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Introduction to Management Science
9th Edition
by Bernard W. Taylor III
Chapter 14
Simulation
© 2007 Pearson Education
Chapter 14 - Simulation
1
Chapter Topics
The Monte Carlo Process
Computer Simulation with Excel Spreadsheets
Simulation of a Queuing System
Continuous Probability Distributions
Statistical Analysis of Simulation Results
Verification of the Simulation Model
Areas of Simulation Application
Chapter 14 - Simulation
2
Overview
Analogue simulation replaces a physical system with an
analogous physical system that is easier to manipulate.
In computer mathematical simulation a system is replaced
with a mathematical model that is analyzed with the
computer.
Simulation offers a means of analyzing very complex
systems that cannot be analyzed using the other
management science techniques in the text.
Chapter 14 - Simulation
3
Monte Carlo Process
A large proportion of the applications of simulations are for
probabilistic models.
The Monte Carlo technique is defined as a technique for
selecting numbers randomly from a probability distribution
for use in a trial (computer run) of a simulation model.
The basic principle behind the process is the same as in
the operation of gambling devices in casinos (such as those
in Monte Carlo, Monaco).
Gambling devices produce numbered results from welldefined populations.
Chapter 14 - Simulation
4
Monte Carlo Process
Use of Random Numbers (1 of 10)

In the Monte Carlo process, values for a random variable are
generated by sampling from a probability distribution.

Example: ComputerWorld demand data for laptops selling for
$4,300 over a period of 100 weeks.
Table 14.1 Probability Distribution of Demand for Laptop PC’s
Chapter 14 - Simulation
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Monte Carlo Process
Use of Random Numbers (2 of 10)

The purpose of the Monte Carlo process is to generate the
random variable, demand, by sampling from the probability
distribution P(x).

The partitioned roulette wheel replicates the probability
distribution for demand if the values of demand occur in a
random manner.

The segment at which the wheel stops indicates demand
for one week.
Chapter 14 - Simulation
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Monte Carlo Process
Use of Random Numbers (3 of 10)
Figure 14.1 A Roulette Wheel for Demand
Chapter 14 - Simulation
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Monte Carlo Process
Use of Random Numbers (4 of 10)

When wheel is spun actual demand for PC’s is determined by a
number at rim of the wheel.
Figure 14.2
Numbered Roulette Wheel
Chapter 14 - Simulation
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Monte Carlo Process
Use of Random Numbers (5 of 10)

Process of spinning a wheel can be replicated using random
numbers alone.

Transfer random numbers for each demand value from roulette
wheel to a table.
Table 14.2 Generating Demand from Random Numbers
Chapter 14 - Simulation
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Monte Carlo Process
Use of Random Numbers (6 of 10)

Select number from a random number table:
Table 14.3 Random Number Table
Chapter 14 - Simulation
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Monte Carlo Process
Use of Random Numbers (7 of 10)

Repeating selection of random numbers simulates demand
for a period of time.

Estimated average demand = 31/15 = 2.07 laptop PCs per
week.

Estimated average revenue = $133,300/15 = $8,886.67.
Chapter 14 - Simulation
11
Monte Carlo Process
Use of Random Numbers (8 of 10)
Chapter 14 - Simulation
12
Monte Carlo Process
Use of Random Numbers (9 of 10)

Average demand could have been calculated analytically:
n
E( x)   P( xi) xi
i1
where:
xi  demand value i
P( xi)  probability of demand
n  the number of different demand values
therefore:
E( x)  (.20)(0)  (.40)(1)  (.20)(2)  (.10)(3)  (.10)(4)
 1.5 PC's per week
Chapter 14 - Simulation
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Monte Carlo Process
Use of Random Numbers (10 of 10)

The more periods simulated, the more accurate the results.

Simulation results will not equal analytical results unless
enough trials have been conducted to reach steady state.

Often difficult to validate results of simulation - that true
steady state has been reached and that simulation model
truly replicates reality.

When analytical analysis is not possible, there is no
analytical standard of comparison thus making validation
even more difficult.
Chapter 14 - Simulation
14
Computer Simulation with Excel Spreadsheets
Generating Random Numbers (1 of 2)

As simulation models get more complex they become
impossible to perform manually.

In simulation modeling, random numbers are generated by
a mathematical process instead of a physical process (such
as wheel spinning).

