Transcript File

Formulas
HOW TO WRITE
THEM
1st – Definition
A symbolic representation of a
compound or molecule
Why do they Combine?
Atoms Strive to meet two conditions
1. To be neutral
- By having the same # of electrons and Protons
2. Have the same # of electrons as a Noble gas
- Being nonreactive is the most stable
Can they have both at the same time?
NO
Having the same number of electrons as a
Noble gas is more desired
They must gain or lose electrons
- What would happen to their charge if
they gained an electron?
Negative
- What would happen to their charge if
they lost an electron?
Positive
SOME DEFINITIONS
- Ion – an atom that has a charge
- Oxidation number – The charge an atom has is
called it’s oxidation number.
- Valence electrons – The number of electrons
on the outside edge of an atom’s outer
orbit
- Maximum of eight
How can there be only eight when some of
the orbits can hold more than eight?
Well . . .
Think of an orbit as having a thickness where:
The 1st orbit is only thin enough to hold 2 electrons
The 2nd orbit can only hold one thickness of 8 electrons
But the 3rd and the 4th orbits are so thick that the electrons are spread
out between the inside edge and the out side edge.
1st
2 electrons
2nd
8 electrons
3rd
18 electrons
4th
32 electrons
Only eight can be
on this outside
edge and the rest
are inside
somewhere
Using the periodic table to know what charge an atom takes
- Remember that the atoms want the same number of
electrons as a Noble gas
Examples
Cl
17
Protons
17
Electrons
Noble Gas
18
Difference
-1
O
N
Na
Mg
F
Br
8
8
10
7
7
10
11
11
10
12
12
10
9
9
10
35
35
36
-2
-3
+1
+2
-1
-1
Subtract the noble gas electrons from the element electrons and that is the charge
Bellringer 11/19
*Keep this one in your notes. We will NOT be taking it for a grade!
1. DEFINE AN OXIDATION NUMBER.
1. DEFINE A SUBSCRIPT.
1. WHAT IS THE OXIDATION NUMBER
FOR CHLORINE?
+1
+2
+3 4 -3 -2 -1
1. SYMBOL: Write the symbol for each element
2. OXIDATION: Add their oxidation numbers
3. PLUS: Put a plus sign between the ions and
add an arrow pointing to the right
4. FORMULA: Write the Formula so that the
total net charge equals zero
5. BALANCE: Determine how many
atoms of each to do this
Sally
Offered
Peter
Four
Bananas
Symbol
Oxidation
Plus
Formula
Balance
For Example:
-Combining Sodium and Chlorine
1. First write their symbols
1.
Na
2.
+1
3.
+
1.
Cl
2.
-1
3.
4.
NaCl
(+1) + (-1)= 0
2. Then add the oxidation numbers
3. Put a plus sign and draw an arrow pointing to the right
4. Write the formula (Positive is always 1st)
The charges add up to be zero (balanced)
Another Example:
Magnesium and Fluorine
+2
Mg + F
- Subscript – The small
number below and to the
right of the symbol that
denotes the number of
atoms in a formula.
Remember the positive
one first!
-1
MgF
2
One Mg ion
(+2) +
Two F Ions
(-1) + (-1) = 0
One Mg plus two F charges
will add up to be zero.
Practice Problems:
1. Potassium and Sulfur
K+1 + S-2  K2S
2. Strontium and Bromine
Sr+2 + Br-1  SrBr2
3. Lithium and Oxygen
Li+1 + O-2  Li2O
4. Calcium and Iodine
Ca+2 + I-1  CaI2
5. Aluminum and Chlorine Al+3 + Cl-1  AlCl3
6. Gallium and Oxygen
Ga+3 + O-2  Ga2O3
7. Aluminum and Oxygen Al+3 + O-2  Al2O3
8. Boron and Sulfur
B+3 + S-2  B2S3
One more rule for the Transition Metals
-Transition metals are called that because their ion charge can be
one charge in one reaction and a different one in another
-Since they are in a state of transition, it is unknown what charge they
are for writing formulas
- For this reason, a roman Numeral is assigned to represent the charge
For example:
Iron (III) would be written like this :
Fe+3
and
Cobalt (IV) would be written like this: Co+4
Here are the Roman numerals up to Fifteen:
1- I
6- VI
11. XI
2- II
7- VII
12. XII
3- III
8- VIII
13. XIII
4- IV
9- IX
14. XIV
5- V
10- X
15. XV
-Roman Numerals tell you two things:
-It is a Transition metal
- It is a Positive Charge that matches the roman numeral
Practice Problems:
1. Iron (I) and Sulfur
Fe+1 + S-2  Fe2S
2. Lead (IV) and Bromine
Pb+4 + Br-1  PbBr4
3. Cobalt (II) and Oxygen Co+2 + O-2  CoO
4. Copper (II) and Iodine Cu+2 + I-1  CuI2
Fe+3 + Cl-1  FeCl3
5. Iron (III) and Chlorine
6. Mercury (I) and Oxygen
Hg+1 + O-2  Hg2O
7. Copper (III) and Oxygen
Cu+3 + O-2  Cu2O3
8. Silver (II) and Sulfur
Ag+2 + S-2  AgS
More Problems: Write the symbols with the charges, arrow,
and final formula.
O and H
Li and Cl
Na and Po
K and Br
Mg and I
Ca and O
Al and S
Ca and F
Fr and Te
Ba and N
Na and P
Be and At