LAWS OF EXPONENTS
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Transcript LAWS OF EXPONENTS
CHAPTER 5
INDICES AND
LOGARITHMS
What is Indices?
Examples of numbers in index
form.
33
(3 cubed or 3 to the power of 3)
25
(2 to the power of 5)
3
and 5 are known as indices.
27=33, 3 is a base and 3 is an index
32=25, 2 is a base and 5 is an index
So , why we use indices?
Indices can make large numbers
much more manageable, as a
large number can be reduced to
just a base and an index.
Eg: 1,048,576
= 220
LAWS OF INDICES
Multiplication of indices with same base:
am an = am + n
bm + n = bm bn
Example:
x4 x3 = x 4 + 3 = x 7
1
4
7
4+(-7)
3
y y =y
= y = y3
2x+3 = 2x 23 = 8(2x)
1
y
y
–
2
y
2
3 = 3 3 = 3 32
Division of indices with same base:
am ÷ an = am n
bm n = bm ÷ bn
Example:
9
c
9 4 = c5
=
c
4
c
x
3
x-2
3 = 2
3
25
4p 2
p
1
3
1
p
3
5
3
3
3p
12p
Raising an index to a power
(am)n = amn
bmn = (bm)n
EXAMPLE:
(b4)3 = b43 = b12
(32)3 = 323 = 36
(2x)2 = 22x
(2y+1)3 = 23y + 3
32c = (3c)2
n
(ab)
=
n
n
a b
EXAMPLE:
(xy)3 = x3 y3
23 33 = 63
(ab)-2 = a-2 b-2
Law 5:
a
b
n
n
a
n
b
a a b
b a
b
5 2 2 4
2 5 5 25
EXAMPLE:
2
3
2
2
2
2
2
3
2
2
2
2
2
2
2
Other properties of index
Zero index: a0 = 1, a 0
1
n
a
a-n
Negative index:
Fractional index:
1
n
a a
m
n
n
a a
2
3
64
n
m
a
64
3
n
2
4
m
2
Law 5:
a
b
n
n
a
n
b
a a b
b a
b
5 2 2 4
2 5 5 25
EXAMPLE:
2
3
2
2
2
2
2
3
2
2
2
2
2
2
2
Example
Solve
(a) 91 – x = 27
1
p
+
1
3
–
p
(b) 2
4
= 16
(c) Solve the simultaneous equation
2x.42y = 8
1
x
-y
5 .25 =
125
x+3
x+2
(d) 4 – 4 = 6
Solution
(a)
(b)
(c)
(d)
x = -0.5
p = 11
x = -1, y = 1
x = -1.5