Random numbers are typically generated on the computer
using a numerical technique and thus are not true random
numbers but pseudorandom numbers.
Chapter 14 - Simulation
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Computer Simulation with Excel Spreadsheets
Generating Random Numbers (2 of 2)
Artificially created random numbers must have the following
characteristics:
The random numbers must be uniformly distributed.
The numerical technique for generating the numbers
must be efficient.
The sequence of random numbers should reflect no
pattern.
Chapter 14 - Simulation
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Simulation with Excel Spreadsheets (1 of 3)
Exhibit 14.1
Chapter 14 - Simulation
17
Simulation with Excel Spreadsheets (2 of 3)
Exhibit 14.2
Chapter 14 - Simulation
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Simulation with Excel Spreadsheets (3 of 3)
Exhibit 14.3
Chapter 14 - Simulation
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Computer Simulation with Excel Spreadsheets
Decision Making with Simulation (1 of 2)

Revised ComputerWorld example; order size of one laptop each week.
Exhibit 14.4
Chapter 14 - Simulation
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Computer Simulation with Excel Spreadsheets
Decision Making with Simulation (2 of 2)

Order size of two laptops each week.
Exhibit 14.5
Chapter 14 - Simulation
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Simulation of a Queuing System
Burlingham Mills Example (1 of 3)
Table 14.5 Distribution of Arrival Intervals
Table 14.6 Distribution of Service Times
Chapter 14 - Simulation
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Simulation of a Queuing System
Burlingham Mills Example (2 of 3)
Average waiting time = 12.5days/10 batches
= 1.25 days per batch
Average time in the system = 24.5 days/10 batches
= 2.45 days per batch
Chapter 14 - Simulation
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Simulation of a Queuing System
Burlingham Mills Example (3 of 3)
Caveats:
Results may be viewed with skepticism.
Ten trials do not ensure steady-state results.
Starting conditions can affect simulation results.
If no batches are in the system at start, simulation
must run until it replicates normal operating system.
If system starts with items already in the system,
simulation must begin with items in the system.
Chapter 14 - Simulation
24
Computer Simulation with Excel
Burlingham Mills Example
Exhibit 14.6
Chapter 14 - Simulation
25
Continuous Probability Distributions
A continuous function must be used for continuous distributions.
Example :
f(x)  x , 0  x  4 where x  time (minutes)
8
Cumulative probability of x :
x
xx
x


F(x)   dx  1  x dx  1 1 x 2 
80
8  2 0
08
2
x
F(x) 
16
Let F(x)  the random number r
r  x2
16
x4 r
By generating a random number,r, a value x for " time" is determined .
Example : if r  .25, x  4 .25  2 minutes
Chapter 14 - Simulation
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Machine Breakdown and Maintenance System
Simulation (1 of 6)

Bigelow Manufacturing Company must decide if it should
implement a machine maintenance program at a cost of
$20,000 per year that would reduce the frequency of
breakdowns and thus time for repair which is $2,000 per
day in lost production.

A continuous probability distribution of the time between
machine breakdowns:
f(x) = x/8, 0  x  4 weeks, where x = weeks between
machine breakdowns
x = 4*sqrt(ri), value of x for a given value of ri.
Chapter 14 - Simulation
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Machine Breakdown and Maintenance System
Simulation (2 of 6)
Table 14.8
Probability Distribution of Machine Repair Time
Chapter 14 - Simulation
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Machine Breakdown and Maintenance System
Simulation (3 of 6)

Revised probability of time between machine breakdowns:
f(x) = x/18, 0  x6 weeks where x = weeks between
machine breakdowns
x = 6*sqrt(ri)
Table 14.9 Revised Probability Distribution of Machine Repair Time with the Maintenance Program
Chapter 14 - Simulation
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Machine Breakdown and Maintenance System
Simulation (4 of 6)

Simulation of system without maintenance program (total annual
repair cost of $84,000):
Table 14.10 Simulation of Machine Breakdowns and Repair Times
Chapter 14 - Simulation
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Machine Breakdown and Maintenance System
Simulation (5 of 6)

