differential equation
Download
Report
Transcript differential equation
First-Order Differential Equations
S.-Y. Leu
Sept. 28, 2005
1
CHAPTER 2
First-Order Differential Equations
2.1 Solution Curves Without the Solution
2.2 Separable Variables
2.3 Linear Equations
2.4 Exact Equations
2.5 Solutions by Substitutions
2.6 A Numerical Solution
2.7 Linear Models
2.8 Nonlinear Models
2.9 Systems: Linear and Nonlinear Models
2
2.1 Solution Curves Without the Solution
y
Slope=
dy
y'
dx
x
Short tangent segments suggest the
shape of the curve
輪廓
3
2.1 Solution Curves Without the Solution
The general first-order differential equation has
the form
F(x, y, y’)=0
or in the explicit form
y’=f(x,y)
Note that, a graph of a solution of a first-order
differential equation is called a solution curve
or an integral curve of the equation.
On the other hand, the slope of the integral
curve through a given point (x0,y0) is y’(x0).
4
2.1 Solution Curves Without the Solution
A drawing of the plane, with short line
segments of slope drawn at selected points ,
is called a direction field or a slope field of
the differential equation .
The name derives from the fact that at each
point the line segment gives the direction of
the integral curve through that point. The
line segments are called lineal elements.
5
2.1 Solution Curves Without the Solution
Plotting Direction Fields
1st Step
y’=f(x,y)=C=constant curves of equal inclination
2nd Step
Along each curve f(x,y)=C, draw lineal elements
direction field
3rd Step
Sketch approximate solution curves having the
directions of the lineal elements as their tangent
directions.
6
2.1 Solution Curves Without the Solution
If the derivative dy/dx is positive
(negative) for all x in an interval I,
then the differentiable function y(x)
is increasing (decreasing) on I.
7
2.1 Solution Curves Without the Solution
DEFINITION: autonomous DE
A differential equation in which the independent
variable does not explicitly appear is known
as an autonomous differential equation.
For example, a first order autonomous DE has
the form y ' f ( y)
DEFINITION: critical point
'
A critical point of an autonomous DE y f ( y) is a real
number c such that f(c) = 0.
Another name for critical point is stationary point or
equilibrium point.
If c is a critical point of an autonomous DE, then y(x) = c is a
constant solution of the DE.
2.1 Solution Curves Without the Solution
DEFINITION: phase portrait
A one dimensional phase portrait of an
'
y
f ( y) is a diagram which indicates
autonomous DE
the values of the dependent variable for which y is
increasing, decreasing or constant.
Sometimes the vertical line of the phase portrait is
called a phase line.
2.2 Separable
Variables
DEFINITION: Separable DE
A first-order differential equation of
the form
dy
g ( x ) h( y )
dx
is said to be separable or to
have separable variables.
(Zill, Definition 2.1, page 44).
10
2.2 Separable Variables
Method of Solution
dy
g ( x ) h( y )
dx
1 dy
dy
p( y )
g ( x)
h( y ) dx
dx
If y (x) represents a solution
'
p
(
(
x
))
( x) g ( x)
'
p( ( x)) ( x) dx g ( x) dx
p ( y ) dy g ( x) dx
H ( y) c1 G( x) c2
dy ' ( x) dx
H ( x) G ( x) c
11
2.2 Separable Variables
The Natural Logarithm
x
1
domain
,
ln x
dt
1
t
,
ln x log e x
1
Dx ln x
x
ln( ab) ln a ln b
ln (0, )
e 2.71828
1
D ln x 2
x
2
x
ln
a
ln a ln b
b
ln a r r ln a
The natural exponential function
domain exp (, )
exp x e x
12
2.3 Linear
Equations
DEFINITION: Linear Equation
A first-order differential equation of
the form
dy
a1 ( x)
a0 ( x ) y g ( x)
dx
is said to be a linear equation.
(Zill, Definition 2.2, page 51).
When g ( x) 0 homogeneous
Otherwise it is non-homogeneous.
13
2.3 Linear
Equations
Standard Form
a1 ( x)
dy
a0 ( x ) y g ( x)
dx
dy
p( x) y f ( x)
dx
14
2.2 Separable Equations
A differential equation is called separable if it
can be written as y ' A( x) B( y )
Such that we can separate the variables and
write
1
B( y )
dy A( x)dx
B( y ) 0
We attempt to integrate this equation
1
dy
B( y )
A( x)dx
2.2 Separable Equations
Example 1.
y ye
'
as
2
x
dy
x
e
dx
2
y
is separable. Write
dy
y 2ex
dx
y0
Integrate this equation to obtain
or in the explicit form y 1
1
e x k
y
ex k
What about y=0 ? Singular solution !
2.2 Separable Equations
Example 2.
x 2 y ' 1 y is separable, too. We write
dy
dx
2
1 y x
x0
y 1
Integrate the separated equation to obtain
1
ln 1 y k
1 y e k e 1 / x Ae 1 / x
x
1 y Ae 1 / x Be 1 / x
y 1 Be 1 / x
The general solution is
Again, check if y=-1 is a solution or not ?
it is a solution, but not a singular one, since it is a special case of the
general solution
2.3 Linear Differential Equations
A first-order differential equation is linear if it has the
form y ' ( x) p ( x) y q ( x)
p ( x ) dx
Multiply the differential equation by e
to get
e
p ( x ) dx
y ' ( x) p( x)e
d
y ( x )e
dx
q ( x )e
y q( x)e
y ( x) e
p ( x ) dx
p ( x ) dx
p ( x ) dx
Now integrate to obtain y( x)e
p ( x ) dx
p ( x ) dx
q( x)e
p ( x ) dx
p ( x ) dx
q( x)e
dx C e
p ( x ) dx
dx C
p ( x ) dx
The function e p ( x ) dx is called an integrating factor for
the differential equation.
2.3 Linear Differential Equations
Linear: A differential equation is called linear if
there are no multiplications among
dependent variables and their derivatives.
In other words, all coefficients are functions of
'
( x) p ( x) y q( x)
independentyvariables.
Non-linear: Differential equations that do not
satisfy the definition of linear are non-linear.
Quasi-linear: For a non-linear differential
equation, if there are no multiplications among
all dependent variables and their derivatives in
the highest derivative term, the differential
equation is considered to be quasi-linear.
2.3 Linear Differential Equations
Example
y ' y sin( x)
is a linear DE. P(x)=1 and
q(x)=sin(x), both continuous for all x.
An integrating factor is e p ( x ) dx e dx e x
Multiply the DE by e
Or ye x ' e x sin( x)
Integrate to getye
x
to get y e
x
'
x
ye e sin( x)
x
x
1
e sin( x) dx e sin( x) cos(x) C
2
The general solution is
x
x
y
1
sin( x) cos(x) Cex
2
2.3 Linear Differential Equations
Example
y
'
2
Solve the initial value problem y 3x x ; y (1) 5
It can be written in linear form ' 1
2
y
x
y 3x
x0
An integrating factor is e (1/ x ) dx eln(x ) x
for
Multiply the DE by x
to get xy ' y 3x 3
Or xy ' 3x 3
3 3 C
3 4
y x
Integrate to get xy x C
,then
4
x
4
for x 0
3
For the initial condition, we need y(1) 5 C
4
C=17/4 the solution of the initial value problem
3 3 17
is
y ( x) x
4
4x