Transcript Order_of_Operations_Exponents_Variables_Exp

Exam
Review
Nick Marshall &
Andy Garcia-Civita
Order of Operations
Does anybody in the audience know what order
of operations is?
How do you know the order to do the problem?
PEMDAS
PEMDAS=
1) Parentheses
2) Exponents
3) Multiplication
4) Division
5) Addition
6)Subtraction
PEDMSA
PEDMSA=
1)
2)
3)
4)
5)
6)
Parentheses
Exponents
Division
Multiplication
Subtraction
Addition
PEDMSA also works because it
is whatever comes first in the
problem. Division could come
before multiplication and
subtraction could come
before addition. It just
depends on how the problem
is written.
We'll Walk You Through This One!
(8x3)-(6+6)x4+20
You solve the parentheses first.
(24-12)x4+20
You solve the parentheses first again.
12x4+20
Then you do multiplication.
48+20=
Finally you do addition to get the
answer!
68
Now You Are On Your Own. Solve This.
15•2÷(1+5)•13-17
Answer
48
Exponents
Now we will switch to exponents. Exponents are little
numbers that go on the top of the number. There is a base,
and that is the big number. Then there is the exponent and
that is the little number that goes on the top.
What They Mean
Ex. 24
The base is the 2 and the exponent is 4. It means two to the fourth power. You do 2x2x2x2.
You get 16. In other words, you multiply the base however many times the exponent says.
It's time for you to solve it!
Solve:
1) 43
2) 54
The Answers
1.
2.
64
625
Algebraic Expressions
Expressions contain numbers, variables and at least one
operation. This problem is pretty self-explanatory. You just
change the letters to the numbers that we give you, and then
you are ready to solve the problem.
Example
X = 4, Y = 3, Z = 4.8
X•Y+Z
Just change those letters to the right numbers:
4•3+4.8
Now you can get the answer.
Solve
Solve this problem if a=2.6, b=6, and c=3.4.
a+b-c=?
Answer
5.2
Variables
A variable is a letter that takes a place of
a number. Variables could make the
problem harder because you don't know
one number. It is very important that you
know variables. For example, in an
algebraic expression you have to know
what the letters stand for, or else you
can't do the problem.
Example
R = 56, O = 75, P = 22
R+P÷O
What would the problem look like?
56+22÷75
Solve
J = 745, E = 32, Q = 56.3
Q•J÷E
What will the problem look like?
Answer
56.3•745÷32
Thank You!
Thank you for doing our review
with us and good luck to you all on
the exams!