Simulation of system with maintenance program (total annual
repair cost of $42,000):
Table 14.11 Simulation of Machine Breakdowns and Repair with the Maintenance Program
Chapter 14 - Simulation
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Machine Breakdown and Maintenance System
Simulation (6 of 6)
Results and caveats:
Implement maintenance program since cost savings
appear to be $42,000 per year and maintenance program
will cost $20,000 per year.
However, there are potential problems caused by
simulating both systems only once.
Simulation results could exhibit significant variation since
time between breakdowns and repair times are
probabilistic.
To be sure of accuracy of results, simulations of each
system must be run many times and average results
computed.
Efficient computer simulation required to do this.
Chapter 14 - Simulation
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Machine Breakdown and Maintenance System
Simulation with Excel (1 of 2)

Original machine breakdown example:
Exhibit 14.7
Chapter 14 - Simulation
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Machine Breakdown and Maintenance System
Simulation with Excel (2 of 2)

Simulation with maintenance program.
Exhibit 14.8
Chapter 14 - Simulation
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Statistical Analysis of Simulation Results (1 of 2)

Outcomes of simulation modeling are statistical measures
such as averages.

Statistical results are typically subjected to additional
statistical analysis to determine their degree of accuracy.

Confidence limits are developed for the analysis of the
statistical validity of simulation results.
Chapter 14 - Simulation
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Statistical Analysis of Simulation Results (2 of 2)

Formulas for 95% confidence limits:
upper confidence limit  x  (1.96)(s / n )
lower confidence limit  x  (1.96)(s / n )
where x is the mean and s the standard deviation
from a sample of size n from any population.

We can be 95% confident that the true population mean will
be between the upper confidence limit and lower
confidence limit.
Chapter 14 - Simulation
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Simulation Results
Statistical Analysis with Excel (1 of 3)

Simulation with maintenance program.
Exhibit 14.9
Chapter 14 - Simulation
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Simulation Results
Statistical Analysis with Excel (2 of 3)
Exhibit 14.10
Chapter 14 - Simulation
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Simulation Results
Statistical Analysis with Excel (3 of 3)
Exhibit 14.11
Chapter 14 - Simulation
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Verification of the Simulation Model (1 of 2)
Analyst wants to be certain that model is internally correct
and that all operations are logical and mathematically
correct.
Testing procedures for validity:
Run a small number of trials of the model and compare
with manually derived solutions.
Divide the model into parts and run parts separately to
reduce complexity of checking.
Simplify mathematical relationships (if possible) for
easier testing.
Compare results with actual real-world data.
Chapter 14 - Simulation
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Verification of the Simulation Model (2 of 2)
Analyst must determine if model starting conditions are
correct (system empty, etc).
Must determine how long model should run to insure
steady-state conditions.
A standard, fool-proof procedure for validation is not
available.
Validity of the model rests ultimately on the expertise and
experience of the model developer.
Chapter 14 - Simulation
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Some Areas of Simulation Application
Queuing
• Inventory Control
• Production and Manufacturing
• Finance
• Marketing
• Public Service Operations
• Environmental and Resource Analysis
Chapter 14 - Simulation
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Example Problem Solution (1 of 6)
Data
Willow Creek Emergency Rescue Squad
Minor emergency requires two-person crew, regular, a
three-person crew, and major emergency, a fiveperson crew.
Chapter 14 - Simulation
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Example Problem Solution (2 of 6)
Distribution of number of calls per night and emergency type:
Calls
0
1
2
3
4
5
6
Probability
.05
.12
.15
.25
.22
.15
.06
1.00
Emergency Type Probability
Minor
.30
Regular
.56
Major
.14
1.00
Required: Manually simulate 10 nights of calls; determine
average number of calls each night and maximum number of
crew members that might be needed on any given night.
Chapter 14 - Simulation
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Example Problem Solution (3 of 6)
Solution Step 1: Develop random number ranges for the
probability distributions.
Calls
Probability
0
1
2
3
4
5
6
.05
.12
.15
.25
.22
.15
.06
1.00
Emergency
Type
Minor
Regular
Major
Cumulative
Probability
.05
.17
.32
.57
.79
.94
1.00
Probability
.30
.56
.14
1.00
Random Number
Range, r1
1–5
6 – 17
18 – 32
33 – 57
58 – 79
80 – 94
95 – 99, 00
Cumulative
Probability
.30
.86
1.00
Chapter 14 - Simulation
Random Number
Range, r1
1 – 30
31 – 86
87 – 99, 00
45
Example Problem Solution (4 of 6)
Step 2: Set Up a Tabular Simulation (use second column of
random numbers in Table 14.3).
Chapter 14 - Simulation
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Example Problem Solution (5 of 6)
Step 2 continued:
Chapter 14 - Simulation
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Example Problem Solution (6 of 6)
Step 3: Compute Results:
average number of minor emergency calls per night =
10/10 =1.0
average number of regular emergency calls per night =
14/10 = 1.4
average number of major emergency calls per night =
3/10 = 0.30
If calls of all types occurred on same night, maximum
number of squad members required would be 14.
Chapter 14 - Simulation
48
End of chapter
The rest of the transparencies are given as a brief
overview of Crystall Ball software; which not included
in the exam.
Chapter 14 - Simulation
49
Crystal Ball
Overview

