Using Excel array formulas to take a matrix
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Transcript Using Excel array formulas to take a matrix
Use’s Excel Array Formulas to
Solve Simultaneous Equations
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Simultaneous Linear Equation
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Present Example
The example we will consider here is
from resistor circuits and goes by the
name Kirchhoff’s circuit laws.
The variables are currents in different
“loops” of the circuit.
The coefficients (numbers multiplying the
variables) are resistances.
The constants are voltages.
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Example with numbers
5
0
0
= 3.2 JA
= -1.0 JA
= -2.2 JA
– 1.0 JB
+ 5.5 JB
– 3.0 JB
- 2.2 JC
– 3.0 JC
+ 6.9 JC
In the above we have three current
variables: JA, JB and JC.
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Loop equations as matrix equation
5 = 3.2
JA – 1 JB - 2.2 JC
0 = -1 JA + 5.5
JB – 3 JC
0 = -2.2JA – 3 JB + 6.9 JC
3.2 1 2.2 J A 5
1 5.5 3 J 0
B
2.2 3 6.9 J C 0
5
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Enter matrix in Excel, highlight a region the
same size as the matrix.
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In the formula bar, enter =MINVERSE(range)
where range is the set of cells corresponding to
the matrix (e.g. B1:D3). Then hit Crtl+Shift+Enter
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Result of matrix inversion
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Prepare the “voltage vector”, then highlight a range the same size as the
vector and enter =MMULT(range1,range2) where range1 is the inverse
matrix and range2 is the voltage vector. Then Ctrl-Shift-Enter.
Voltage vector
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Results of Matrix Multiplication
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The answer
The current vector is the answer
JA=3.152 mA
JB=1.470 mA
JC=1.644 mA
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Use the matrix approach in
Excel to find the solution for
10 = 7 JA
0 = -3 JA
0 = -4 JA
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– 3 JB
+ 6 JB
– 1 JB
- 4 JC
– 1 JC
+ 10JC
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Atomic Isotope Problem
Atomic Masses
Isotopes:
The element indium exists naturally as two isotopes.
113In has a mass of 112.9043 amu, and 115In has a
mass of 114.9041 amu. The average atomic mass of
indium is 114.82 amu. Calculate the percent relative
abundance of the two isotopes of indium.
http://eppe.tripod.com/stoictry.htm
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Use the matrix approach in
Excel to find the solution for
112.9043 x + 114.9041 y = 114.82
x+y=1
where x is the fraction of the first
isotope and x is the fraction of the
second isotope.
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