Transcript Document
Complex Variables
Mohammed Nasser
Acknowledgement:
Steve Cunningham
Open Disks or Neighborhoods
Definition. The set of all points z which satisfy
the inequality |z – z0|<, where is a positive
real number is called an open disk or
neighborhood of z0 .
Remark. The unit disk, i.e., the neighborhood
|z|< 1, is of particular significance.
1
Interior Point
Definition. A point z 0 S is called an interior point
of S if and only if there exists at least one
neighborhood of z0 which is completely contained
in S.
z0
S
Open Set. Closed Set.
Definition. If every point of a set S is an interior point of
S, we say that S is an open set.
Definition. S is closed iff Sc is open. Theorem: S` S,
i.e., S contains all of its limit points
S is closed set.
Sets may be neither open nor closed.
Open
Closed
Neither
Connected
An open set S is said to be connected if
every pair of points z1 and z2 in S can be
joined by a polygonal line that lies entirely in
S. Roughly speaking, this means that S
consists of a “single piece”, although it may
contain holes.
S
z1
z2
Domain, Region, Closure,
Bounded, Compact
An open, connected set is called a domain. A region
is a domain together with some, none, or all of its
boundary points. The closure of a set S denoted S,
is the set of S together with all of its boundary. Thus
S S B(S.)
A set of points S is bounded if there exists a positive
real number r such that |z|<r for every z S.
A region which is both closed and bounded is said to
be compact.
Review: Real Functions of Real
Variables
Definition. Let . A function f is a rule which
assigns to each element a one and only one
element b , . We write f: , or in the
specific case b = f(a), and call b “the image of a
under f.”
We call “the domain of definition of f ” or simply
“the domain of f ”. We call “the range of f.”
We call the set of all the images of , denoted f (),
the image of the function f . We alternately call f a
mapping from to .
Real Function
In effect, a function of a real variable maps
from one real line to another.
f
Complex Function
Definition. Complex function of a complex
variable. Let C. A function f defined on
is a rule which assigns to each z a
complex number w. The number w is called
a value of f at z and is denoted by f(z), i.e.,
w = f(z).
The set is called the domain of definition of
f. Although the domain of definition is often a
domain, it need not be.
Remark
Properties of a real-valued function of a real variable
are often exhibited by the graph of the function. But
when w = f(z), where z and w are complex, no such
convenient graphical representation is available
because each of the numbers z and w is located in
a plane rather than a line.
We can display some information about the function
by indicating pairs of corresponding points z = (x,y)
and w = (u,v). To do this, it is usually easiest to draw
the z and w planes separately.
Graph of Complex Function
y
w = f(z)
v
x
z-plane
domain of
definition
u
range
w-plane
Arithmetic Operations in Polar Form
The representation of z by its real and imaginary
parts is useful for addition and subtraction.
For multiplication and division, representation by
the polar form has apparent geometric meaning.
Suppose we have 2 complex numbers, z1 and z2 given by :
z 1 x 1 iy 1 r1e
i1
z 2 x 2 iy 2 r2e
x
i2
i y
z 1 z 2 x 1 iy 1 x 2 iy 2
1
x2
z 1z 2 r1e
i1
r1r2e
magnitudes multiply!
1
y2
r e
i2
2
i (1 ( 2 ))
phases add!
Easier with normal
form than polar form
Easier with polar form
than normal form
For a complex number z2 ≠ 0,
z1
z2
r1e
r2e
i1
i2
magnitudes divide!
z1
r1
z2
r2
r1
r2
e
i (1 ( 2 ))
r1
r2
e
i (1 2 )
phases subtract!
z 1 ( 2 ) 1 2
Example 1
Describe the range of the function f(z) = x2 + 2i, defined on (the domain is) the
unit disk |z| 1.
Solution: We have u(x,y) = x2 and v(x,y) = 2. Thus as z varies over the closed
unit disk, u varies between 0 and 1, and v is constant (=2).
Therefore w = f(z) = u(x,y) + iv(x,y) = x2 +2i is a line segment from w = 2i to w
= 1 + 2i.
y
domain
f(z)
x
v
range
u
Example 2
Describe the function f(z) = z3 for z in the semidisk given by |z| 2, Im z
0.