Many realistic simulation problems contain more complex
probability distributions than those used in the examples.

However there are several simulation add-ins for Excel that
provide a capability to perform simulation analysis with a
variety of probability distributions in a spreadsheet format.

Crystal Ball, published by Decisioneering, is one of these.

Crystal Ball is a risk analysis and forecasting program that
uses Monte Carlo simulation to provide a statistical range of
results.
Chapter 14 - Simulation
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Crystal Ball
Simulation of Profit Analysis Model (1 of 17)

Recap of Western Clothing Company break-even and profit
analysis:
Price (p) for jeans is $23; variable cost (cv) is $8; fixed
cost (cf ) is $10,000.
Profit Z = vp - cf - vc; break-even volume v = cf/(p - cv)
= 10,000/(23-8) = 666.7 pairs.
Chapter 14 - Simulation
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Crystal Ball
Simulation of Profit Analysis Model (2 of 17)

Modifications to demonstrate Crystal Ball:
Assume volume is now volume demanded and is
defined by a normal probability distribution with mean
of 1,050 and standard deviation of 410 pairs of jeans.
Price is uncertain and defined by a uniform probability
distribution from $20 to $26.
Variable cost is not constant but defined by a triangular
probability distribution.
Will determine average profit and profitability with given
probabilistic variables.
Chapter 14 - Simulation
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Crystal Ball
Simulation of Profit Analysis Model (3 of 17)
Exhibit 14.12
Chapter 14 - Simulation
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Crystal Ball
Simulation of Profit Analysis Model (4 of 17)
Exhibit 14.13
Chapter 14 - Simulation
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Crystal Ball
Simulation of Profit Analysis Model (5 of 17)
Exhibit 14.14
Chapter 14 - Simulation
55
Crystal Ball
Simulation of Profit Analysis Model (6 of 17)
Exhibit 14.15
Chapter 14 - Simulation
56
Crystal Ball
Simulation of Profit Analysis Model (7 of 17)
Exhibit 14.16
Chapter 14 - Simulation
57
Crystal Ball
Simulation of Profit Analysis Model (8 of 17)
Exhibit 14.17
Chapter 14 - Simulation
58
Crystal Ball
Simulation of Profit Analysis Model (9 of 17)
Exhibit 14.18
Chapter 14 - Simulation
59
Crystal Ball
Simulation of Profit Analysis Model (10 of 17)
Exhibit 14.19
Chapter 14 - Simulation
60
Crystal Ball
Simulation of Profit Analysis Model (11 of 17)
Exhibit 14.20
Chapter 14 - Simulation
61
Crystal Ball
Simulation of Profit Analysis Model (12 of 17)
Exhibit 14.21
Chapter 14 - Simulation
62
Crystal Ball
Simulation of Profit Analysis Model (13 of 17)
Exhibit 14.22
Chapter 14 - Simulation
63
Crystal Ball
Simulation of Profit Analysis Model (14 of 17)
Exhibit 14.23
Chapter 14 - Simulation
64
Crystal Ball
Simulation of Profit Analysis Model (15 of 17)
Exhibit 14.24
Chapter 14 - Simulation
65
Crystal Ball
Simulation of Profit Analysis Model (16 of 17)
Exhibit 14.25
Chapter 14 - Simulation
66
Crystal Ball
Simulation of Profit Analysis Model (17 of 17)
Exhibit 14.26
Chapter 14 - Simulation
67