Transcript CS 101
CS 101
Lecture 4
Repetition
1
pre and post increment and decrement
• If i=i+1; we may write i++ to mean the same thing, and
is called the postincrement operator. ++i also means
i=i+1 and is called the preincrement operator. --i and i-are called the preincrement and postincrement operators
and each means i=i-1.
• The difference shows up in expressions and commands.
If i = 4 then
cout<<++x<<‘ ‘<<x;will print out 5 5 but
cout<<x++<<‘ ‘<<x; will print out 4 5.
• Similarly, if x=5 and y=3 then
cout<<x<<‘ ‘<<y<‘ ‘<<++x*y--<<‘ ‘<<x<<‘ ‘<<y will
print
5 3 18 6 2 to the screen
2
Shortcut assignment and arithmetic
operators
We can write x+=3; to mean x=x+3, similarly we can
write x*=4; x/=5; x-=2; x%=3;
if x,y are integer variables, x/y is truncated, i.e., 7/3 is 2.
If at least the numerator or denominator of x/y is a
double or a float, then the result is an untruncated
double or float. 7.0/3 is 2.333 We can also write
double(7)/3 or 7/double(3) to get the same result, but not
double(7/3), since this gives 2.0. If x,y are integer
variables, x%y gives the remainder when x is divided by
y. 7%3 is 1. 13%5 is 3. -13%5 is –3. In math, -13%5 is
2.
3
The while loop
• If i is an integer variable containing 0, then the
statement
while(i<5) {cout<<i*i<<‘ ‘;i++;}
will print 0 1 4 9 to the screen. The pair of
statements cout<<i*i<<‘ ‘; i++; gets repeated 5
times, each time with a different value of i. The
five values of i are 0,1,2,3,4. Before the pair of
statements is executed, the test i<5 is
performed. If it is true, then both statements
are executed. If not(as when 5<5 is false), then
the next statement after the while loop is
executed.
4
while loop program
• While loops are usually used when it is not known in
advance how many times the loop will be executed. The
following program
#include<iostream.h>
main( ){
double sum=0;
int i=1;
while(1.0/(2*i*i+2*i+1)>.0001){sum=sum+1.0/(2*i*i+2*i
+1);i++}
cout<<sum<<endl;}
will execute 70 times and print .433617 to the screen. We
have avoided solving the equation 2i2 + 2i +1 = 10000 to
find out in advance how many times we must loop.
5
for loops
There are three parts to the for loop statement.
for(int i=1;i<5;i++)cout<<i<<‘ ‘;
int i=1; is called the initialization command, and is done first and
only once. If there are several commands before the first ; then
they must be separated by commas. i<5 is called the test
expression. If it is true then the body of the for loop, in this case,
the statement cout<<i<<‘ ‘; is performed. If the body is performed
then the final statement(s) is(are) carried out after the body. Then
the test expression is evaluated again.
The above for statement will print 1 2 3 4 to the screen. The above
for statement is equivalent to
for(int i=1;i<5;cout<<i<<‘ ‘,i++){} and also to
for(int i=1;i<5;){cout<<i<<‘ ‘;i++;} and also to
for(int i=1; ;){if(i<5)cout<<i<<‘ ‘;else break;}
6
break and continue
If a break statement occurs in the body of a
loop, the loop is exited. If a continue statement
occurs in the body of a loop, the next iteration
is performed. If the loop is a for loop then after
the continue, the update portion of the for loop
is executed.
7
Quiz 2 and solution
Write a program which will ask the user to input 50
numbers(doubles), and print the average to a file called
average.txt
#include<fstream.h>
main(){
cout<<“Please enter 50 numbers.\n”;
double x, sum=0;
for(int i=0;i<50;i++)
{cin>>x;
sum=sum+x;}
ofstream fout(“average.txt”);
fout<<sum/50;
fout.close();
8
loops with a conditional
Suppose we want to read 50 integers from the file
input.txt and write the even integers to the file
oute.txt and the odd integers to the file outo.txt.
#include<fstream.h>
main(){
ifstream fin(“input.txt”);
ofstream foute(“oute.txt”),fouto(“outo.txt”);
int x;
for(int i=0;i<50;i++)
{fin>>x;if(x%2==1)fouto<<x<<‘ ‘;else foute<<x<<‘
‘;}
fin.close();fouto.close();foute.close();}
9
Quiz 3 and solution
Write a program which will ask the user to input 50
numbers(doubles), and print the numbers to three different files.
If the number is divisible by 3, the number is printed to the file
three0.txt; if dividing the number by 3 yields a remainder of 1, the
number is printed to the file three1.txt; if dividing the number by
3 yields a remainder of 2, the number is printed to the file
three2.txt
#include<fstream.h>
main(){int x;
ofstream out0(“three0.txt”),fout1(“three1.txt”),fout2(“three2.txt”);
cout<<“Please enter 50 integrs.\n”;
for(int i=0;i<50;i++){cin>>x; if(x%3==0)fout0<<x<<‘ ‘;
else if(x%3==1)fout1<<x<<‘ ‘; else fout2<<x<<‘ ‘;}
fout1.close(); fout1.close(); fout2.close();}
10