Solution: We know that the points in the sector of the semidisk from
Arg z = 0 to Arg z = 2/3, when cubed cover the entire disk |w| 8
because
3
2i
2e
8e
The cubes of the remaining points of z also fall into this disk,
overlapping it in the upper half-plane as depicted on the next screen.
i 2
3
w = z3
y
v
8
2
-2
2
x
-8
8
-8
u
If Z is in x+iy form
z3=z2..z=(x2-y2+i2xy)(x+iy)=(x3-xy2+i2x2y+ix2y-iy3 -2xy2)
=(x3-3xy2) +i(3x2y-y3)
If u(x,y)= (x3-3xy2) and v(x,y)=(3x2y-y3), we can write
z3=f(z)=u(x,y) +iv(x,y)
Example 3
f(z)=z2, g(z)=|z| and
h(z)= z
i)
D={(x,x)|x is a real number}
ii)
D={|z|<4| z is a complex number}
Draw the mappings
Sequence
Definition. A sequence of complex numbers,
denoted
k
zn1, is a function f, such that f: N C, i.e, it is a
function whose domain is the set of natural numbers
between 1 and k, and whose range is a subset of
the complex numbers. If k = , then the sequence is
called infinite and is denoted by zn, or more
1
often, zn . (The notation f(n) is equivalent.)
Having defined sequences and a means for
measuring the distance between points, we proceed
to define the limit of a sequence.
Meaning of Zn
Zn
Z0
|zn-z0|=rn
Where rn=
, xn
x0,,, yn
Z0
0
(x n x 0 )2 (y n y 0 )2
y0
I proved it in previous classes
Geometric Meaning of Zn
Z0
zn tends to z0 in any linear or curvilinear way.
Limit of a Sequence
Definition. A sequence of complex numberszn is
1
said to have the limit z0 , or to converge to z0 , if for
any > 0, there exists an integer N such that |zn –
z0| < for all n > N. We denote this by
lim zn z0 or
n
zn z0 as n .
Geometrically, this amounts to the fact that z0 is the
only point of zn such that any neighborhood about it,
no matter how small, contains an infinite number of
points zn .
Theorems and Exercises
Theorem. Show that zn=xn+iyn
only if xn x0, yn y0 .
z0=x0+iy0 if and
Ex. Plot the first ten elements of the following sequences
and find their limits if they exist:
i)
1/n +i 1/n
ii)
1/n2 +i 1/n2
iii)
n +i 1/n
iv)
(1-1/n )n +i (1+1/n)n
Limit of a Function
We say that the complex number w0 is the limit of
the function f(z) as z approaches z0 if f(z) stays
close to w0 whenever z is sufficiently near z0 .
Formally, we state:
Definition. Limit of a Complex Sequence. Let f(z) be
a function defined in some neighborhood of z0
except with the possible exception of the point z0 is
the number w0 if for any real number > 0 there
exists a positive real number > 0 such that |f(z) –
w0|< whenever 0<|z - z0|< .
Limits: Interpretation
We can interpret this to mean that if we observe points z within a radius of z0,
we can find a corresponding disk about w0 such that all the points in the disk
about z0 are mapped into it. That is, any neighborhood of w0 contains all the
values assumed by f in some full neighborhood of z0, except possibly f(z0).
v
y
w = f(z)
z
0
z-plane
w0
x
w-plane
u
Complex Functions : Limit and
Continuity
f: Ω1
Ω2
Ω1 and Ω2 are domain and codomain respectively.
Let z0 be a limit point of Ω1 , w0 belongs to Ω2 .
Let us take any B any nbd of w0 in Ω2 and take inverse of B, f-1{B}.
f-1{B} contains a nbd of z0 in Ω1..
In the case of Continuity the only difference is w0
=f(z0)),
Properties of Limits
as z z0, lim f(z) A, then A is unique
If as z z0, lim f(z) A and lim g(z) B,
If
then
lim [ f(z) g(z) ] = A B
lim f(z)g(z) = AB, and
lim f(z)/g(z) = A/B. if B 0.
Continuity
Definition. Let f(z) be a function such that f: C
C. We call f(z) continuous at z0 iff:
F is defined in a neighborhood of z0,
The limit exists, and
zz0
lim f ( z) f ( z0 )
A function f is said to be continuous on a set
S if it is continuous at each point of S. If a
function is not continuous at a point, then it is
said to be singular at the point.
Note on Continuity
One can show that f(z) approaches a limit
precisely when its real and imaginary parts
approach limits, and the continuity of f(z) is
equivalent to the continuity of its real and
imaginary parts.
Properties of Continuous
Functions
If f(z) and g(z) are continuous at z0, then so
are f(z) g(z) and f(z)g(z). The quotient
f(z)/g(z) is also continuous at z0 provided that
g(z0) 0.
Also, continuous functions map compact sets
into compact sets.
Exercises
i.
ii.
iii.
iv.
v.
vi.
Find domain and range of the following
functions and check their continuity:
f1(z)=z
f2(z)=|z|
f3(z)=z2
f4(z)=
f5(z)=1/(z-2)
f6(z)=ez/log(z)/z1./2/cos(z)
z
f: <S1,d1>
s in S1.
For all sn
<S2,d2> is continuous at
s
f(s )
n
f(s)
it is true in a general metric space but not
in general topological space.
Test for Continuity of Functions