely to commit perjury?
(c) What is the conditional probability that Al is innocent, given that Bo and Ci gave
conflicting testimony?
(d) Are the events “Bo tells a lie” and “Ci tells a lie” independent? Are these events
conditionally independent to an observer who knows whether or not Al is guilty?
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Exercises
P4. The probability that any particular bulb will burn out during its Kth
month of use is given by the probability distribution function for K:
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P( K k )
55
k 1
k 1,2,3,...
Does this distribution sum to 1?
Four bulbs are life-tested simultaneously. Determine the probability that
(a)
(b)
(c)
(d)
None of the four bulbs fails during its first month of use.
Exactly two bulbs have failed by the end of the third month.
Exactly one bulb fails during each of the first three months.
Exactly one bulb has failed by the end of the second month, and exactly two
bulbs are still working at the start of the fifth month.
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Exercises
P5. Discrete random variable X is described by the probability distribution
function:
x
K
x 0,1,2
P( X x)
12
0
o/w
Let d1, d2,…, d20 represent 20 successive independent experimental values of
random variable X.
(a) Determine the numerical value of K.
(b) Determine the probability that d1 > d2 .
( c) Determine the probability that d1+ d2+…+ d20 1.0
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Exercises
P6. Back to stocks. We know that the return of different stocks are random
variables. And for:
Snowboard Inc.: mean return = 0.9, stand. deviation of return = 0.075.
Skiboots Inc.: mean return = 0.9, stand. deviation of return = 0.27.
If you decide to invest 30% of your capital in Snowboard Inc., and 10% in Skiboots
Inc. What is the mean and variance of the return of the resulting portfolio?
How much of each stock should you buy to obtain a portfolio with minimal variance?
(minimal risk!)
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Exercises
P7. Helen has an early class tomorrow morning. She knows that she needs to
get to bed by 10 PM in order to be sufficiently rested to concentrate and
participate in class. However, before she goes to bed, she must start and then
complete a homework assignment which is due tomorrow morning.
According to her experience, the time it takes her to complete a homework
assignment for this class is Normally distributed with mean = 3.5 hours and
standard deviation = 1.2 hours. Helen looks at her watch, and sees that it is
now 6pm. What is the probability that she will be able to get to bed in time to
be sufficiently rested?
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Exercises
P8. According to the latest Census, 52.2% of Boston residents are female.
Suppose a group of 100 Bostonians is selected at random.
Find the mean and the standard deviation of the number of female members of the
group.
Use the Normal approximation to find the probability that less than one half of the
members of the group are female.
Use the Normal approximation to find the probability that the number of female
members of the group is between 45 and 55.
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Solutions
P1. (a) 115,000
(b) 20,615.53
(c) 133,000
(d) 0.3859
P2. (a) 0.95^10
(b) 0.955
(c) 10(0.955)^9(0.45)
(d) 0.95/0.955
P3. (a) 0.22
(b) Bo is more likely. 0.16 > 0.06.
(c) 3/11
(d) First question NO. Second YES.
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P4. Yes
(a) (4/5)^4
(b) 0.374568
(c) 0.030968
(d) 0.154538
P5. (a) K=5/12
(b) 47/144=0.326389
(c) 0.4228*10^-7
P6. (a) E(Z)=0.9, V(Z)=0.0298485
(b) 80.89% of Snowboard Inc.
V(Z*)=0.0016474
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Solutions
P7. P(X<=4) = 0.66095
P8. (a) E(X)=52.2, Std(X)=2.49516
(b) P(X<50) = 0.18805
(c) P(45<=X<=55) = 0.86775
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